CHEMISTRY-TEXT
CHEMISTRY-TEXT
8th Edition
ISBN: 9780134856230
Author: Robinson
Publisher: PEARSON
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Chapter 6, Problem 6.32CP
Interpretation Introduction

Interpretation:

Born-Haber cycle for formation of LiCl(s) from its elements should be drawn.

Concept introduction:

The pictorial representation of formation of ionic solids from its constituent elements is known as Born-Haber cycle. Following are the steps required to draw Born-Haber cycle of any ionic compound:

Step 1: Solid metal is converted into gaseous isolated atoms. It takes place by process called sublimation.

Step 2: Gaseous molecules are broken down into separate atoms. Energy is supplied to break molecules apart and this is called bond dissociation energy.

Step 3: Isolated metal atoms are converted into respective cations with the help of ionization energy.

Step 4: Anions are formed from gaseous atoms with the help of electron affinity.

Step 5: Ionic compound is formed by the combination of cation and anion. Energy is released in this process.

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Calculate the lattice energy for LiBr(s) given the following: sublimation energy for Li(s) +166 kJ/mol ΔHf for Br(g) +97 kJ/mol first ionization energy of Li(g) +520. kJ/mol electron affinity of Br(g) –325 kJ/mol enthalpy of formation of LiBr(s) –351 kJ/mol
Calculate the lattice formation enthalpy (lattice energy) of the lattice for LiF(s), in kJ/mol, given the following information: Sublimation energy for Li(s) 161 kJ/mol AH: for F(g) 77 kJ/mol First ionization 520 kJ/mol energy of Li(g) Electron affinity of F(g) -328 kJ/mol Enthalpy of formation of LİF(s) -617 kJ/mol kJ/mol 1 3 4 6. C 7 8 +/- х 100 Tap here or pull up for additional resources LO 00
8. Given the following information: Li(s) HI(g) → H(g) + I(g) enthalpy of sublimation of Li(s) = 166 kJ/mol bond energy of HI = 295 kJ/mol Li(g) Li(g) → Li"(g) + e ionization energy of Li(g)= 520. kJ/mol I(g) + e — Г(g) electron affinity of I(g) = -295 kJ/mol Li"(g) + I(g) → LiI(s) lattice energy of LiI(s) = -737 kJ/mol H2(g) → 2H(g) Calculate the change in enthalpy for: bond energy of H2 = 432 kJ/mol 2Li(s) + 2HI(g) –→ H2(g) + 2LİI(s) a. 330 kJ b. –534 kJ c. -483 kJ d. -984 kJ e. none of these

Chapter 6 Solutions

CHEMISTRY-TEXT

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