Chemistry: The Molecular Science
5th Edition
ISBN: 9781285199047
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
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Chapter 9, Problem 77QRT
Interpretation Introduction
Interpretation:
The principal difference between the orbitals in isolated atoms and in solid metals has to be described.
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Explain how periodic trends in ionization energy and electron affinity explain why atoms of elements in Group I andGroup II tend to bond with other elements by forming positive ions in ionic compounds. Explain with electronconfiguration of elements belonging to Group I and Group II.
What results from an unequal sharing of electrons between atoms?
(P), respectively.
Arrangement of Sodium (Na)
Atoms in Pure Element
88
Arrangement of Phosphorus (P)
Atoms in Pure Element
In terms of how electrons exist in these two materials, which of the below statements is true?
electrons in sodium (Na) are uniformly distributed throughout the crystal within a "sea" of delocalized
electrons; electrons in phosphorus (P) are uniformly distributed throughout the crystal within a "sea"
of delocalized electrons
electrons in sodium (Na) are associated with each sodium atom due to the presence of ionic bonding;
electrons in phosphorus (P) are uniformly distributed throughout the crystal within a "sea" of
delocalized electrons
electrons in sodium (Na) are found mostly within covalent bonds between neighboring nuclei;
electrons in phosphorus (P) are uniformly distributed throughout the crystal within a "sea" of
delocalized electrons
electrons in sodium (Na) are uniformly distributed throughout the crystal within a "sea" of delocalized
electrons; electrons…
Chapter 9 Solutions
Chemistry: The Molecular Science
Ch. 9.1 - Prob. 9.1CECh. 9.2 - Prob. 9.2CECh. 9.2 - Prob. 9.1PSPCh. 9.2 - What mass (g) of ethanol, CH3CH2OH(), can be...Ch. 9.3 - Prob. 9.3CECh. 9.3 - Prob. 9.4CECh. 9.3 - Prob. 9.3PSPCh. 9.4 - What types of solids are these substances? (a) The...Ch. 9.4 - Prob. 9.5PSPCh. 9.4 - Prob. 9.5E
Ch. 9.4 - Prob. 9.6CECh. 9.4 - Sublimation is an excellent means of purification...Ch. 9.4 - Prob. 9.6PSPCh. 9.4 - Prob. 9.8ECh. 9.4 - Prob. 9.9ECh. 9.5 - Predict which liquid—glycerol, HOCH2CH(OH)CH2OH,...Ch. 9.5 - Prob. 9.11CECh. 9.6 - Crystalline polonium has a primitive cubic unit...Ch. 9.6 - Calculate the unit cell edge length of copper...Ch. 9.6 - Vanadium metal crystallizes in a body-centered...Ch. 9.6 - Prob. 9.13ECh. 9.6 - Prob. 9.14ECh. 9.6 - Prob. 9.9PSPCh. 9.9 - Prob. 9.10PSPCh. 9.9 - The graph below is obtained when a liquid metal is...Ch. 9.9 - Look in Appendix D and compare the electron...Ch. 9.11 - Prob. 9.11PSPCh. 9 - Prob. ISPCh. 9 - Prob. IISPCh. 9 - Prob. IIISPCh. 9 - Prob. 1QRTCh. 9 - Prob. 2QRTCh. 9 - Prob. 3QRTCh. 9 - Prob. 4QRTCh. 9 - Prob. 5QRTCh. 9 - Prob. 6QRTCh. 9 - Which processes are endothermic? (a) Condensation...Ch. 9 - Prob. 8QRTCh. 9 - Prob. 9QRTCh. 9 - Prob. 10QRTCh. 9 - Prob. 11QRTCh. 9 - Prob. 12QRTCh. 9 - Prob. 13QRTCh. 9 - After exercising on a hot summer day and working...Ch. 9 - Prob. 15QRTCh. 9 - The molar vaporization enthalpy of methanol is...Ch. 9 - Prob. 17QRTCh. 9 - Mercury is highly toxic. Although it is a liquid...Ch. 9 - Prob. 19QRTCh. 9 - Prob. 20QRTCh. 9 - Prob. 21QRTCh. 9 - Prob. 22QRTCh. 9 - Prob. 23QRTCh. 9 - Prob. 24QRTCh. 9 - Prob. 25QRTCh. 9 - Prob. 26QRTCh. 9 - A liquid has a vapH of 38.7 kJ/mol and a boiling...Ch. 9 - Prob. 28QRTCh. 9 - The vapor pressure of ethanol, C2H5OH, at 50.0 C...Ch. 9 - Prob. 30QRTCh. 9 - Prob. 31QRTCh. 9 - Prob. 32QRTCh. 9 - Which would you expect to have the higher fusion...Ch. 9 - Prob. 34QRTCh. 9 - Prob. 35QRTCh. 9 - Prob. 36QRTCh. 9 - Prob. 37QRTCh. 9 - Prob. 38QRTCh. 9 - Prob. 39QRTCh. 9 - Prob. 40QRTCh. 9 - Prob. 41QRTCh. 9 - Prob. 42QRTCh. 9 - Prob. 43QRTCh. 9 - Prob. 44QRTCh. 9 - At the critical point for carbon dioxide, the...Ch. 9 - Prob. 46QRTCh. 9 - Prob. 47QRTCh. 9 - On the basis of the description given, classify...Ch. 9 - On the basis of the description given, classify...Ch. 9 - Prob. 50QRTCh. 9 - Prob. 51QRTCh. 9 - Prob. 52QRTCh. 9 - Prob. 53QRTCh. 9 - Prob. 54QRTCh. 9 - Prob. 55QRTCh. 9 - Prob. 56QRTCh. 9 - Prob. 57QRTCh. 9 - Prob. 58QRTCh. 9 - Prob. 59QRTCh. 9 - Prob. 60QRTCh. 9 - Prob. 61QRTCh. 9 - The ionic radii of Cs+ and Cl are 181 and 167 pm,...Ch. 9 - Prob. 63QRTCh. 9 - Prob. 64QRTCh. 9 - Prob. 65QRTCh. 9 - Tungsten has a body-centered cubic unit cell and...Ch. 9 - Prob. 67QRTCh. 9 - Prob. 68QRTCh. 9 - Prob. 69QRTCh. 