Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 7, Problem 7.13P
To determine
The elastic modulus, tensile strength and elongation to failure of proposed blend.
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The following figure shows the tensile stress-strain curve for a plain-carbon steel.
600
80
500
MPa
600
10 psi
60
80
400
400
60-
300
40
40
200
200
20
20
100
0.005
0.05
0.10
0.15
Strain
(a) What is this alloy's tensile strength?
MPа
(b) What is its modulus of elasticity?
GPa
(c) What is the yield strength?
i
MPa
Stress (MPa)
Stress (10 psi)
An extruded polymer bear is subjected to a bending moment M. The length of the bear is L = 500 mm. The cross-sectional dimensions
of the bear are b₁ = 39 mm, d₁ = 95 mm, b₂ = 23 mm, d₂ = 23 mm, and a = 8 mm. For this material, the allowable tensile bending stress is
18 MPa, and the allowable compressive bending stress is 9 MPa. Determine the largest moment M that can be applied as shown to the
beam.
M
A
Answer:
M =
L
B
N-m
↓
a
d₂
➡AK
b₂
b₁
yak
An aluminum alloy bar with a radius of 7 mm was subjected to tension until fracture and produced results shown in Table P4 a. Using a spreadsheet program, plot the stress–strain relationship. b. Calculate the modulus of elasticity of the aluminum alloy. c. Determine the proportional limit. d. What is the maximum load if the stress in the bar is not to exceed the proportional limit? e. Determine the 0.2% offset yield strength. f. Determine the tensile strength. g. Determine the percent of elongation at failure.
Chapter 7 Solutions
Materials Science And Engineering Properties
Ch. 7 - Prob. 1CQCh. 7 - Prob. 2CQCh. 7 - Prob. 3CQCh. 7 - Prob. 4CQCh. 7 - Prob. 5CQCh. 7 - Prob. 6CQCh. 7 - Prob. 7CQCh. 7 - Prob. 8CQCh. 7 - Prob. 9CQCh. 7 - Prob. 10CQ
Ch. 7 - Prob. 11CQCh. 7 - Prob. 12CQCh. 7 - Prob. 13CQCh. 7 - Prob. 14CQCh. 7 - Prob. 15CQCh. 7 - Prob. 16CQCh. 7 - Prob. 17CQCh. 7 - Prob. 18CQCh. 7 - Prob. 19CQCh. 7 - Prob. 20CQCh. 7 - Prob. 21CQCh. 7 - Prob. 22CQCh. 7 - Prob. 23CQCh. 7 - Prob. 24CQCh. 7 - Prob. 25CQCh. 7 - Prob. 26CQCh. 7 - Prob. 27CQCh. 7 - Prob. 28CQCh. 7 - Prob. 29CQCh. 7 - Prob. 30CQCh. 7 - Prob. 31CQCh. 7 - Prob. 32CQCh. 7 - Prob. 33CQCh. 7 - Prob. 34CQCh. 7 - Prob. 35CQCh. 7 - Prob. 36CQCh. 7 - Prob. 37CQCh. 7 - Prob. 38CQCh. 7 - Prob. 39CQCh. 7 - Prob. 40CQCh. 7 - Prob. 41CQCh. 7 - Prob. 42CQCh. 7 - Prob. 43CQCh. 7 - Prob. 44CQCh. 7 - Prob. 45CQCh. 7 - Prob. 46CQCh. 7 - Prob. 47CQCh. 7 - Prob. 48CQCh. 7 - Prob. 49CQCh. 7 - Prob. 50CQCh. 7 - Prob. 51CQCh. 7 - Prob. 52CQCh. 7 - Prob. 1DRQCh. 7 - Prob. 2DRQCh. 7 - Prob. 3DRQCh. 7 - Prob. 4DRQCh. 7 - Prob. 5DRQCh. 7 - Prob. 6DRQCh. 7 - Prob. 7DRQCh. 7 - Prob. 8DRQCh. 7 - Prob. 1ETSQCh. 7 - Prob. 2ETSQCh. 7 - Prob. 3ETSQCh. 7 - Prob. 4ETSQCh. 7 - Prob. 5ETSQCh. 7 - Prob. 6ETSQCh. 7 - Prob. 7ETSQCh. 7 - Prob. 8ETSQCh. 7 - Prob. 9ETSQCh. 7 - Prob. 7.1PCh. 7 - Prob. 7.2PCh. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10PCh. 7 - Prob. 7.11PCh. 7 - Prob. 7.13P
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- 1. The tensile strength vs. temperature curves of aluminum are plotted below. Explain the meaning of these two curves. 400 Ultimate strength 300 Yield strength 200 100 -200 -150 -100 -50 50 100 150 200 250 Temperature, °C Strength, kPaarrow_forwardQuestion No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness I. Which metal is more ductile? Why? 900 -Metal A E 600 Metal B 300 0.00 a02 004 a.06 0.08 0.10 0.12 014 Strain, matm FIGURE P1.16 Strees, MPaarrow_forwardIf the modulus of elasticity for a given material is twice its modulus of rigidity, then bulk modulus is equal to (a) 2C (6) 3С 20 (c) 3 3C (d) 2 -arrow_forward
- Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness f. Which metal is more ductile? Why? 000 -Metal A S 600 -Metal B 300 0.00 a.02 0.04 0.06 0.08 0.10 0.12 0.14 Strain, mim FIGURE P1.16 Stress, MPaarrow_forwardThe stress-strain diagram for a steel alloy having an original diameter of 0.5 in. and a gage length of 2 in. is given in the figure. If the specimen is loaded until it is stressed to 70 ksi, determine the approximate amount of elastic recovery and the increase in the gage length after it is unloaded. o (ksi) 80 70 60 50 40 30 20 10 e (in./in.) 0 04 0.08 0.12 0.16 0.20 0.24 0.28 0 0005 0.0010.0015 0.002 0.0025 0.0030.0035arrow_forwardA 100 mm x 100 mm x 100 mm cube made with glass polymers in the y- direction is subjected to a tensile load of 100 kN along the y-direction. However, the cube is constrained against deformation in the x and z directions. Given the following properties: Ex = 20 GPa Ey = 50 GPa Ez = 20 GPa Vxy = 0.25 Vxz = 0.5 Vyz = 0.25 (a) Compute for the change in length of the cube in the y-direction and; (b) Determine the stresses, ox,Oy,Oz•arrow_forward
