Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 7, Problem 7.4P
To determine
The yield strength of titanium if grain size is reduced to
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Students have asked these similar questions
The strength of titanium is 448.16 MPa when the grain size is 17.02 μm and565.4 MPawhen the grain size is0.8μm. What average grain size (in nm) is required to achieve a strength of approximately 839 MPa?
In an engineering application, the material is a strip of iron with a fixed crystallographic structure subject to a tensile load during operation. The part
failed (yielded) during operation and needs to be replaced with a component with better properties. You are told that two other iron strips had failed
at yield stresses of 110 and 120 MPa, with grain sizes of 30 microns and 25 microns respectively. The current strip has a grain size of 20 microns. The
diameter of the rod is 1 mm and the load applied is 100 N. What is the yield stress of the new part C and would you recommend it for operation?
Select one:
Oa. 133.5 MPa, yes
O b.
OC.
Od
Oe.
120.5 MPa, no
129.5, yes
140.5, no
123.5 MPa, yes
If it is constrained between two supports A and B and is stress-free at 20 ℃, what would be the stress in the two materials when it is heated to 70 ℃,
For Steel: Es = 210 GPa, Coefficient of expansion = 12x10^6/℃.
For Brass: Eb = 105 GPa, Coefficient of expansion = 19x10^-6/℃
Chapter 7 Solutions
Materials Science And Engineering Properties
Ch. 7 - Prob. 1CQCh. 7 - Prob. 2CQCh. 7 - Prob. 3CQCh. 7 - Prob. 4CQCh. 7 - Prob. 5CQCh. 7 - Prob. 6CQCh. 7 - Prob. 7CQCh. 7 - Prob. 8CQCh. 7 - Prob. 9CQCh. 7 - Prob. 10CQ
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- Given your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a test piece or component and why? a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder C. Polishing to reduce surface defects Od. Increasing its volume, to give a larger cross sectional area Oe. Increasing the grain size so there are less grain boundaries to initiate failurearrow_forwardA copper rod is deformed using a uniaxial tensile force of 16000 N. Deformation continues until sufficient strain hardening has occurred such that the applied force is too small to allow further deformation. After deformation, the rod has a diameter of 0.01 m and a length of 1.5 m. Assume that copper follows the strain hardening lawwith K of 310 MPa and n=0.54 Please calculate the true strain after the deformation ?arrow_forwardNarrow bars of aluminum are bonded to the two sides of a thick steel plate as shown. Initially, at T₁ = 70°F, all stresses are zero. Knowing that the temperature will be slowly raised to T₂ and then reduced to T₁, determine (a) the highest temperature T₂ that does not result in residual stresses, (b) the temperature T₂ that will result in a residual stress in the aluminum equal to 58 ksi. Assume aa = 12.8 x 10-6/°F for the aluminum and a = 6.5 × 10-6/°F for the steel. Further assume that the aluminum is elastoplastic with E = 10.9 × 106 psi and ay = 58 ksi. (Hint: Neglect the small stresses in the plate.) Fig. P2.121arrow_forward
- A cylindrical specimen of cold-worked steel has a Brinell hardness of 240. If the specimen remained cylindrical during deformation and its original radius was 11.8 mm, determine its radius after deformation. For steel, the dependence of tensile strength on percent cold work is shown in Animated Figure 7.19b. i mmarrow_forwardIn a tensile test a metal begins to neck at a true strain = 0.28 with a corresponding true stress = 345.0 MPa. Without knowing any more about the test, can you estimate the strength coefficient and the strain hardening exponent in the flow curve equation?arrow_forwardA batch of casted mild steel has a modulus of elasticity of 200 GPa and a yield strength of 250 MPa. Calculate for its modulus of resilience. After cold working the steel, the yield strength increases to 310 MPa. Calculate for the percent reduction in the average grain diameter given σo = 70 MPa and k = 0.74.arrow_forward
- After an inspection it is found that a structural ceramic part has no flaws greater than 100 micrometers in size, calculate the maximum service stress (in MPa) available with SiC. Assume that Y= 1arrow_forwardA mild steel specimen is under uniaxial tensile stress. Young's modulus and yield stress for mild steel are 2 x 105 MPa and 250 MPa respectively. The maximum amount of strain energy per unit volume that can be stored in this specimen without permanent set isarrow_forwardDraw a tensile stress-strain curve for a typical semi-crystalline polymer such as LLDPE, and define the three main regions on the curve.arrow_forward
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