Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Textbook Question
Chapter 9, Problem 17QP
Given the following mRNA, write the double-stranded DNA segment that served as the template. Indicate both the 5′ and the 3′ ends of both DNA strands. Also write out the tRNA anticodons and the amino acid sequence of the protein encoded by the mRNA message.
DNA:
mRNA: 5′-CCGCAUGUUCAGUGGGCGUAAACACUGA-3′
protein:
tRNA:
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For each of the following items, fill in either the DNA strand, the MRNA codons, the tRNA anticodons, or the
amino acid sequence that have been left blank. If several sequences might work, choose only one.
Furthermore, circle the start and the stop codons of each mRNA sequence.
1.
DNA (3'-5')
ACG
TAC
GGC
CGG
TTA
AAG
CAT
ACT
TTC
TTG
MRNA
TRNA
Amino Acid
2.
DNA (3'-5')
MRNA
AUG
ACU
AGC
UGG
GGG
UAU
UAC
UUU
UAG
AAA
TRNA
Amino Acid
3.
DNA (3'-5')
MRNA
TRNA
GCU
CCU
UAC
CAC
ССС
CGU
AUG
GCU
GGG
AUC
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Amino Acid
Consider the following DNA sequence, which codes for a short polypeptide:
5'-ATGGGCTTAGCGTAGGTTAGT-3'
Determine the mRNA transcript of this sequence. You have to write these sequences from the 5' end to the 3' end and indicate those ends as shown in the original sequence in order to get the full mark.
How many amino acids will make up this polypeptide?
Determine the first four anticodons that will be used in order to translate this sequence.
Chapter 9 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 9.6 - Antibiotics and Protein Synthesis Antibiotics are...Ch. 9.6 - Antibiotics and Protein Synthesis Antibiotics are...Ch. 9 - There have been recurring cases of mad-cow disease...Ch. 9 - There have been recurring cases of mad-cow disease...Ch. 9 - There have been recurring cases of mad-cow disease...Ch. 9 - The Link Between Genes and proteins The genetic...Ch. 9 - Define replication, transcription, and...Ch. 9 - If the genetic code used 4 bases at a time, how...Ch. 9 - If the genetic code uses triplets, how many...Ch. 9 - What is the start codon? What are the stop codons?...
Ch. 9 - Is an entire chromosome made into an mRNA during...Ch. 9 - The promoter and terminator regions of genes are...Ch. 9 - The following segment of DNA codes for a protein....Ch. 9 - What are the three modifications made to pre-mRNA...Ch. 9 - The pre-mRNA transcript and protein made by...Ch. 9 - Briefly describe the function of the following in...Ch. 9 - Prob. 12QPCh. 9 - Determine the percent of the following gene that...Ch. 9 - How many kilobases of the DNA strand below will...Ch. 9 - Prob. 15QPCh. 9 - Given the following tRNA anticodon sequence,...Ch. 9 - Given the following mRNA, write the...Ch. 9 - The following is a portion of a protein:...Ch. 9 - Below is the structure of glycine. Draw a...Ch. 9 - Indicate in which category, transcription or...Ch. 9 - Prob. 21QPCh. 9 - Polypeptide folding is often mediated by other...Ch. 9 - Do mutations in DNA alter proteins all the time?Ch. 9 - a. Can a mutation change a proteins tertiary...
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- Consider the mRNA sequence below. Assume that the following mRNA segment has been translated. 5'-GCAAGUCUUAAU-3' Note for numbers 1 and 2: Use the three-letter abbreviation of amino acid; separate amino acids with a hyphen: do not include the stop codon. Example: ala-cys-glu 1. Using the table of the genetic code, determine the sequence of amino acids. ala-ser-leu-asn 2. If mutation occurs by substitution of the 6th nucleotide with adenosine-5'- monophosphate, what is the resulting amino acid sequence? 3. What type of mutation occurred? Choose from same sense, missense and non-sense.arrow_forwardUse a codon chart determine the amino acid sequence. Remember to read through the strand and ONLY start after the promoter and STOP when it tells you to stop. Follow example below: Example: DNA AGA TATA TAC CTC CGG TGG GTG CTT GTC TGT ATC CTT CTC AGT ATC MRNA O protein AUG GAG GCC ACC CAC GAA CAG ACA UAG GAA GAG UCA UAG start-glu-ala-thre-hist - asp-glu-threo-stop met DNA CCT ATA TAC ACA CGG AGG GTA CGC TAT TCT ATG ATT ACA CGG TTG CGA TCC ATA ATC mRNA DGGA UAU) AUG uGul Gcc nccl cAul GCol protein ly Tur MeT cys AlA ser HIJ Ala 2 3 4 DNA AGA ACT ATA TAC CTC TTA ACA CTC TAA AGA CCA GCA CTC CGA TGA ACT GGA GCA mRNA protein DNA TAT ATAC CTT GGG GAA TAT ACA CGC TGG CTT CGA TGA ATC CGT ACG GTA CTC GCC ATC mRNA protein D DNA TAA ACT ATA TAC CTA GCT TAG ATC TAA TTA CCC ATC mRNA protein Auu UGA UAU AGU GAUCGA AUC MAG Auu AAU leu Stop. TRY-Met-Asp- ARG-Isle-Stop-Ile. Asn DNA CTA TTT ATA TAC TAG AGC GAA TAG AAA CTT ATC ATC mRNA protein D DNA CAT ATA TAC CTT AGT TAT CCA TTG ACT CGA ATT GTG CGC TTG…arrow_forwardConsider the mRNA sequence below. Assume that the following mRNA segment has been translated. 5’-UACCGAAUGUCU-3’ Note for letters a and b: Use the three-letter abbreviation of amino acid; separate amino acids with a hyphen: do not include the stop codon. Example: ala-cys-glu a. Using the table of the genetic code, determine the sequence of amino acids. b. If mutation occurs by substitution of the 12th nucleotide with cytidine-5’-monophosphate, what is the resulting amino acid sequence? c. What type of mutation occurred? Choose from same sense, missense and non-sense.arrow_forward
