An Introduction to Thermal Physics
1st Edition
ISBN: 9780201380279
Author: Daniel V. Schroeder
Publisher: Addison Wesley
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Question
Chapter 7.4, Problem 56P
(a)
To determine
The solar constant for Venus and the average temperature of the surface of Venus.
(b)
To determine
The temperature of Venus considering the reflectivity of the clouds.
(c)
To determine
The temperature of Venus.
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The planet Venus is different from the earth in several respects. First, it is only 70% as far from the sun. Second, its thick clouds reflect 77% of all incident sunlight. Finally, its atmosphere is much more opaque to infrared light.
Calculate the solar constant at the location of Venus, and estimate what the average surface temperature of Venus would be if it had no atmosphere and did not reflect any sunlight.
A. The planet Venus is different from the earth in several respects: (a) it is
only 70 % as far from the sun, so the solar constant is 2800 W/m²; (b) its
thick clouds reflect 77% of all incident sunlight and (c) its atmosphere is
much more opaque to infrared light.
B.
(i) Estimate what the average surface temperature of Venus would be if it
had no atmosphere and did not reflect any sunlight.
(ii) Taking into account the reflectivity of the clouds, estimate the surface
temperature.
Use the theory of Earth's energy balance to discuss the greenhouse effect.
Our Sun shines bright with a luminosity of 3.828 x 1026 Watt. Her energy is responsible for many processes and the habitable temperatures on the Earth that make our life possible.
Calculate the amount of energy arriving on the Earth in a single day.
To how many litres of heating oil (energy density: 37.3 x 106 J/litre) is this equivalent?
The Earth reflects 30% of this energy: Determine the temperature on Earth’s surface.
What other factors should be considered to get an even more precise temperature estimate?
Note: The Earth’s radius is 6370 km; the Sun’s radius is 696 x 103 km; 1 AU is 1.495 x 108 km.
Chapter 7 Solutions
An Introduction to Thermal Physics
Ch. 7.1 - Prob. 1PCh. 7.1 - Prob. 3PCh. 7.1 - Prob. 4PCh. 7.1 - Show that when a system is in thermal and...Ch. 7.1 - Prob. 7PCh. 7.2 - Prob. 8PCh. 7.2 - Prob. 9PCh. 7.2 - Prob. 11PCh. 7.2 - Prob. 12PCh. 7.2 - Prob. 13P
Ch. 7.2 - Prob. 14PCh. 7.2 - Prob. 15PCh. 7.2 - Prob. 16PCh. 7.2 - Prob. 17PCh. 7.2 - Prob. 18PCh. 7.3 - Prob. 19PCh. 7.3 - Prob. 20PCh. 7.3 - Prob. 21PCh. 7.3 - Prob. 22PCh. 7.3 - Prob. 24PCh. 7.3 - Prob. 25PCh. 7.3 - Prob. 26PCh. 7.3 - Prob. 29PCh. 7.3 - Prob. 32PCh. 7.3 - Prob. 33PCh. 7.3 - Prob. 34PCh. 7.4 - Prob. 37PCh. 7.4 - Prob. 38PCh. 7.4 - Prob. 39PCh. 7.4 - Prob. 40PCh. 7.4 - Prob. 41PCh. 7.4 - Prob. 42PCh. 7.4 - Prob. 43PCh. 7.4 - Prob. 44PCh. 7.4 - Prob. 45PCh. 7.4 - Prob. 46PCh. 7.4 - Prob. 47PCh. 7.4 - Prob. 48PCh. 7.4 - Prob. 49PCh. 7.4 - Prob. 50PCh. 7.4 - Prob. 51PCh. 7.4 - Prob. 52PCh. 7.4 - Prob. 53PCh. 7.4 - Prob. 54PCh. 7.4 - Prob. 55PCh. 7.4 - Prob. 56PCh. 7.5 - Prob. 57PCh. 7.5 - Prob. 58PCh. 7.5 - Prob. 59PCh. 7.5 - Prob. 60PCh. 7.5 - The heat capacity of liquid 4He below 0.6 K is...Ch. 7.5 - Prob. 62PCh. 7.5 - Prob. 63PCh. 7.5 - Prob. 64PCh. 7.6 - Prob. 65PCh. 7.6 - Prob. 66PCh. 7.6 - Prob. 67PCh. 7.6 - Prob. 68PCh. 7.6 - If you have a computer system that can do...Ch. 7.6 - Prob. 70PCh. 7.6 - Prob. 71PCh. 7.6 - Prob. 72PCh. 7.6 - Prob. 73PCh. 7.6 - Prob. 75P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
