Chapter 9, Problem 99A

Interpretation Introduction

(a)

Interpretation:

The complete ionic equation and net ionic equations for given chemical reaction needs to be determined.

${\text{K}}_{\text{2}}\text{S}\left(aq\right)+{\text{CoCl}}_{\text{2}}\left(aq\right)\to 2\text{KCl}\left(aq\right)+\text{CoS}\left(s\right)$

Concept introduction Chemical equation is the balanced chemical equation which shows the reactants and products using their chemical formulas. An ionic equation represents all the particles in a solution according to their existence and net ionic equations are the ionic equations that include only the particles participating in the reaction.

Answer to Problem 99A

For given equation ionic equation is as follows:

${\text{2K}}^{\text{+}}\left(aq\right)+{\text{S}}^{2-}\left(aq\right){\text{+Co}}^{\text{2+}}\left(aq\right){\text{+2Cl}}^{-}\left(aq\right)\to 2{\text{K}}^{\text{+}}\left(aq\right)+2{\text{Cl}}^{-}\left(aq\right)+\text{CoS}\left(s\right)$

Net ionic equation is as follows:

${\text{S}}^{2-}\left(aq\right){\text{+Co}}^{\text{2+}}\left(aq\right)\to \text{CoS}\left(s\right)$

Explanation of Solution

The given equation is as follows:

${\text{K}}_{\text{2}}\text{S}\left(aq\right)+{\text{CoCl}}_{\text{2}}\left(aq\right)\to 2\text{KCl}\left(aq\right)+\text{CoS}\left(s\right)$

For the above equation complete ionic equation is as follows:

${\text{2K}}^{\text{+}}\left(aq\right)+{\text{S}}^{2-}\left(aq\right){\text{+Co}}^{\text{2+}}\left(aq\right){\text{+2Cl}}^{-}\left(aq\right)\to 2{\text{K}}^{\text{+}}\left(aq\right)+2{\text{Cl}}^{-}\left(aq\right)+\text{CoS}\left(s\right)$

After eliminates all ions that are shared by both sides net ionic equation is as follows:

$\begin{array}{l}\cancel{{\text{2K}}^{\text{+}}\left(aq\right)}+{\text{S}}^{2-}\left(aq\right){\text{+Co}}^{\text{2+}}\left(aq\right)\text{+}\cancel{{\text{2Cl}}^{-}\left(aq\right)}\to \cancel{{\text{2K}}^{\text{+}}\left(aq\right)}+\cancel{{\text{2Cl}}^{-}\left(aq\right)}+\text{CoS}\left(s\right)\\ {\text{S}}^{2-}\left(aq\right){\text{+Co}}^{\text{2+}}\left(aq\right)\to \text{CoS}\left(s\right)\end{array}$

(b)

Interpretation Introduction

Interpretation:

The complete ionic equation and net ionic equations for given chemical reaction needs to be determined.

${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}\left(aq\right)+{\text{CaCO}}_3\left(s\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{CO}}_{\text{2}}\left(g\right)+{\text{CaSO}}_{\text{4}}\left(s\right)$

Concept introduction:

Chemical equation is the symbolic description of a chemical reaction that products and reactants are indicating in terms of their chemical formula. Net ionic equation eliminates all ions which are shared by both sides.

Answer to Problem 99A

For given equation ionic equation complete ionic equation and net ionic equation is same.