- The sequence below is of the DNA duplex for a gene in which transcription begins with the nucleotide highlighted by the arrow. If the upper strand shown is the template strand, write the sequence you expect for the mRNA transcribed from this gene. Please write 5' to 3'. 5'-[x]-3' 5'-TACGTGACGGTAATACTAGC-3' 3'-ATGCACTGCCATTATGATCG-5'arrow_forwardGiven the DNA sequence below: 5’-ACATGTGTACAGGCTTTGTCTGAATGGCTT-3’ 3’-TGTACACATGTCCGAAACAGACTTACCGAA-5’ Transcribe the gene. (Write the primary structure of the mRNA that will be produced.)arrow_forwardBelow is the 5’–3’ strand of a double-stranded DNA molecule with the following nucleotide sequences:5’ C C T A T G C A G T G G C C A T A T T C C A A A G C A T A G C 3’1. If the above DNA strand is the coding (sense) strand and the DNA molecule is transcribed, what is the correct nucleotide sequence and direction of the RNA formed after transcription?arrow_forward
- Below is the 5’–3’ strand of a double-stranded DNA molecule with the following nucleotide sequences:5’ C C T A T G C A G T G G C C A T A T T C C A A A G C A T A G C 3’ 1. If the above DNA strand is the template (antisense) strand and the DNA molecule is transcribed, what is the correct nucleotide sequence and direction of the RNA formed after transcription?arrow_forwardChoose one of the strands and transcribe the strand. Show the steps (with proper label) and do a post-transcriptional processing. Once the transcript is made, do the process of translation. Again follow the steps. Use the Wobble Table for reference. DNA strand: 5'-TCGAAACGAGCTGCAGCTAGCTAGCTACGTCAGCTGCATCTGTCTACGAGCGACTGTCTAGCATAGCGTAGCTGC-3 'Complementary strand: 3'-TCGAAACGAGCTGCAGCTAGCTAGCTACGTCAGCTGCATCTGTCTACGAGCGACTGTCTAGCATAGCGTAGCTGC-5'arrow_forwardGiven the following DNA sequence of the template strand for a given gene: 5' TTTCCGTCTCAGGGCTGAAAATGTTTGCTCATCGAACGC3' Part A ) Write the mRNA that will be transcribed from the DNA sequence above (be sure to label the 5' and 3' ends). Part B ) Use the genetic code to write the peptide sequence translated in a cell from the mRNA in part A. Please use the 3 letter abbreviation for each amino acid. Part C: How would the peptide synthesized in a cell be different if the mRNA was translated in vitro (i.e. not in the cell)?arrow_forward
- The DNA sequence below is transcribed from left to right (the partner/coding strand is shown). Using this sequence, write the sequence of the polypeptide that results from this gene. Be sure to appropriately label the ends of the molecule. 5'-ATGCACGGCGACTAG-3' Second letter A UAU Tyr UAC First letter U A G U UUU1 UUC UUA LOU Leu CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu AUU AUC lle AUA AUG Met Val C UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala CAU His CAC CAA CAG Gin AAU Asn AAC AAA 1 Lys AAG LYS G {}a UAA Stop UGA Stop A UAG Stop UGG Trp GAU 1 GAC Asp GAA GIU Glu GAGJ UGU UGC CGU CGC CGA CGG AGU AGC AGA AGG Cys GGU GGC GGA GGG Arg Ser Arg DOA DOA DOA DUTO Third letter Glyarrow_forwardYou may wish to consult the genetic code above to answer the following question. A mutation has changed a portion of a protein coding gene that encodes a messenger RNA sequence. The original messenger RNA sequence is 5-AUGCCCAGAGCU-3' Which mutation is a nonsynonymous (missense) mutation that changes a single amino acid in the encoded protein? O 5-AUGCCCAGGGCC-3' O 5'-AUGCCCUGAGCU-3' O 5'-AUGCCCACAGCU-3 5'-AUGCCCCAGAGCU-3arrow_forwardFor the messenger RNA sequence below, find the beginning of the amino acid coding sequence and translate the sequence using the genetic code provided below. 5' - AAUUAUGGGCAAUAUGCCGGGCcGGUUAAGCG - 3' Second Letter A UGU cys u UGC Phe UCU UU U UUC UUA UAU Tyr Ser UAC UAA UAG Leu UCA Stop UGA Stop UUG UCG Stop UGG Trp CUU CU CAU His CGU c cuc Leu ccc ССА CCG Pro CÁC CAA CAG CGC CGA CGG Arg CUA CUG Gin 1st 3rd letter Ser u letter AUU ACU AAU AAC AAA AAG Asn A AUC AUA AUG lle ACC ACA AGU AGC AGA AGG Thr Lys Arg Met ACG GUU G GUC GUA GUG GCU GAU GAC GAA Asp GGU Val GCC Ala GGC Gly GCA GGA Glu GCG GAG GGG Garrow_forward
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