Chapter 9, Problem 69A

Interpretation Introduction

(a)

Interpretation:

Skeleton equation for the reaction needs to be written.

$\text{Butane}\left({\text{C}}_{\text{4}}{\text{H}}_{\text{10}}\right)\text{+Oxygen}\left(\text{l}\right)\to \text{Carbon}\text{dioxide}\left(\text{g}\right)\text{+}\text{water}\left(\text{l}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 69A

The skeleton equation for the reaction

$\text{Butane}\left({\text{C}}_{\text{4}}{\text{H}}_{\text{10}}\right)\text{+Oxygen}\left(\text{l}\right)\to \text{Carbon}\text{dioxide}\left(\text{g}\right)\text{+}\text{water}\left(\text{l}\right)$ is given as,

${\text{C}}_{\text{4}}{\text{H}}_{\text{10}}\left(\text{g}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to {\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)$

Explanation of Solution

To determine the skeleton formula of a reaction, one must know the chemical symbols of elements and compounds. A skeleton equation shows the reactants and products using the chemical formula of them and the balancing of the reaction is not required.

The formula of butane, oxygen, carbon dioxide and water is ${\text{C}}_{\text{4}}{\text{H}}_{\text{10}}$, ${\text{O}}_{\text{2}}$, ${\text{CO}}_{\text{2}}$ and ${\text{H}}_{\text{2}}\text{O}$ respectively. So, the skeleton equation will be:

${\text{C}}_{\text{4}}{\text{H}}_{\text{10}}\left(\text{g}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to {\text{CO}}_{\text{2}}\left(\text{g}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)$

(b)

Interpretation Introduction

Interpretation:

The skeleton equation for the reaction needs to be determined.

$\text{aluminium}\text{carbonate}\left(\text{s}\right)\to \text{aluminium}\text{oxide}\left(\text{s}\right)\text{+}\text{carbon}\text{dioxide}\left(\text{g}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 69A

The skeleton equation for the reaction

$\text{aluminium}\text{carbonate}\left(\text{s}\right)\to \text{aluminium}\text{oxide}\left(\text{s}\right)\text{+}\text{carbon}\text{dioxide}\left(\text{g}\right)$ is,

${\text{Al}}_{\text{2}}{\left({\text{CO}}_{\text{3}}\right)}_{\text{3}}\to \left(\text{s}\right){\text{Al}}_{\text{2}}{\text{O}}_{\text{3}}\left(\text{s}\right)\text{+}{\text{CO}}_{\text{2}}\left(\text{g}\right)$

Explanation of Solution

To determine the skeleton formula of a reaction, we must know the chemical symbols of elements and compounds. A skeleton equation shows the reactants and products using the chemical formula of them and the balancing of the reaction is not required.

The formula of aluminium carbonate, aluminium oxide and carbon dioxide is ${\text{Al}}_{\text{2}}{\left({\text{CO}}_{\text{3}}\right)}_{\text{3}}$, ${\text{Al}}_{\text{2}}{\text{O}}_{\text{3}}$ and ${\text{3CO}}_{\text{2}}$ respectively.

So, the skeleton equation is,

${\text{Al}}_{\text{2}}{\left({\text{CO}}_{\text{3}}\right)}_{\text{3}}\to \left(\text{s}\right){\text{Al}}_{\text{2}}{\text{O}}_{\text{3}}\left(\text{s}\right)\text{+}{\text{CO}}_{\text{2}}\left(\text{g}\right)$

(c)

Interpretation Introduction

Interpretation:

The skeleton equation for the reaction needs to be determined.

$\text{silver}\text{nitrate}\left(\text{aq}\right)\text{+}\text{sodium}\text{sulfide}\left(\text{aq}\right)\to \text{silvers}\text{sulfide}\left(\text{s}\right)\text{+}\text{sodium}\text{nitate}\left(\text{aq}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Answer to Problem 69A

The skeleton equation for the reaction

$\text{silver}\text{nitrate}\left(\text{aq}\right)\text{+}\text{sodium}\text{sulfide}\left(\text{aq}\right)\to \text{silvers}\text{sulfide}\left(\text{s}\right)\text{+}\text{sodium}\text{nitate}\left(\text{aq}\right)$ is

${\text{AgNO}}_{\text{3}}\left(\text{aq}\right){\text{+Na}}_2\text{S}\left(\text{aq}\right)\to {\text{Ag}}_2\text{S}\left(\text{s}\right)\text{+}{\text{NaNO}}_{\text{3}}\left(\text{aq}\right)$

Explanation of Solution

To determine the skeleton formula of a reaction, we must know the chemical symbols of elements and compounds. A skeleton equation shows the reactants and products using the chemical formula of them and the balancing of the reaction is not required.

The formula of silver nitrate, sodium sulfide, silver sulfide and sodium nitrate is ${\text{AgNO}}_{\text{3}}$, ${\text{Na}}_2\text{S}$, ${\text{Ag}}_2\text{S}$ and ${\text{NaNO}}_{\text{3}}$

So, the skeleton equation is given as,

${\text{AgNO}}_{\text{3}}\left(\text{aq}\right){\text{+Na}}_2\text{S}\left(\text{aq}\right)\to {\text{Ag}}_2\text{S}\left(\text{s}\right)\text{+}{\text{NaNO}}_{\text{3}}\left(\text{aq}\right)$