- (b) (i) A tensile test specimen made from 0.4% C steel has a circular cross section of diameter d mm and a gauge length of 25 mm. When a load of 4500 N is applied during the test, the gauge length of the specimen extends to 25.02 mm. If the Young's Modulus of the steel is 199 GPa, calculate the diameter of the tensile test specimen used. 4arrow_forwardQuestion-5 The following engineering stress-strain data were obtained from the tensile test for a 0.2% plain carbon steel. (a) Plot the engineering stress-strain curve for these data. (b) Determine the 0.2 percent offset yield stress for this steel. (c) Determine the tensile elastic modulus of this steel. (d) Determine the ultimate tensile strength of the alloy. (e) Determine the percent elongation at fracture. Engineering stress (ksi) 0 30 55 60 68 72 74 75 Engineering strain (in./in.) 0 0.001 0.002 0.005 0.01 0.02 0.04 0.06 Engineering stress (ksi) 76 75 73 69 65 56 51 Engineering strain (in./in.) 0.08 0.10 0.12 0.14 0.16 0.18 (Fracture) 0.19 Question-6 A 20-cm-long rod with a diameter of 0.250 cm is loaded with a 5000 N weight. If the diameter decreases to 0.210 cm, determine (a) the engineering stress and strain at this load and (b) the true stress and strain at this load.arrow_forwardTesting a round steel alloy bar with a diameter of 15 mm and a gauge length of 250 mm produced the stress-strain relationship shown in Figure P3.28. Determine a. the elastic modulus b. the proportional limit c. the yield strength at a strain offset of 0.002 d. the tensile strength e. the magnitude of the load required to produce an increase in length of 0.38 mm f. the final deformation, if the specimen is unloaded after being strained by the amount specified in (e) g. In designing a typical structure made of this material, would you expect the stress applied in (e) reasonable? Why? 750 500 250 0.01 0.02 0.03 0.04 Strain, m/m FIGURE P3.28 Stress, MPaarrow_forward
- An elastoplastic material with strain hardening has the stress–strain relationship shown in Figure . The yield point corresponds to 600 MPa stress and 0.003 m/m strain.a. If a bar made of this material is subjected to a stress of 650 MPa and then released, what is the permanent strain?b. What is the percent increase in yield strength that is gained by the strain hardening shown in part (a)?c. After strain hardening, if the material is subjected to a stress of 625 MPa,how much strain is obtained? Is this strain elastic, permanent, or a combination of both?arrow_forwardThe assembly shown is composed of a steel shell and an aluminum core that has been welded to a rigid plate. The gap between the plate and the steel shell is 1- mm. If the assembly's temperature is reduced by 180°C, determine (a) the final axial stresses in each material and (b) the deflection of the rigid bar. To support your response, draw a deformation diagram with appropriate labels. Use the following properties: Aluminum core Steel shell Diameters (mm) d = 15 mm do = 30 mm d₁ = 20 mm E (GPa) 70 200 2 m a (/°C) 22 x 10-6 12 x 10-6arrow_forwardThe assembly is composed of a steel shell and an aluminum core that has been welded to a rigid plate. The gap between the plate and the aluminum is initially 1- mm. If the assembly's temperature is reduced by 180°C, determine (a) the final axial stresses in each material and (b) the deflection of the rigid bar. To support your response, draw a deformation diagram with appropriate labels. Use the following properties: Aluminum core Steel shell Diameters (mm) d = 15 mm do = 30 mm d₁ = 20 mm E (GPa) 70 200 2 m a (/°C) 22 x 10-6 12 x 10-6arrow_forward
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