Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 12, Problem 104A

(a)

Interpretation Introduction

Interpretation: A balanced chemical equation for the equation BaNO32aq+Na2SO4aqBaSO4s+NaNO3aq is to be written.

Concept Introduction: The components of a chemical equation are reactants, products, and a directional arrow. For a chemical reaction to be considered "balanced," both sides of the equation must have the same number of atoms.

(a)

Expert Solution
Check Mark

Answer to Problem 104A

The balanced chemical equation is as follows:

  BaNO32aq+Na2SO4aqBaSO4s+2NaNO3aq

Explanation of Solution

The given chemical equation is as follows:

  BaNO32aq+Na2SO4aqBaSO4s+NaNO3aq

On the right side 1

  Na atom, 2 N atoms, and 10

  O atoms, and on the left side 2

  Na atoms, 1 N atom, and 7

  O atoms are present in this equation. To balance this equation, put the coefficient of 2 in front of NaNO3 .

The balanced chemical equation is as follows:

  BaNO32aq+Na2SO4aqBaSO4s+2NaNO3aq

(b)

Interpretation Introduction

Interpretation: A balanced chemical equation for the equation AlCl3aq+AgNO3aqAgCls+AlNO33aq is to be written.

Concept Introduction: The components of a chemical equation are reactants, products, and a directional arrow. For a chemical reaction to be considered "balanced," both sides of the equation must have the same number of atoms.

(b)

Expert Solution
Check Mark

Answer to Problem 104A

The balanced chemical equation is as follows:

  AlCl3aq+3AgNO3aq3AgCls+AlNO33aq

Explanation of Solution

The given chemical equation is as follows:

  AlCl3aq+AgNO3aqAgCls+AlNO33aq

On the right side 3 Cl atoms, 1 N atom, and 3 O atoms, and on the left side 1 Cl atom, 2 N atoms and 6 O atoms are present in this equation. To balance this equation, put the coefficient of 3 in front of AgNO3 and AgCl .

The balanced chemical equation is as follows:

  AlCl3aq+3AgNO3aq3AgCls+AlNO33aq

(c)

Interpretation Introduction

Interpretation: A balanced chemical equation for the equation H2SO4aq+MgOH2aqMgSO4aq+H2Ol is to be written.

Concept Introduction: The components of a chemical equation are reactants, products, and a directional arrow. For a chemical reaction to be considered "balanced," both sides of the equation must have the same number of atoms.

(c)

Expert Solution
Check Mark

Answer to Problem 104A

The balanced chemical equation is as follows:

  H2SO4aq+MgOH2aqMgSO4aq+2H2Ol

Explanation of Solution

The given chemical equation is as follows:

  H2SO4aq+MgOH2aqMgSO4aq+H2Ol

On the right side 4 H atoms and 6 O atoms and on the left side 2 H atoms, and 5 O atoms are present in this equation. To balance this equation, put the coefficient of 2 in front of H2O .

The balanced chemical equation is as follows:

  H2SO4aq+MgOH2aqMgSO4aq+2H2Ol

Chapter 12 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 12.2 - Prob. 12SPCh. 12.2 - Prob. 13SPCh. 12.2 - Prob. 14SPCh. 12.2 - Prob. 15SPCh. 12.2 - Prob. 16SPCh. 12.2 - Prob. 17SPCh. 12.2 - Prob. 18SPCh. 12.2 - Prob. 19SPCh. 12.2 - Prob. 20SPCh. 12.2 - Prob. 21LCCh. 12.2 - Prob. 22LCCh. 12.2 - Prob. 23LCCh. 12.2 - Prob. 24LCCh. 12.2 - Prob. 25LCCh. 12.3 - Prob. 26SPCh. 12.3 - Prob. 27SPCh. 12.3 - Prob. 28SPCh. 12.3 - Prob. 29SPCh. 12.3 - Prob. 30SPCh. 12.3 - Prob. 31SPCh. 12.3 - Prob. 32SPCh. 12.3 - Prob. 33SPCh. 12.3 - Prob. 34LCCh. 12.3 - Prob. 35LCCh. 12.3 - Prob. 36LCCh. 12.3 - Prob. 37LCCh. 12.3 - Prob. 38LCCh. 12 - Prob. 39ACh. 12 - Prob. 40ACh. 12 - Prob. 41ACh. 12 - Prob. 42ACh. 12 - Prob. 43ACh. 12 - Prob. 44ACh. 12 - Prob. 45ACh. 12 - Prob. 46ACh. 12 - Prob. 47ACh. 12 - Prob. 48ACh. 12 - Prob. 49ACh. 12 - Prob. 50ACh. 12 - Prob. 51ACh. 12 - Prob. 52ACh. 12 - Prob. 53ACh. 12 - Prob. 54ACh. 12 - Prob. 55ACh. 12 - Prob. 56ACh. 12 - Prob. 57ACh. 12 - Prob. 58ACh. 12 - Prob. 59ACh. 12 - Prob. 60ACh. 12 - Prob. 61ACh. 12 - Prob. 62ACh. 12 - Prob. 63ACh. 12 - Prob. 64ACh. 12 - Prob. 65ACh. 12 - Prob. 66ACh. 12 - Prob. 67ACh. 12 - Prob. 68ACh. 12 - Prob. 69ACh. 12 - Prob. 70ACh. 12 - Prob. 71ACh. 12 - Prob. 72ACh. 12 - Prob. 73ACh. 12 - Prob. 74ACh. 12 - Prob. 75ACh. 12 - Prob. 76ACh. 12 - Prob. 77ACh. 12 - Prob. 78ACh. 12 - Prob. 79ACh. 12 - Prob. 80ACh. 12 - Prob. 81ACh. 12 - Prob. 82ACh. 12 - Prob. 83ACh. 12 - Prob. 84ACh. 12 - Prob. 85ACh. 12 - Prob. 88ACh. 12 - Prob. 89ACh. 12 - Prob. 90ACh. 12 - Prob. 91ACh. 12 - Prob. 92ACh. 12 - Prob. 93ACh. 12 - Prob. 94ACh. 12 - Prob. 95ACh. 12 - Prob. 96ACh. 12 - Prob. 97ACh. 12 - Prob. 98ACh. 12 - Prob. 99ACh. 12 - Prob. 100ACh. 12 - Prob. 101ACh. 12 - Prob. 102ACh. 12 - Prob. 103ACh. 12 - Prob. 104ACh. 12 - Prob. 105ACh. 12 - Prob. 106ACh. 12 - Prob. 107ACh. 12 - Prob. 1STPCh. 12 - Prob. 2STPCh. 12 - Prob. 3STPCh. 12 - Prob. 4STPCh. 12 - Prob. 5STPCh. 12 - Prob. 6STPCh. 12 - Prob. 7STPCh. 12 - Prob. 8STPCh. 12 - Prob. 9STPCh. 12 - Prob. 10STP
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