General, Organic, and Biological Chemistry - 4th edition
General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
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Chapter 11.6, Problem 11.11PP
Interpretation Introduction

(a)

Interpretation:

Whether the following molecule is polar or non-polar should be determined:

General, Organic, and Biological Chemistry - 4th edition, Chapter 11.6, Problem 11.11PP , additional homework tip  1

Concept introduction:

Polarity of any individual bond is determined by the electro-negativities of the atoms forming a bond. Any covalent bond is non-polar when two identical atoms or of similar electro-negativity are bonded together. CHandCC bonds are said to be non-polar as their electro-negativities are similar. Bond is said to be polar when two atoms of different electro-negativity are bonded such as bond between carbon atom and hetero-atoms (N,O,halogens) . δ+andδ symbols are given to atoms of less and more electro-negative respectively. Molecule is said to be non-polar if individual bond dipoles cancel in a molecule and if not then the molecule is said to be polar.

Interpretation Introduction

(b)

Interpretation:

Whether the following molecule is polar or non-polar should be determined:

General, Organic, and Biological Chemistry - 4th edition, Chapter 11.6, Problem 11.11PP , additional homework tip  2

Concept introduction:

Polarity of any individual bond is determined by the electro-negativities of the atoms forming a bond. Any covalent bond is non-polar when two identical atoms or of similar electro-negativity are bonded together. CHandCC bonds are said to be non-polar as their electro-negativities are similar. Bond is said to be polar when two atoms of different electro-negativity are bonded such as bond between carbon atom and hetero-atoms (N,O,halogens) . δ+andδ symbols are given to atoms of less and more electro-negative respectively. Molecule is said to be non-polar if individual bond dipoles cancel in a molecule and if not then the molecule is said to be polar.

Interpretation Introduction

(c)

Interpretation:

Whether CCl4 is polar or non-polar should be determined:

Concept introduction:

Polarity of any individual bond is determined by the electro-negativities of the atoms forming a bond. Any covalent bond is non-polar when two identical atoms or of similar electro-negativity are bonded together. CHandCC bonds are said to be non-polar as their electro-negativities are similar. Bond is said to be polar when two atoms of different electro-negativity are bonded such as bond between carbon atom and hetero-atoms (N,O,halogens) . δ+andδ symbols are given to atoms of less and more electro-negative respectively. Molecule is said to be non-polar if individual bond dipoles cancel in a molecule and if not then the molecule is said to be polar.

Interpretation Introduction

(d)

Interpretation:

Whether CH3CH2CH2NH2 is polar or non-polar should be determined:

Concept introduction:

Polarity of any individual bond is determined by the electro-negativities of the atoms forming a bond. Any covalent bond is non-polar when two identical atoms or of similar electro-negativity are bonded together. CHandCC bonds are said to be non-polar as their electro-negativities are similar. Bond is said to be polar when two atoms of different electro-negativity are bonded such as bond between carbon atom and hetero-atoms (N,O,halogens) . δ+andδ symbols are given to atoms of less and more electro-negative respectively. Molecule is said to be non-polar if individual bond dipoles cancel in a molecule and if not then the molecule is said to be polar.

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Label the polar bonds in each molecule, and then decide if the molecule is polar or nonpolar. a. HCl b. C 2H 6 c. CH 2F 2 d. HCN e. CCl 4
II. Complete the table below. Compound Molecular Geometry Molecule Polarity 1. НCСI 2. H2S 3. CH4 4. N2 Dipole moment of CO2 5. Н2О Take note that bond polarity and molecule polarity are not the same. The presence of polar bonds does not automatically make a molecule polar. The geometry of the molecule also plays an important role. This can be seen in CO2 wherein the electronegativity difference of C and O is 1.0. This equal distribution of polar bonds makes the molecule non- polar.
Which molecules have polar bonds? А. A CI B =. E. ö- В. CI Е F H н F. О- Which are polar molecules? С. CH2 CHз CH2 CH2 A CH2 Нзс в C D Н D. Е F