${\text{2H}}^{\text{2+}}\left(aq\right)+{\text{SO}}^{2-}{}_4\left(aq\right){\text{+CaCO}}_3\left(s\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{CO}}_{\text{2}}\left(g\right)+{\text{CaSO}}_{\text{4}}\left(s\right)$

Explanation of Solution

The given equation is as follows:

${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}\left(aq\right)+{\text{CaCO}}_3\left(s\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{CO}}_{\text{2}}\left(g\right)+{\text{CaSO}}_{\text{4}}\left(s\right)$

For the above equation complete ionic equation is as follows:

${\text{2H}}^{\text{2+}}\left(aq\right)+{\text{SO}}^{2-}{}_4\left(aq\right){\text{+CaCO}}_3\left(s\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{CO}}_{\text{2}}\left(g\right)+{\text{CaSO}}_{\text{4}}\left(s\right)$

There are no spectator ions in the above equation. So, the net ionic equation is same as complete ionic equation. So, net ionic equation is,

${\text{2H}}^{\text{2+}}\left(aq\right)+{\text{SO}}^{2-}{}_4\left(aq\right){\text{+CaCO}}_3\left(s\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{CO}}_{\text{2}}\left(g\right)+{\text{CaSO}}_{\text{4}}\left(s\right)$

(c)

Interpretation Introduction

Interpretation:

The complete ionic equation and net ionic equations for given chemical reaction needs to be determined.

$2\text{HClO}\left(aq\right)+\text{Ca}{\left(\text{OH}\right)}_{\text{2}}\left(aq\right)\to 2{\text{H}}_{\text{2}}\text{O}\left(l\right)+\text{Ca}{\left(\text{ClO}\right)}_{\text{2}}\left(aq\right)$

Concept introduction Chemical equation is the balanced chemical equation which shows the reactants and products using their chemical formulas. An ionic equation represents all the particles in a solution according to their existence and net ionic equations are the ionic equations that include only the particles participating in the reaction.

Answer to Problem 99A

Complete ionic equation is as follows:

${\text{2H}}^{\text{+}}\left(aq\right)+2{\text{ClO}}^{-}\left(aq\right){\text{+Ca}}^{\text{2+}}\left(aq\right){\text{+2OH}}^{-}\left(aq\right)\to 2{\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{Ca}}^{\text{2+}}\left(aq\right)+2{\text{ClO}}^{-}\left(aq\right)$

Net ionic equation is,

${\text{H}}^{\text{+}}\left(aq\right)\text{+}{\text{OH}}^{-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)$

Explanation of Solution

The given equation is as follows:

$2\text{HClO}\left(aq\right)+\text{Ca}{\left(\text{OH}\right)}_{\text{2}}\left(aq\right)\to 2{\text{H}}_{\text{2}}\text{O}\left(l\right)+\text{Ca}{\left(\text{ClO}\right)}_{\text{2}}\left(aq\right)$

For the above equation complete ionic equation is as follows:

${\text{2H}}^{\text{+}}\left(aq\right)+2{\text{ClO}}^{-}\left(aq\right){\text{+Ca}}^{\text{2+}}\left(aq\right){\text{+2OH}}^{-}\left(aq\right)\to 2{\text{H}}_{\text{2}}\text{O}\left(l\right)+{\text{Ca}}^{\text{2+}}\left(aq\right)+2{\text{ClO}}^{-}\left(aq\right)$

Net ionic equation cancels all the spectator ions of the reaction. So, the net ionic equation is as follows:

$\begin{array}{l}{\text{2H}}^{\text{+}}\left(aq\right)+\cancel{2{\text{ClO}}^{-}\left(aq\right)}\text{+}\cancel{{\text{Ca}}^{\text{2+}}\left(aq\right)}{\text{+2OH}}^{-}\left(aq\right)\to 2{\text{H}}_{\text{2}}\text{O}\left(l\right)+\cancel{{\text{Ca}}^{\text{2+}}\left(aq\right)}+\cancel{2{\text{ClO}}^{-}\left(aq\right)}\\ {\text{2H}}^{\text{+}}\left(aq\right){\text{+2OH}}^{-}\left(aq\right)\to 2{\text{H}}_{\text{2}}\text{O}\left(l\right)\\ {\text{H}}^{\text{+}}\left(aq\right)\text{+}{\text{OH}}^{-}\left(aq\right)\to {\text{H}}_{\text{2}}\text{O}\left(l\right)\end{array}$