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- The next four questions use this description. Our Sun has a peak emission wavelength of about 500 nm and a radius of about 700,000 km. Your dark-adapted eye has a pupil diameter of about 7 mm and can detect light intensity down to about 1.5 x 10-11 W/m2. Assume the emissivity of the Sun is equal to 1. First, given these numbers, what is the surface temperature of the Sun in Kelvin to 3 significant digits? What is the power output of the Sun in moles of watts? (in other words, take the number of watts and divide it by Avogadro's number) Assuming that all of the Sun's power is given off as 500 nm photons*, how many photons are given off by the Sun every second? Report your answer to the nearest power of 10 (e.g. if you got 7 x 1024, give your answer as 25).arrow_forwardThe Stefan-Boltzmann Law says that the light radiated from a perfect radiator ("blackbody") is proportional to the temperature raised to the fourth power: where σ is the Stefan-Boltzmann constrant (σ = 5.67 x 10-8 in MKS units) In equilibrium, F coming in equals F going out. At Mars' distance from the Sun, F coming in is 153 in MKS units. What is the blackbody temperature for Mars at a distance of 1.524 AU from the Sun?arrow_forwardUse the value of the solar energy flux on Earth to determine the radius of the Sun. Assuming that the Sun's temperature is 5780 K and that its emissivity is 1, find its radius in kilometers. Neglect the temperature of the environment.arrow_forward
- a) Calculate the escape velocity for hydrogen atoms from the surface (the photosphere) of our Sun. The Sun has a mass of 1.99×1030 kg and a radius of 6.96×108 m. b) If the velocity in (a) were the root-mean-squared of the hydrogen atoms in the Sun, what would the temperature of the photosphere have to be?arrow_forwardThe average temperature of the atmosphere has increased by 0.4°C over the last thirty years. Estimate how much energy has gone into warming up the planet in this way. Keep in mind that the atmosphere has a mass of 5 × 1018kg, and the specific heat capacity of air is about 1 Jg−1K−1. How do we get to this answer (2×1021J)arrow_forwardThe planet Venus is different from the earth in several respects. First, it is only 70% as far from the sun. Second, its thick clouds reflect 77% of all incident sunlight. Finally, its atmosphere is much more opaque to infrared light. Estimate the surface temperature again, taking the reflectivity of the clouds into account.arrow_forward
- The following heat transfer formula quantifies the radiation emitted from the Sun: P = eoA(T4 – T?) Equation 5 where: P= radiated power (Watts) e = emissivity (=1 for ideal radiator; unitless) o = Stefan-Boltzmann constant = 5.67x10-8 W/m2-K+ A = radiating area (m²) T= temperature of radiator (Kelvin) Tc = temperature of surroundings (Kelvin) Q3 Using the following values, together with equation 5, calculate the power emitted by the Sun. sun's surface temperature = 5780 K temperature of the environment that the Sun is located in = 4 K emissivity of the Sun = 1 radius of the Sun = 695,700,000 m Stephen-Boltzmann constant o = 5.67 x 10-8 W/m2-K4 Show your work below-you may use the equation editor or insert a picture of your handwritten work.arrow_forwardProxima Centauri, the nearest star to our Sun, has a surface temperature of 2,768.85 °C. What is its total intensity emitted? O 4.3 MW per square meter. O 4.9 MW per square meter. O 5.2 MW per square meter. O 5.7 MW per square meter. O 6.4 MW per square meter.arrow_forwardThe amount of radiant energy emitted by a surface is given by q = ɛ0 AT+ where q represents the rate of thermal energy (per unit time) emitted by the surface in watts; e = the emissivity of the surface 0<ɛ<1 and is unitless o = Stefan-Boltzman constant (o = 5.67×10% ) A represents the area of the surface in m² Ty = surface temperature of the object expressed in kelvin What are the appropriate units for o if the equation is to be homogeneous in units?arrow_forward
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