Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 12.2, Problem 21LC
Interpretation Introduction

Interpretation: The use of mole ratios in chemical calculations needs to be explained.

Concept introduction: A mole ratio can be defined as the ratio between the amounts in moles of any two substances involved in a balanced chemical equation.

Expert Solution & Answer
Check Mark

Answer to Problem 21LC

Mole ratios are used in chemical calculations to convert moles of reactant or product to different moles of reactant or product.

Explanation of Solution

Consider a balanced chemical equation:

  2H2+O22H2O

In this reaction, two moles of hydrogen react with one mole of oxygen to give two moles of water.

A mole ratio conversion for the balanced chemical equation can be written as:

  1 mole of H212 mole of O2 1 mole of O22 mole of H2   1 mole of H2O1 mole of H2

So, this is how mole ratio conversion can be done in calculations.

Chapter 12 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 12.2 - Prob. 12SPCh. 12.2 - Prob. 13SPCh. 12.2 - Prob. 14SPCh. 12.2 - Prob. 15SPCh. 12.2 - Prob. 16SPCh. 12.2 - Prob. 17SPCh. 12.2 - Prob. 18SPCh. 12.2 - Prob. 19SPCh. 12.2 - Prob. 20SPCh. 12.2 - Prob. 21LCCh. 12.2 - Prob. 22LCCh. 12.2 - Prob. 23LCCh. 12.2 - Prob. 24LCCh. 12.2 - Prob. 25LCCh. 12.3 - Prob. 26SPCh. 12.3 - Prob. 27SPCh. 12.3 - Prob. 28SPCh. 12.3 - Prob. 29SPCh. 12.3 - Prob. 30SPCh. 12.3 - Prob. 31SPCh. 12.3 - Prob. 32SPCh. 12.3 - Prob. 33SPCh. 12.3 - Prob. 34LCCh. 12.3 - Prob. 35LCCh. 12.3 - Prob. 36LCCh. 12.3 - Prob. 37LCCh. 12.3 - Prob. 38LCCh. 12 - Prob. 39ACh. 12 - Prob. 40ACh. 12 - Prob. 41ACh. 12 - Prob. 42ACh. 12 - Prob. 43ACh. 12 - Prob. 44ACh. 12 - Prob. 45ACh. 12 - Prob. 46ACh. 12 - Prob. 47ACh. 12 - Prob. 48ACh. 12 - Prob. 49ACh. 12 - Prob. 50ACh. 12 - Prob. 51ACh. 12 - Prob. 52ACh. 12 - Prob. 53ACh. 12 - Prob. 54ACh. 12 - Prob. 55ACh. 12 - Prob. 56ACh. 12 - Prob. 57ACh. 12 - Prob. 58ACh. 12 - Prob. 59ACh. 12 - Prob. 60ACh. 12 - Prob. 61ACh. 12 - Prob. 62ACh. 12 - Prob. 63ACh. 12 - Prob. 64ACh. 12 - Prob. 65ACh. 12 - Prob. 66ACh. 12 - Prob. 67ACh. 12 - Prob. 68ACh. 12 - Prob. 69ACh. 12 - Prob. 70ACh. 12 - Prob. 71ACh. 12 - Prob. 72ACh. 12 - Prob. 73ACh. 12 - Prob. 74ACh. 12 - Prob. 75ACh. 12 - Prob. 76ACh. 12 - Prob. 77ACh. 12 - Prob. 78ACh. 12 - Prob. 79ACh. 12 - Prob. 80ACh. 12 - Prob. 81ACh. 12 - Prob. 82ACh. 12 - Prob. 83ACh. 12 - Prob. 84ACh. 12 - Prob. 85ACh. 12 - Prob. 88ACh. 12 - Prob. 89ACh. 12 - Prob. 90ACh. 12 - Prob. 91ACh. 12 - Prob. 92ACh. 12 - Prob. 93ACh. 12 - Prob. 94ACh. 12 - Prob. 95ACh. 12 - Prob. 96ACh. 12 - Prob. 97ACh. 12 - Prob. 98ACh. 12 - Prob. 99ACh. 12 - Prob. 100ACh. 12 - Prob. 101ACh. 12 - Prob. 102ACh. 12 - Prob. 103ACh. 12 - Prob. 104ACh. 12 - Prob. 105ACh. 12 - Prob. 106ACh. 12 - Prob. 107ACh. 12 - Prob. 1STPCh. 12 - Prob. 2STPCh. 12 - Prob. 3STPCh. 12 - Prob. 4STPCh. 12 - Prob. 5STPCh. 12 - Prob. 6STPCh. 12 - Prob. 7STPCh. 12 - Prob. 8STPCh. 12 - Prob. 9STPCh. 12 - Prob. 10STP
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