(a)
To find: The mean of the number of goals scored by a team.
(a)
Answer to Problem 29E
The approximately mean is
Explanation of Solution
Given:
The given table is as:
Goals | Number of Teams |
Calculation:
The mean is calculated as:
The approximately mean is
(b)
To find: The median class of the frequency distribution.
(b)
Answer to Problem 29E
The median class of the frequency distribution is
Explanation of Solution
First make a table of cumulative frequency teams.
Goals | Number of Teams | Cumulative frequency |
Notice that
(c)
To find: The median of the number of goals scored by a team.
(c)
Answer to Problem 29E
The median is
Explanation of Solution
The median class is
The median is calculated as”
The median is
(d)
To find: The mean and median of actual data.
(d)
Answer to Problem 29E
The mean and median are given below.
Explanation of Solution
The actual data is as:
The mean and median is calculated as:
After arranging the data in ascending order we will find the median as:
The mean and median are given above.
(e)
To find: The comparison between the measure of central tendency found by using the frequency chart with the measures of central tendency found by using the actual data.
(e)
Answer to Problem 29E
The explanation is given below.
Explanation of Solution
The mean calculated using the frequency distribution is very close to the one calculated with the actual data. The median calculated with the actual data is less than the one calculated with the frequency distribution.
The explanation is given above.
Chapter 14 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Additional Math Textbook Solutions
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