Chapter 11 Solutions

General, Organic, and Biological Chemistry - 4th edition

Ch. 11.4 - Prob. 11.5PCh. 11.4 - How many H’s are bonded to each indicated carbon...Ch. 11.4 - Using the skeletal structure, determine the...Ch. 11.5 - Prob. 11.7PCh. 11.5 - Prob. 11.8PCh. 11.5 - For each compound. [1] Identify the functional...Ch. 11.5 - How do a carboxylic acid and an alcohol differ?...Ch. 11.5 - Label each of the following condensed structures...Ch. 11.5 - Prob. 11.11PCh. 11.5 - Prob. 11.12PCh. 11.5 - Identify all of the functional groups in atenolol,...Ch. 11.5 - Prob. 11.13PCh. 11.5 - Prob. 11.10PPCh. 11.5 - Prob. 11.14PCh. 11.6 - Indicate the polar bonds in each compound. Label...Ch. 11.6 - Prob. 11.11PPCh. 11.6 - Prob. 11.16PCh. 11.6 - Predict the water solubility of each compound.Ch. 11.6 - Prob. 11.17PCh. 11.7 - Prob. 11.18PCh. 11.7 - Prob. 11.19PCh. 11.7 - Prob. 11.20PCh. 11 - Prob. 21PCh. 11 - Prob. 22PCh. 11 - Complete each structure by filling in all H’s and...Ch. 11 - Complete the structure of mepivacaine by filling...Ch. 11 - Prob. 25PCh. 11 - Prob. 26PCh. 11 - Prob. 27PCh. 11 - Prob. 28PCh. 11 - “Ecstasy” is a widely used illegal stimulant....Ch. 11 - Prob. 30PCh. 11 - Explain why each C—C—C bond angle in benzene...Ch. 11 - Prob. 32PCh. 11 - Convert each compound to a condensed structure.Ch. 11 - Convert each compound to a condensed structure.Ch. 11 - Convert each compound to a skeletal structure.Ch. 11 - Convert each compound to a skeletal structure.Ch. 11 - Convert each shorthand structure to a complete...Ch. 11 - Convert each shorthand structure to a complete...Ch. 11 - Convert each skeletal structure to a complete...Ch. 11 - Convert each skeletal structure to a complete...Ch. 11 - A and B are ball-and-stick models of two compounds...Ch. 11 - Prob. 42PCh. 11 - What is wrong in each of the following shorthand...Ch. 11 - Prob. 44PCh. 11 - Prob. 45PCh. 11 - Albuterol (trade names Proventil and Ventolin) is...Ch. 11 - Prob. 47PCh. 11 - Prob. 48PCh. 11 - Prob. 49PCh. 11 - (a) Identify the functional groups in donepezil,...Ch. 11 - Prob. 51PCh. 11 - GHB is an addictive, illegal recreational drug...Ch. 11 - Prob. 53PCh. 11 - Prob. 54PCh. 11 - Prob. 55PCh. 11 - Prob. 56PCh. 11 - Prob. 57PCh. 11 - (a) Identify the functional groups in venlafaxine,...Ch. 11 - You are given two unlabeled bottles of solids, one...Ch. 11 - State how potassium iodide (KI) and pentane...Ch. 11 - The given beaker contains 100 mL of the organic...Ch. 11 - Prob. 62PCh. 11 - Why do we need to know the shape of a molecule...Ch. 11 - 1,1-Dichloroethylene (CH2=CCl2) is a starting...Ch. 11 - Indicate the polar bonds in each molecule. Label...Ch. 11 - Indicate the polar bonds in each molecule. Label...Ch. 11 - Classify each molecule as polar or nonpolar.Ch. 11 - Classify each molecule as polar or nonpolar. a....Ch. 11 - Which molecule is more water soluble? Explain.Ch. 11 - Explain why pantothenic acid, vitamin B5, is water...Ch. 11 - Prob. 71PCh. 11 - Prob. 72PCh. 11 - Explain why regularly taking a large excess of a...Ch. 11 - You can obtain the minimum daily requirement of...Ch. 11 - Prob. 75PCh. 11 - Vitamin B6 is obtained by eating a diet that...Ch. 11 - Prob. 77PCh. 11 - Can an oxygen-containing organic compound, have...Ch. 11 - Prob. 79PCh. 11 - Prob. 80PCh. 11 - Benzocaine is the active ingredient in topical...Ch. 11 - Methyl salicylate is responsible for the...Ch. 11 - Answer the following questions about aldosterone,...Ch. 11 - Answer the following questions about...Ch. 11 - Prob. 85PCh. 11 - Skin moisturizers come in two types, (a) One type...Ch. 11 - THC is the active component in marijuana (Section...Ch. 11 - Cocaine is a widely abused, addicting drug....
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Types of bonds; Author: Edspira;https://www.youtube.com/watch?v=Jj0V01Arebk;License: Standard YouTube License, CC-BY