Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 9, Problem 34CQ
To determine
The elastic strain in the material under stress relaxation.
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The value of strain if stress is 35 MPa and Youngs modulus
65 MPa
(a) Illustrate a typical stress-strain curve for brittle and ductile materials.
Briefly explain the (a) how and (b) why the size of elastic deformation changes as the thickness of the specimen increases when a rod-shaped specimen made of the same material is bent.
Chapter 9 Solutions
Materials Science And Engineering Properties
Ch. 9 - Prob. 1CQCh. 9 - Prob. 2CQCh. 9 - Prob. 3CQCh. 9 - Prob. 4CQCh. 9 - Prob. 5CQCh. 9 - Prob. 6CQCh. 9 - Prob. 7CQCh. 9 - Prob. 8CQCh. 9 - Prob. 9CQCh. 9 - Prob. 10CQ
Ch. 9 - Prob. 11CQCh. 9 - Prob. 12CQCh. 9 - Prob. 13CQCh. 9 - At temperatures above the equi-cohesive...Ch. 9 - Prob. 15CQCh. 9 - Prob. 16CQCh. 9 - Prob. 17CQCh. 9 - Prob. 18CQCh. 9 - Prob. 19CQCh. 9 - Prob. 20CQCh. 9 - Prob. 21CQCh. 9 - Prob. 22CQCh. 9 - Prob. 23CQCh. 9 - Prob. 24CQCh. 9 - Prob. 25CQCh. 9 - Prob. 26CQCh. 9 - Prob. 27CQCh. 9 - Prob. 28CQCh. 9 - Prob. 29CQCh. 9 - Prob. 30CQCh. 9 - Prob. 31CQCh. 9 - Prob. 32CQCh. 9 - Prob. 33CQCh. 9 - Prob. 34CQCh. 9 - Prob. 35CQCh. 9 - Prob. 1ETSQCh. 9 - Prob. 2ETSQCh. 9 - Prob. 3ETSQCh. 9 - Prob. 4ETSQCh. 9 - Prob. 5ETSQCh. 9 - Prob. 6ETSQCh. 9 - Prob. 7ETSQCh. 9 - Prob. 8ETSQCh. 9 - Prob. 9ETSQCh. 9 - Prob. 10ETSQCh. 9 - Prob. 11ETSQCh. 9 - Prob. 12ETSQCh. 9 - Prob. 9.1PCh. 9 - Prob. 9.2PCh. 9 - Prob. 9.3PCh. 9 - Prob. 9.4PCh. 9 - Prob. 9.5PCh. 9 - Prob. 9.6PCh. 9 - Prob. 9.7PCh. 9 - Prob. 9.8PCh. 9 - Prob. 9.9PCh. 9 - Prob. 9.10PCh. 9 - For silver at a tensile stress of 7 MPa and a...Ch. 9 - For germanium at a tensile stress of 410 MPa and a...Ch. 9 - Prob. 9.13PCh. 9 - Prob. 9.14PCh. 9 - Prob. 9.15PCh. 9 - Prob. 9.16PCh. 9 - Prob. 9.17PCh. 9 - Prob. 9.18PCh. 9 - Prob. 9.19PCh. 9 - Prob. 9.20PCh. 9 - Prob. 9.21PCh. 9 - Prob. 9.22P
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- A single zinc crystal is loaded in tension with the normal to its slip plane at 60° to the tensile axis and the slip direction at 40° to the tensile axis. a) Calculate the resolved shear stress when a tensile stress of0.69 MPa is applied. b) What tensile stress is necessary to reach the critical resolved shear stress of 0.94 MPa?arrow_forwardAt a point in a strained material, tensile stress of 100 MPa and compressive stress of 60 MPa are found to be principal stresses Maximum shear stress at that point is: O 60 MPa O 20 MPa O 40 MPa O 80 MPaarrow_forwardAt an axial load of 20 kN, a 35-mm-wide by 10-mm-thick polyimide polymer bar elongates 2.7 mm while the bar width contracts 0.15 mm. The bar is 240 mm long. At the 20-kN load, the stress in the polymer bar is less than its proportional limit.Determine(a) the modulus of elasticity.(b) Poisson’s ratio.(c) the change in the bar thickness.arrow_forward
- At an axial load of 25 kN, a 50-mm-wide by 15-mm-thick polyimide polymer bar elongates 3.1 mm while the bar width contracts 0.26 mm. The bar is 220 mm long. At the 25-kN load, the stress in the polymer bar is less than its proportional limit Determine (a) the modulus of elasticity. (b) Poisson's ratio. (c) the change in the bar thickness. Answers: (a) E- (b) v- (c) Audness GPa mmarrow_forwardAt an axial load of 20 kN, a 45-mm-wide by 10-mm-thick polyimide polymer bar elongates 3.3 mm while the bar width contracts 0.21 mm. The bar is 240 mm long. At the 20-kN load, the stress in the polymer bar is less than its proportional limit. Determine (a) the modulus of elasticity. (b) Poisson's ratio. (c) the change in the bar thickness. Answers: (a) E= (b) v = (c) Athickness= i i i GPa mmarrow_forwardA plate in equilibrium is subjected to uniform stresses along its edges with magnitude o = 30 %3D MPa and ow = 50 MPa as shown in the figure. %3D = 50 MPa %3D O = 30 MPa XX ple The Young's modulus of the material is 2 x 1011 N/m2 and the Poisson's ratio is 0.3. If o is negligibly small and assumed to be zero, then the strain Ezz isarrow_forward
- At an axial load of 22 kN, a 15-mm-thick × 50-mm-wide polyimide polymer bar elongates 5.7 mm while the bar width contracts 0.15 mm. The bar is 245-mm long. At the 22-kN load, the stress in the polymer bar is less than its proportional limit. Determine Poisson’s ratio.arrow_forwardAt an axial load of 22 kN, a 45-mm-wide by 15-mm-thick polyimide polymer bar elongates 2.8 mm while the bar width contracts 0.25 mm. The bar is 190 mm long. At the 22-kN load, the stress in the polymer bar is less than its proportional limit. Determine (a) the modulus of elasticity. (b) Poisson's ratio. (c) the change in the bar thicknessarrow_forwardA metal sample on a tension in the test ,296MPa , a tensile true strain 0.08, and true stress 356 MPa when the strain is 0.27. Determine the strength coefficient and strain hardening exponent in the flow curve equation.arrow_forward
- 1. Calculate the strain at the centroid of the tension steel in single layer if the effective depth is 250 mm and the depth of neutral axis is 100 mm. answer: 0.0045 2. Calculate the strain at extreme layer of steel if fy=415 MPa and the strength reduction factor is 0.80. answer: 0.0038arrow_forwardQ.3. (30%) A circular aluminum tube subjected to T pure torsion by torques T has an outer radius r2 equal to 2 times the inner radius r1. (a) If the maximum shear strain in the tube is measured as 500x10-6 rad, what is the shear strain y1 at the inner surface? (b) If the maximum allowable rate of twist (0) is 0.15°/m and the maximum shear strain is to be kept at 500x10-6 rad by adjusting the torque T, what is the minimum required outer radius (r2 )min?arrow_forwardAt an axial load of 22 kN, a 15-mm-thick x 35-mm-wide polyimide polymer bar elongates 4.2 mm while the bar width contracts 0.25 mm. The bar is 215-mm long. At the 22-kN load, the stress in the polymer bar is less than its proportional limit. Determine Poisson's ratio. O 0.366 O 0.336 EBA O 0.473 O 0.229 O 0.427arrow_forward
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