Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 12, Problem 40A
Interpretation Introduction

Interpretation: The equation in terms of the interacting number of moles of reactants and products is to be interpreted.

Concept Introduction: Reactants, products, and an arrow indicating the reaction's direction make up a chemical equation. A balanced chemical equation is one in which the number of atoms in each of the molecules is the same on both sides of the equation.

Expert Solution & Answer
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Answer to Problem 40A

In the chemical equation 2KClO3s  2KCls+3O2g , the number of moles of reactant is two and the number of moles of product is five.

In the chemical equation 4NH3g+6NOg 5N2g+6H2Og , the number of moles of reactant is ten and the number of moles of product is eleven.

In the chemical equation 4Ks+O2g  2K2Os , the number of moles of reactant is five and the number of moles of product is two.

Explanation of Solution

The interacting particles are the molecules of reactants and products taking place in a chemical equation.

Consider the given chemical equation as follows:

  2KClO3s  2KCls+3O2g

The three moles of KClO3 decomposes to give two moles of KCl and three moles of O2 .

The number of moles of reactant is two and the number of moles of product is five.

Consider the given chemical equation as follows:

  4NH3g+6NOg 5N2g+6H2Og

The reaction between four moles of NH3 and six molecules of NO gives five moles of N2 and six moles of H2O .

The number of moles of reactant is ten and the number of moles of product is eleven.

Consider the given chemical equation as follows:

  4Ks+O2g  2K2Os

The four moles of K reacts with one mole of O2 to give two moles of K2O .

The number of moles of reactant is five and the number of moles of product is two.

Chapter 12 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 12.2 - Prob. 12SPCh. 12.2 - Prob. 13SPCh. 12.2 - Prob. 14SPCh. 12.2 - Prob. 15SPCh. 12.2 - Prob. 16SPCh. 12.2 - Prob. 17SPCh. 12.2 - Prob. 18SPCh. 12.2 - Prob. 19SPCh. 12.2 - Prob. 20SPCh. 12.2 - Prob. 21LCCh. 12.2 - Prob. 22LCCh. 12.2 - Prob. 23LCCh. 12.2 - Prob. 24LCCh. 12.2 - Prob. 25LCCh. 12.3 - Prob. 26SPCh. 12.3 - Prob. 27SPCh. 12.3 - Prob. 28SPCh. 12.3 - Prob. 29SPCh. 12.3 - Prob. 30SPCh. 12.3 - Prob. 31SPCh. 12.3 - Prob. 32SPCh. 12.3 - Prob. 33SPCh. 12.3 - Prob. 34LCCh. 12.3 - Prob. 35LCCh. 12.3 - Prob. 36LCCh. 12.3 - Prob. 37LCCh. 12.3 - Prob. 38LCCh. 12 - Prob. 39ACh. 12 - Prob. 40ACh. 12 - Prob. 41ACh. 12 - Prob. 42ACh. 12 - Prob. 43ACh. 12 - Prob. 44ACh. 12 - Prob. 45ACh. 12 - Prob. 46ACh. 12 - Prob. 47ACh. 12 - Prob. 48ACh. 12 - Prob. 49ACh. 12 - Prob. 50ACh. 12 - Prob. 51ACh. 12 - Prob. 52ACh. 12 - Prob. 53ACh. 12 - Prob. 54ACh. 12 - Prob. 55ACh. 12 - Prob. 56ACh. 12 - Prob. 57ACh. 12 - Prob. 58ACh. 12 - Prob. 59ACh. 12 - Prob. 60ACh. 12 - Prob. 61ACh. 12 - Prob. 62ACh. 12 - Prob. 63ACh. 12 - Prob. 64ACh. 12 - Prob. 65ACh. 12 - Prob. 66ACh. 12 - Prob. 67ACh. 12 - Prob. 68ACh. 12 - Prob. 69ACh. 12 - Prob. 70ACh. 12 - Prob. 71ACh. 12 - Prob. 72ACh. 12 - Prob. 73ACh. 12 - Prob. 74ACh. 12 - Prob. 75ACh. 12 - Prob. 76ACh. 12 - Prob. 77ACh. 12 - Prob. 78ACh. 12 - Prob. 79ACh. 12 - Prob. 80ACh. 12 - Prob. 81ACh. 12 - Prob. 82ACh. 12 - Prob. 83ACh. 12 - Prob. 84ACh. 12 - Prob. 85ACh. 12 - Prob. 88ACh. 12 - Prob. 89ACh. 12 - Prob. 90ACh. 12 - Prob. 91ACh. 12 - Prob. 92ACh. 12 - Prob. 93ACh. 12 - Prob. 94ACh. 12 - Prob. 95ACh. 12 - Prob. 96ACh. 12 - Prob. 97ACh. 12 - Prob. 98ACh. 12 - Prob. 99ACh. 12 - Prob. 100ACh. 12 - Prob. 101ACh. 12 - Prob. 102ACh. 12 - Prob. 103ACh. 12 - Prob. 104ACh. 12 - Prob. 105ACh. 12 - Prob. 106ACh. 12 - Prob. 107ACh. 12 - Prob. 1STPCh. 12 - Prob. 2STPCh. 12 - Prob. 3STPCh. 12 - Prob. 4STPCh. 12 - Prob. 5STPCh. 12 - Prob. 6STPCh. 12 - Prob. 7STPCh. 12 - Prob. 8STPCh. 12 - Prob. 9STPCh. 12 - Prob. 10STP
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