Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 6, Problem 6.13P
To determine
The elastic modulus, upper yield point and lower yield point for 1045 steel.
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Calculate the stress and strain at each force interval. Plot a graph of the stress-strain curve. Estimate the yield point of the steel and note its location on the curve. Estimate the ultimate strength of the steel and note its location on the curve.
In the figure shown below, determine:
1) The final temperature if the normal stress at
aluminium is Oal =
= -90 MPa and the initial
temperature 20°C.
2)
The final length of the aluminium member.
Aluminum
Bronze
A=1800mm2
A=1500mm2
E=105GPA
E=73GPA
a=23.2x10-6/°C
a=21.6x10-6/°C
Gap=0.5mm
0.35m
0.45m
Q2c) Listed in the table below is the tensile
stress-strain data for different grades of steels.
Utilizing the data given answer the three queries
given below.
Material Yield
Tensile Strain at Fracture Elastic
StrengthStrengthFractureStrengthModulus
(MPa)
(MPa)
(MPa)
(GPa)
A
410
1440
0.63
265
410
В
200
220
0.40
105
250
C
815
950
0.25
500
610
D
800
650
0.14
720
210
E
Fractures before yielding
650
550
1) Which will experience the greatest percent
reduction in area? Why?
2) Which is the strongest? Why?
3) Which is the stiffest? Why?
Chapter 6 Solutions
Materials Science And Engineering Properties
Ch. 6 - Prob. 1CQCh. 6 - Prob. 2CQCh. 6 - Prob. 3CQCh. 6 - Prob. 4CQCh. 6 - Prob. 5CQCh. 6 - Prob. 6CQCh. 6 - Prob. 7CQCh. 6 - Prob. 8CQCh. 6 - Prob. 9CQCh. 6 - Prob. 10CQ
Ch. 6 - Prob. 11CQCh. 6 - Prob. 12CQCh. 6 - Prob. 13CQCh. 6 - Prob. 14CQCh. 6 - Prob. 15CQCh. 6 - Prob. 16CQCh. 6 - Prob. 17CQCh. 6 - Prob. 18CQCh. 6 - Prob. 19CQCh. 6 - Prob. 20CQCh. 6 - Prob. 21CQCh. 6 - Prob. 22CQCh. 6 - Prob. 23CQCh. 6 - Prob. 24CQCh. 6 - Prob. 25CQCh. 6 - Prob. 26CQCh. 6 - Prob. 27CQCh. 6 - Prob. 28CQCh. 6 - Prob. 29CQCh. 6 - Prob. 30CQCh. 6 - Prob. 31CQCh. 6 - Prob. 32CQCh. 6 - Prob. 33CQCh. 6 - Prob. 34CQCh. 6 - Prob. 35CQCh. 6 - Prob. 36CQCh. 6 - Prob. 37CQCh. 6 - Prob. 38CQCh. 6 - Prob. 1ETSQCh. 6 - Prob. 2ETSQCh. 6 - Prob. 3ETSQCh. 6 - Prob. 4ETSQCh. 6 - Prob. 5ETSQCh. 6 - Prob. 6ETSQCh. 6 - Prob. 7ETSQCh. 6 - Prob. 8ETSQCh. 6 - Prob. 9ETSQCh. 6 - At the ultimate tensile strength. (a) The true...Ch. 6 - Prob. 11ETSQCh. 6 - Prob. 12ETSQCh. 6 - Prob. 13ETSQCh. 6 - Prob. 14ETSQCh. 6 - Prob. 15ETSQCh. 6 - Prob. 16ETSQCh. 6 - Prob. 6.1PCh. 6 - Prob. 6.2PCh. 6 - Compare the engineering and true secant elastic...Ch. 6 - Prob. 6.4PCh. 6 - Prob. 6.5PCh. 6 - An iron specimen is plastically deformed in shear...Ch. 6 - Prob. 6.7PCh. 6 - Prob. 6.8PCh. 6 - Prob. 6.9PCh. 6 - Prob. 6.10PCh. 6 - Prob. 6.11PCh. 6 - Prob. 6.12PCh. 6 - Prob. 6.13PCh. 6 - Prob. 6.14PCh. 6 - Estimate the elastic and plastic strain at the...Ch. 6 - Prob. 6.16PCh. 6 - Prob. 6.17PCh. 6 - Prob. 6.18PCh. 6 - Prob. 6.19PCh. 6 - Prob. 6.1DPCh. 6 - Prob. 6.2DP
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- An aluminum alloy [E = 70 GPa; v = 0.33; a = 23.0×10-6/°C] bar is subjected to a tensile load P. The bar has a depth of d = 260 mm, a cross-sectional area of A = 14720 mm2, and a length of L = 5.5 m. The initial longitudinal normal strain in the bar is zero. After load P is applied and the temperature of the bar has been increased by AT = 46°C, the longitudinal normal strain is found to be 1680 µɛ. % D Calculate the change in bar depth d after the load P has been applied and the temperature has been increased. L P Answer: Ad = i mmarrow_forward4. A 2.0 m steel is being subjected into a tensile test. At force 30 kN, the length of the steel is now 2.2 m, but after the force has been released, the steel returned to 2.1 m. The state of the steel is at?arrow_forwardA 19-mm reinforcing steel bar and a gauge length of 75 mm was subjected to ten- sion, with the results shown in Table P3.27. Using a computer spreadsheet pro- gram, plot the stress-strain relationship. From the graph, determine the Young's modulus of the steel and the deformation corresponding to a 150-kN load. TABLE P3.27 Load, kN Deformation, mm 54 0.084 163 0.168 284 0.336 330 1.428 366 3.360arrow_forward
- Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness I. Which metal is more ductile? Why? 900 -Metal A E 600 Metal B 300 0.00 a02 004 a.06 0.08 0.10 0.12 014 Strain, matm FIGURE P1.16 Strees, MPaarrow_forwardA steel 0.6 inch×1.2 inch steel 90 m long is subjected to a 45 KN tensile load along its lenght.If poison's ratio is 0.3 Find: A. The deformation along its lenght. B. The deformation along its thickness. C. The defirmation along uts width. D. The lateral strain.arrow_forwardShow Stress/ strain curve for nitinol and steel (2 separate charts please)arrow_forward
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