Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
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Chapter 1, Problem 19P
a.
Summary Introduction
To determine: The number of sheets of paper printed on one side that would be required to print out the human genome.
Introduction: The Human Genome Project was an international scientific research project to determine the base pairs that make up human DNA.
b.
Summary Introduction
To determine: The tallness of the stack of paper with the entire human genome.
Introduction: The Human Genome Project is the international, collaborative research program whose goal was the complete mapping and understanding of all the genes of human beings.
c.
Summary Introduction
To determine: What would be required among a backpack shopping cart or a semitrailer truck to haul around this stack.
Introduction: The Human Genome Project is the world's largest collaborative biological project.
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The human genome (3.4 Gb) would be 2.3 metres long if stretched linearly. In not more than 200 words, explain how a genome of this size is fit into a cell of minuscule proportions. You may add a diagram to your answer.
a. What type of nucleic acid and from what species would the scientist use to begin
construction of her genomic DNA library?
b. From what tissue would she isolate this nucleic acid?
c. What type of reagent would the scientist use to cut the genome into appropriately sized
fragments?
d. What size nucleic acid fragments would one aim to prepare for the library construction
so as to to avoid having to screen an overwhelming number of clones?
e. Into what vector would the scientist ligate her genomic DNA fragments?
f. What organism would the scientist use to propagate the clones of her genomic DNA
library?
g. From the information given in the problem determine what probe could be used to
screen the scientist's library to find her clone of interest ?
A compact disc (CD) stores about 4.8 × 109 bits of information in a 96 cm2 area. This information is stored as a binary code—that is, every bit is either a 0 or a 1.
how many bits would it take to specify each nucleotide pair in a DNA sequence?
how many CDs would it take to store the information contained in the human genome?
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- The human genome (3.4Gb) would be 2.3 metres long if stretched linearly. In not more than 200 words, explain how a genome of this size is fit into a cell if minuscule proportionsarrow_forwardAssume 2x108 reads of 75 bps long are obtained from a next-generation sequencing experiment to sequence a human genome. Suppose the length of the human genome is 3x109 bps. What is the depth (i.e., coverage) of the sequencing?arrow_forwardE. How many nucleotides would be required to generate a polypeptide that is 15 amino acids long? This requires knowing how many nucleotides of DNA code for one amino acid. F. Assuming that there are between 20,000-25,000 genes in the human genome, do you think there are 1) fewer, 2) approximately the same number, or 3) more proteins in the human genome? Explain your answer.arrow_forward
- Give typing answer with explanation and conclusion to all parts Maxim-Gilbert and Sanger Sequencing are two different methods used to sequence DNA. Describe the general techniques of Maxim-Gilbert and Sanger DNA Sequencing. List the advantages and disadvantages of each.arrow_forwardIn not more than 200 words, explain how the human genome of 3.4 Gb would be in 2.3 meters long when stretched linearly if this size is fit into a cell of minuscule proportions.arrow_forwardYou have sequenced the genome of the bacterium Salmonella typhimurium, and you are using BLAST analysis to identify similarities within the S. typhimurium genome to known proteins. You find a protein that is 100 percent identical in the bacterium Escherichia coli. When you compare nucleotide sequences of the S. typhimurium and E. coli genes, you find that their nucleotide sequences are only 87 percent identical.a. Explain this observation.b. What do these observations tell you about the merits of nucleotide- versus protein-similarity searches in identifying related genes?arrow_forward
- Consider a genome whose length is 1000 bp. "Shotgun" sequencing techniques are applied to the genome, resulting in 20 reads, with an average length of 50 bp. A very important point is that, even though 20×50 = 1000, there is no guarantee that ALL 1000 bp of the genome are represented in the fragments. Calculate the coverage. What does this value mean? Why would it be a good idea to have a coverage greater than 1?arrow_forwardThe human genome 3.4 Gb would be 2.3 meters long if stretched linearly.In not more than 200 words,explain how a genome of this size is fit into a cell of minuscule proportions.arrow_forwardWhen performing Sanger sequencing a scientist accidentally forgot to include ddGTP in his sequencing reaction (he did include ddATP, ddCTP, and ddTTP along with all the other needed components). Which of the following statements are true? A.All DNA fragments will terminate at the first G base pair B.A color will be missing from the chromatogram. C.The sequencing primer will not contain G base pairs. D.There will be gaps in the chromatogram.arrow_forward
- If a virus particle contained double-stranded B-DNA of 400,000 base pairs, A. How many complete helical turns would occur on each strand? B. How many atoms of phosphorus would be present? C. If the mole % of G in this genome is 17%, what is the mole % of A?arrow_forwardA diploid human cell contains approximately 6.4 billion base pairs of DNA. a. How many nucleosomes are present in such a cell? (Assume that the linker DNA encompasses 40 bp.) b. How many histone proteins are complexed with this DNA?arrow_forwardHow many Illumina clusters would you need to generate 15X coverage of the human genome, assuming your read lenght is 600 bp? (assume a human genome size of 3 billion bp) - 2.5 billion - 75 million - 7 million - 100 millionarrow_forward
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Genome Annotation, Sequence Conventions and Reading Frames; Author: Loren Launen;https://www.youtube.com/watch?v=MWvYgGyqVys;License: Standard Youtube License