Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 12, Problem 76A

(a)

Interpretation Introduction

Interpretation: The number of frames needed to make 29 bicycles built for three is to be calculated.

Concept Introduction: Reactants, products, and an arrow indicating the reaction's direction make up a chemical equation. A balanced chemical equation is one in which the number of atoms in each of the molecules is the same on both sides of the equation.

(a)

Expert Solution
Check Mark

Answer to Problem 76A

The number of frames in 29 bicycles built for three is 29.

Explanation of Solution

A bicycle built for three has a frame, two wheels, six pedals, and three seats.

The balanced equation for this bicycle is given as

  F+2W+6P+3S FW2P6S3

There are 29 bicycles built for three.

One bicycle has one frame in it.

To calculate the frame for 29 bicycles, multiply the number of frames in one bicycle by 29.

  F=1F×29=29F

There are 29 frames in 29 bicycles built for three.

(b)

Interpretation Introduction

Interpretation: The number of wheels needed to make 29 bicycles built for three is to be calculated.

Concept Introduction: Reactants, products, and an arrow indicating the reaction's direction make up a chemical equation. A balanced chemical equation is one in which the number of atoms in each of the molecules is the same on both sides of the equation.

(b)

Expert Solution
Check Mark

Answer to Problem 76A

The number of wheels in 29 bicycles built for three is 58.

Explanation of Solution

A bicycle built for three has a frame, two wheels, six pedals, and three seats.

The balanced equation for this bicycle is given as

  F+2W+6P+3S FW2P6S3

There are 29 bicycles built for three.

One bicycle has two wheels in it.

To calculate the wheels for 29 bicycles, multiply the number of wheels in one bicycle by 29.

  W=2W×29=58W

There are 58 wheels in 29 bicycles built for three.

(c)

Interpretation Introduction

Interpretation: The number of pedals needed to make 29 bicycles built for three is to be calculated.

Concept Introduction: Reactants, products, and an arrow indicating the reaction's direction make up a chemical equation. A balanced chemical equation is one in which the number of atoms in each of the molecules is the same on both sides of the equation.

(c)

Expert Solution
Check Mark

Answer to Problem 76A

The number of pedals in 29 bicycles built for three is 174.

Explanation of Solution

A bicycle built for three has a frame, two wheels, six pedals, and three seats.

The balanced equation for this bicycle is given as

  F+2W+6P+3S FW2P6S3

There are 29 bicycles built for three.

One bicycle has six pedals in it.

To calculate the pedals for 29 bicycles, multiply the number of pedals in one bicycle by 29.

  P=6P×29=174P

There are 174 pedals in 29 bicycles built for three.

(d)

Interpretation Introduction

Interpretation: The number of seats needed to make 29 bicycles built for three is to be calculated.

Concept Introduction: Reactants, products, and an arrow indicating the reaction's direction make up a chemical equation. A balanced chemical equation is one in which the number of atoms in each of the molecules is the same on both sides of the equation.

(d)

Expert Solution
Check Mark

Answer to Problem 76A

The number of seats in 29 bicycles built for three is 87.

Explanation of Solution

A bicycle built for three has a frame, two wheels, six pedals, and three seats.

The balanced equation for this bicycle is given as

  F+2W+6P+3S FW2P6S3

There are 29 bicycles built for three.

One bicycle has three seats in it.

To calculate the seats for 29 bicycles, multiply the number of seats in one bicycle by 29.

  S=3S×29=87S

There are 87 seats in 29 bicycles built for three.

Chapter 12 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 12.2 - Prob. 12SPCh. 12.2 - Prob. 13SPCh. 12.2 - Prob. 14SPCh. 12.2 - Prob. 15SPCh. 12.2 - Prob. 16SPCh. 12.2 - Prob. 17SPCh. 12.2 - Prob. 18SPCh. 12.2 - Prob. 19SPCh. 12.2 - Prob. 20SPCh. 12.2 - Prob. 21LCCh. 12.2 - Prob. 22LCCh. 12.2 - Prob. 23LCCh. 12.2 - Prob. 24LCCh. 12.2 - Prob. 25LCCh. 12.3 - Prob. 26SPCh. 12.3 - Prob. 27SPCh. 12.3 - Prob. 28SPCh. 12.3 - Prob. 29SPCh. 12.3 - Prob. 30SPCh. 12.3 - Prob. 31SPCh. 12.3 - Prob. 32SPCh. 12.3 - Prob. 33SPCh. 12.3 - Prob. 34LCCh. 12.3 - Prob. 35LCCh. 12.3 - Prob. 36LCCh. 12.3 - Prob. 37LCCh. 12.3 - Prob. 38LCCh. 12 - Prob. 39ACh. 12 - Prob. 40ACh. 12 - Prob. 41ACh. 12 - Prob. 42ACh. 12 - Prob. 43ACh. 12 - Prob. 44ACh. 12 - Prob. 45ACh. 12 - Prob. 46ACh. 12 - Prob. 47ACh. 12 - Prob. 48ACh. 12 - Prob. 49ACh. 12 - Prob. 50ACh. 12 - Prob. 51ACh. 12 - Prob. 52ACh. 12 - Prob. 53ACh. 12 - Prob. 54ACh. 12 - Prob. 55ACh. 12 - Prob. 56ACh. 12 - Prob. 57ACh. 12 - Prob. 58ACh. 12 - Prob. 59ACh. 12 - Prob. 60ACh. 12 - Prob. 61ACh. 12 - Prob. 62ACh. 12 - Prob. 63ACh. 12 - Prob. 64ACh. 12 - Prob. 65ACh. 12 - Prob. 66ACh. 12 - Prob. 67ACh. 12 - Prob. 68ACh. 12 - Prob. 69ACh. 12 - Prob. 70ACh. 12 - Prob. 71ACh. 12 - Prob. 72ACh. 12 - Prob. 73ACh. 12 - Prob. 74ACh. 12 - Prob. 75ACh. 12 - Prob. 76ACh. 12 - Prob. 77ACh. 12 - Prob. 78ACh. 12 - Prob. 79ACh. 12 - Prob. 80ACh. 12 - Prob. 81ACh. 12 - Prob. 82ACh. 12 - Prob. 83ACh. 12 - Prob. 84ACh. 12 - Prob. 85ACh. 12 - Prob. 88ACh. 12 - Prob. 89ACh. 12 - Prob. 90ACh. 12 - Prob. 91ACh. 12 - Prob. 92ACh. 12 - Prob. 93ACh. 12 - Prob. 94ACh. 12 - Prob. 95ACh. 12 - Prob. 96ACh. 12 - Prob. 97ACh. 12 - Prob. 98ACh. 12 - Prob. 99ACh. 12 - Prob. 100ACh. 12 - Prob. 101ACh. 12 - Prob. 102ACh. 12 - Prob. 103ACh. 12 - Prob. 104ACh. 12 - Prob. 105ACh. 12 - Prob. 106ACh. 12 - Prob. 107ACh. 12 - Prob. 1STPCh. 12 - Prob. 2STPCh. 12 - Prob. 3STPCh. 12 - Prob. 4STPCh. 12 - Prob. 5STPCh. 12 - Prob. 6STPCh. 12 - Prob. 7STPCh. 12 - Prob. 8STPCh. 12 - Prob. 9STPCh. 12 - Prob. 10STP
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