CHEMISTRY-TEXT
CHEMISTRY-TEXT
8th Edition
ISBN: 9780134856230
Author: Robinson
Publisher: PEARSON
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Chapter 6, Problem 6.96SP

Use the following information plus the data given in Tables6.2 and 6.3 to calculate the second electron affinity, E ea2 , of oxygen. Is the O 2 ion stable in the gas phase? Why is its table in solid MgO?
Heat of sublimation for Mg ( s ) = + 147 . 7 kJ / mol Bond dissociation energy for O 2 ( g ) = + 498 . 4 kJ / mol E ea1 for O ( g ) = 141 .0  kJ / mol Net energy change for formation of MgO ( s )  from its elements = 6 0 1 . 7 kJ / mol

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Calculate the second ionization energy of the metal M (AHion2 in kJ/mol) using the following data: Lattice enthalpy of MO(s), AH = -2278 kJ/mol Bond dissociation enthalpy of O2(g) = +498 kJ/mol First electron affinity of O = -141 kJ/mol Second electron affinity of O = +744 kJ/mol Enthalpy of sublimation of M = + 125 kJ/mol First ionization energy of M = + 309 kJ/mol Standard enthalpy of formation of MO(s), AH = -341 kJ/mol
Calculate the second ionization energy of the metal M (AH¡on2 in kJ/mol) using the following data: Lattice enthalpy of MO(s), AH = -2278 kJ/mol Bond dissociation enthalpy of O2(g) = +498 kJ/mol %3D First electron affinity of O = -141 kJ/mol Second electron affinity of O = +744 kJ/mol Enthalpy of sublimation of M = + 125 kJ/mol First ionization energy of M = + 309 kJ/mol Standard enthalpy of formation of MO(s), AHf = -341 kJ/mol
Consider an ionic compound, MX3, composed of generic metal M and generic gaseous halogen X. The enthalpy of formation of MX3 is ΔHf∘=−965 kJ/mol. The enthalpy of sublimation of M is ΔHsub=123 kJ/mol. The first, second, and third ionization energies of M are IE1=557 kJ?mol, IE2=1751 kJ/mol, and IE3=2731 kJ/mol. The electron affinity of X is ΔHEA=−339 kJ/mol The bond energy of X2 is BE=235 kJ/mol. Determine the lattice energy of MX3.

Chapter 6 Solutions

CHEMISTRY-TEXT

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