9 - Prob. 70QRTCh. 9 - Prob. 71QRTCh. 9 - Prob. 72QRTCh. 9 - Prob. 73QRTCh. 9 - Prob. 74QRTCh. 9 - Prob. 75QRTCh. 9 - Prob. 76QRTCh. 9 - Prob. 77QRTCh. 9 - Prob. 78QRTCh. 9 - Prob. 79QRTCh. 9 - Prob. 80QRTCh. 9 - Which substance has the greatest electrical...Ch. 9 - Prob. 82QRTCh. 9 - Prob. 83QRTCh. 9 - Prob. 84QRTCh. 9 - Prob. 85QRTCh. 9 - Prob. 86QRTCh. 9 - What makes a glass different from a crystalline...Ch. 9 - Prob. 88QRTCh. 9 - Prob. 89QRTCh. 9 - Prob. 90QRTCh. 9 - Will a closed container of water at 70 C or an...Ch. 9 - Prob. 92QRTCh. 9 - Prob. 95QRTCh. 9 - Prob. 96QRTCh. 9 - Prob. 97QRTCh. 9 - Prob. 98QRTCh. 9 - Prob. 99QRTCh. 9 - Prob. 100QRTCh. 9 - Prob. 101QRTCh. 9 - Prob. 102QRTCh. 9 - Prob. 103QRTCh. 9 - Consider this information regarding two compounds....Ch. 9 - Prob. 105QRTCh. 9 - Prob. 106QRTCh. 9 - If you get boiling water at 100 C on your skin, it...Ch. 9 - Prob. 108QRTCh. 9 - The normal boiling point of SO2 is 263.1 K and...Ch. 9 - Butane is a gas at room temperature; however, if...Ch. 9 - Prob. 111QRTCh. 9 - Examine the nanoscale diagrams and the phase...Ch. 9 - Consider the phase diagram and heating-curve...Ch. 9 - Prob. 115QRTCh. 9 - Prob. 116QRTCh. 9 - The phase diagram for water over a relative narrow...Ch. 9 - Prob. 118QRTCh. 9 - Prob. 119QRTCh. 9 - Prob. 120QRTCh. 9 - Prob. 121QRTCh. 9 - Prob. 122QRTCh. 9 - Titanium metal crystallizes in a body-centered...Ch. 9 - Prob. 9.ACPCh. 9 - Prob. 9.BCPCh. 9 - Prob. 9.CCP
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- Look in Appendix D and compare the electron configurations shown there with the fusion enthalpies for the metals shown in Table 9.7. Is there any correlation between these configurations and this property? Does strength of attraction among metal atoms correlate with number of valence electrons? Explain your answers.arrow_forward4. Which of these two metals will have a higher melting point? Explain your choice. Na and Alarrow_forwardA carbon atom can absorb radiation of various wavelengths with resulting changes in its electronic configuration. Write orbital diagrams for the electronic configurations of carbon that result from absorption of the three longest wavelengths of radiation that change its electronic configuration.arrow_forward
- Explain the term "electron sea" in terms of metallic bonding and use it explain one of the properties (such as malleability or conductivity) of a metal such as copper.arrow_forwardThere are properties associated with electromagnets. O a four Ob one three twoarrow_forward8. What is the relationship between an electron configuration and an orbital diagram? Draw the orbital diagram of Silicon as and use it to clearly show how it relates to the electron configuration of Silicon. -arrow_forward
- 4. When a phosphorus atom is substituted for a silicon atom in a crystal, four of the phosphorus valence electrons form bonds with neighboring atoms and the remaining electron is much more loosely bound. You can model the electron as free to move through the crystal lattice. The phosphorus nucleus has one more positive charge than does the silicon nucleus, however, so the extra electron provided by the phosphorus atom is attracted to this single nuclear charge +e. The energy levels of the extra electron are similar to those of the electron in the Bohr hydrogen atom with two important exceptions. First, the Coulomb attraction between the electron and the positive charge on the phosphorus nucleus is reduced by a factor of 1/K from what it would be in free space, where is the dielectric constant of the crystal. As a result, the orbit radii are greatly increased over those of the hydrogen atom. Second, the influence of the periodic electric potential of the lattice causes the electron to…arrow_forward5. Which noble gas has the lowest first ionization energy and why.arrow_forwardPhotoelectron spectroscopy applies the principle of the photoelectric effect to study orbital energies of atoms and mol ecules. High-energy radiation (usually UV or x-ray) is absorbed by a sample and an electron is ejected. The orbital energy can be calculated from the known energy of the radiation and the mea sured energy of the electron lost. The following energy differences were determined for several electron transitions: ∆E2→1 = 4.098x10-17 J ∆E3→£1 = 4.854x10-17 J ∆E5→1 = 5.242x10-17 J ∆E4→2 = 1.024x10-17 J Calculate ∆E and l of a photon emitted in the following transitions: (a) level 3 → 2; (b) level 4 → 1; (c) level 5→4.arrow_forward
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