Biochemistry: Concepts and Connections (2nd Edition)
2nd Edition
ISBN: 9780134641621
Author: Dean R. Appling, Spencer J. Anthony-Cahill, Christopher K. Mathews
Publisher: PEARSON
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Chapter 6, Problem 5P
Give two reasons to explain why a proline residue in the middle of an a helix is predicted to be destabilizing to the helical structure.
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Chapter 6 Solutions
Biochemistry: Concepts and Connections (2nd Edition)
Ch. 6 - Prob. 1PCh. 6 - Bovine pancreatic trypsin inhibitor (BPTI; Figure...Ch. 6 - A schematic structure of the subunit of...Ch. 6 - In the protein adenylate kinase, the C-terminal...Ch. 6 - Give two reasons to explain why a proline residue...Ch. 6 - Consider a small protein containing 101 amino acid...Ch. 6 - a. Based on a more conservative answer to Problem...Ch. 6 - The following sequence is part of a globular...Ch. 6 - a. A protein is found to be a tetramer of...Ch. 6 - Under physiological conditions, the protein...
Ch. 6 - Theoretical and experimental measurements show...Ch. 6 - The peptide hormone vasopressin is used in the...Ch. 6 - A protein gives under conditions of buffer...Ch. 6 - A protein gives a single band on SDS get...Ch. 6 - It has been postulated that the normal...Ch. 6 - Below are shown two views of the backbone...Ch. 6 - Do you expect a Pro Gly mutation in a...Ch. 6 - Rank the following in terms of predicted rates...Ch. 6 - Shown below are two cartoon views of the small...Ch. 6 - Prob. 20PCh. 6 - In most cases, mutations in the core of protein...Ch. 6 - A Leu Ala mutation at a site buried the core of...Ch. 6 - Disulfide bonds have been shown to stabilize...Ch. 6 - Cartoon renderings of the proteins Top 7 and adaH2...
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- A reverse phase column chromatography separates proteins according to their polarity. Which pentapeptide will be eluted FIRST when chromatographed at pH 7 using a reverse phase column such as a C-18 column? Peptide Sequence (from N-terminal to C-terminal) AKGED GAAVF ALLLI MCYAG GAAVF MCYAG ALLLI AKGEDarrow_forwardMelting of three DNA samples with varying lengths was monitored by increase of ultraviolet light absorbance at 260 nm. Which is the shortest DNA? A B Carrow_forwardSelect the CORRECT description of the peptide bond. The peptide bond can freely rotate around the peptide bond. The peptide bond is non-polar, hydrophobic and does not have a dipole. The peptide bond is most stable in the cis configuration. The peptide bond is rigid and planar. The peptide bond has a mix of single and double bond characters. The peptide bond is most stable in the trans configuration.arrow_forward
- Below is a fractional saturation curve for O2 binding to adult hemoglobin. Assume that curve Y represents a system at pH 7.4 and with a normal physiological level of 2,3-BPG. Curve Z represents a system that ___________________ Curve Z: is at pH 7.4 with a higher than normal physiological level of 2,3-BPG. is at pH 7.4 with a normal physiological level of 2,3-BPG but with a decreased level of CO2. has a higher pH with a normal physiological level of 2,3-BPG. has a higher pH with a lower than physiological level of 2,3-BPG.arrow_forwardWhich is a homotropic positive effector of aspartate transcarbamoylase (ATCase)? oxygen CTP aspartate ATParrow_forwardThe reaction scheme shows the mechanism of chymotrypsin-catalyzed peptide hydrolysis. Select ALL CORRECT statements regarding the chymotrypsin mechanism. Serine is the nucleophile in the step 3. Histidine is a general base in the step 2. Carbonyl carbon is the electrophile in the step 3. Histidine is a general acid in the step 4. Carbonyl carbon is the nucleophile in the step 3. This is an example of covalent catalysis. Aspartate is the electrophile in the step 3. Histidine is the nucleophile in the step 3.arrow_forward
- The following shows a protein with mostly beta sheet secondary structures. Which force stabilizes the beta sheet secondary structure of proteins? hydrophobic interactions between nonpolar amino acid side chains within the protein. electrostatic interactions between lysine and aspartic acid residues within the protein. hydrogen bonding between hydrogen bond donors and hydrogen bond acceptors of the peptide backbone. covalent disulfide linkages between cysteine residues within the protein.arrow_forwardThe Lineweaver-Burk plot was obtained when enzyme inhibition study was done in the absence and presence of 0.50 mM inhibitor. Answer the following questions using correct units and significant figures: (a) What is the mode of inhibition, competitive, uncompetitive, mixed, or noncompetitive? Explain your answer. (b) What can you say about the finding site for the inhibitor in relation to the active site of the enzyme? Explain your answer. (c) Calculate the Km and Vmax in the absence of inhibitor. (d) Calculate the Km and Vmax in the presence of 0.50 mM inhibitor. (e) Calculate the KI of the inhibitor using the given equations for reversible inhibition. Which has a higher affinity, the substrate or the inhibitor? How can you tell?arrow_forwardWhich peptide sequence is most likely to be found in the interior portion of a water-soluble globular protein? GGDGEMG DSKSTEG GAIVLWL IVAKSLIarrow_forward
- The following shows a reaction coordinate diagram. Choose a CORRECT statement explaining the diagram. The size of C decreases in the presence of an enzyme. B indicates the activation energy of the reaction in the presence of an enzyme. C indicates the activation energy of the reaction in the presence of an enzyme. A is related to the equilibrium constant of the reaction in the absence of an enzyme.arrow_forwardSelect ALL correct statements regarding myoglobin and hemoglobin. Statements: Myoglobin has a higher affinity for oxygen than hemoglobin does. Both myoglobin and hemoglobin contain mostly alpha-helical structures. Myoglobin has one binding site for 2,3-BPG. Hemoglobin is a tetramer, each of which binds one heme group. In both myoglobin and hemoglobin, iron ions (Fe2+) bind directly to oxygen. Myoglobin is a tetrameric protein. Hemoglobin exhibits cooperative binding with oxygen. Myoglobin does not. Hydrogen ion, carbon dioxide, and 2,3-BPG are negative allosteric effectors of oxygen binding to hemoglobin. Myoglobin has a lower P50 for oxygen than hemoglobin does. Hemoglobin has a higher affinity for oxygen than myoglobin does. Both myoglobin and hemoglobin exhibit cooperative binding to oxygen.arrow_forwardAn enzyme is found to have maximum activity in a pH range of 6 to 8. It is inactive below pH 3. It is also found that glutamate and serine residues are present at the active site. The mutations of these residues show the following results. Select ALL statements that are consistent with the experimental results. When serine is mutated to alanine, the mutant enzyme is fully active with maximum activity at pH 6 to 8. When glutamate is mutated to alanine, the mutant enzyme is inactive at all pH. The pKa of the side chain of glutamate is 4.25. Glutamate is required for catalysis at pH 6 to 8. Serine is not required for catalysis at pH 6 to 8. Glutamate must be protonated for catalysis at pH 6 to 8. Glutamate must be deprotonated for catalysis at pH 6 to 8. Both serine and glutamate are required for catalysis at pH 6 to 8.arrow_forward
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