Chapter 12, Problem 1STP

Interpretation Introduction

Interpretation: The correct option in accordance with the given amounts is to be stated.

Concept Introduction: According to the law of conservation of mass, the mass can neither be created nor be destroyed. Every reaction must be balanced. With the help of the balanced equation, the limiting reagent can be found and in accordance with it, the amount of product can be calculated.

Answer to Problem 1STP

The correct option is (A).

Explanation of Solution

The balanced reaction is given as follows:

  ${\text{3NO}}_2\left(g\right)+{\text{H}}_2\text{O}\left(l\right)\to \text{NO}\left(g\right)+2{\text{HNO}}_{\text{3}}\left(aq\right)$

According to the reaction,

  $\begin{array}{c}\text{3}\text{mol}\text{of}{\text{NO}}_2\left(g\right)\to \text{1}\text{mol}\text{of}{\text{H}}_2\text{O}\left(l\right)\\ \text{1}\text{mol}\text{of}{\text{NO}}_2\left(g\right)\to \frac{\text{1}}{3}\text{mol}\text{of}{\text{H}}_2\text{O}\left(l\right)\\ 8.4\text{mol}\text{of}{\text{NO}}_2\left(g\right)\to \frac{\text{1}}{3}\times 8.4\text{mol}\text{of}{\text{H}}_2\text{O}\left(l\right)\\ \to 2.8\text{mol}\text{of}{\text{H}}_2\text{O}\left(l\right)\end{array}$

Thus, 2.8 mol of ${\text{H}}_2\text{O}$ will react with 8.4 mol of ${\text{NO}}_2$ . Hence, the correct option is (A).