Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
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Chapter 6, Problem 10CONQ
In humans, a rare dominant disorder known as nail-patella syndrome causes abnormalities in the fingernails, toenails, and kneecaps. Researchers have examined family pedigrees with regard to this disorder and have also examined the blood types of individuals within each pedigree. (A description of blood genotypes is found in Chapter 4.) In the following pedigree, individuals affected with nail-patella disorder are shown with filled symbols. The genotype of each individual with regard to ABO blood type is also shown. Does this pedigree suggest any linkage between the gene that causes nail-patella syndrome and the gene that causes blood type?
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In humans, a rare dominant disorder known as nail-patella syndromecauses abnormalities in the fingernails, toenails, and kneecaps.Researchers have examined family pedigrees with regard to thisdisorder and have also examined the blood types of individualswithin each pedigree. (A description of blood genotypes is foundin Chapter 4.) In the following pedigree, individuals affected withnail-patella disorder are shown with filled symbols. The genotypeof each individual with regard to ABO blood type is also shown.Does this pedigree suggest any linkage between the gene thatcauses nail-patella syndrome and the gene that causes blood type?
Alpha thalassemia is a hereditary blood condition that results in varying levels of anemia. It is tied to the HB alpha 1 gene and the HB alpha 2 gene on human chromosome 16.
The diagram shows the proteins for the hemoglobin genes and the pedigree shows genotypes, designated by the letter X, on the chromosomes for a family affected by the condition.
Which represents the predicted level of anemia in a child born to the mother and father in the image with a mutation that results in a genotype of xxxx? Why?
A - mild anemia because the loss of 4 genes would equal the loss of the 4 proteins needed for normal alpha hemoglobin
B - severe anemia because the loss of 4 genes would equal the loss of the 4 proteins needed for normal alpha hemoglobin
C - mild anemia because the addition of 4 genes would produce too many of the proteins needed for normal alpha hemoglobin
D - severe anemia because the addition of 4 genes would produce too many of the proteins needed for normal alpha hemoglobin
Cystic fibrosis is a genetic disease that causes an abnormal production of mucus which in turn can cause damage and infection to the lungs and other organs. In the following pedigree, black indicates all those persons afflicted with cystic fibrosis (square symbols are males, circles are females). There's a healthy couple and they have two children. One is a 23-year-old daughter with cystic fibrosis who is married to a 24-year-old male who is healthy. The other child is a 15-year-old son who is healthy
After studying the pedigree, write a logical hypothesis suggesting the cause of cystic fibrosis in terms of dominant or recessive alleles.
On the basis of your hypothesis, write an appropriate genotype for both of the parents.
Using a Punnett square, what is the probability of the parents having a child with cystic fibrosis?
If the daughter's husband is a carrier of cystic fibrosis, what is the probability that they have a child with cystic fibrosis? Show your Punnett square.
Chapter 6 Solutions
Genetics: Analysis and Principles
Ch. 6.1 - 1. Genetic linkage occurs because
a. genes that...Ch. 6.1 - In the experiment by Bateson and Punnett, which of...Ch. 6.2 - Prob. 1COMQCh. 6.2 - Prob. 2COMQCh. 6.2 - 3. For a chi square analysis involving genes that...Ch. 6.3 - Answer the multiple-choice questions based on the...Ch. 6.3 - Answer the multiple-choice questions based on the...Ch. 6.4 - 1. A tetrad of spores in an ascus is the product...Ch. 6.4 - Prob. 2COMQCh. 6.5 - 1. The process of mitotic recombination involves...
Ch. 6 - 1. What is the difference in meaning between the...Ch. 6 - 2. When a chi square analysis is applied to solve...Ch. 6 - 3. What is mitotic recombination? A heterozygous...Ch. 6 - 4. Mitotic recombination can occasionally produce...Ch. 6 - 5. A crossover has occurred in the bivalent shown...Ch. 6 - A crossover has occurred in the bivalent shown...Ch. 6 - A diploid organism has a total of 14 chromosomes...Ch. 6 - If you try to throw a basketball into a basket,...Ch. 6 - 9. By conducting testcrosses, researchers have...Ch. 6 - In humans, a rare dominant disorder known as...Ch. 6 - 11. When true-breeding mice with brown fur and...Ch. 6 - Though we often think of genes in terms of the...Ch. 6 - 13. If the likelihood of a single crossover in a...Ch. 6 - 14. In most two-factor crosses involving linked...Ch. 6 - Researchers have discovered that some regions of...Ch. 6 - 16. Describe the unique features of ascomycetes...Ch. 6 - Figure 6.1 shows the first experimental results...Ch. 6 - In the experiment of Figure 6.6, Stern followed...Ch. 6 - 3. Explain the rationale behind a testcross. Is it...Ch. 6 - 4. In your own words, explain why a testcross...Ch. 6 - Explain why the percentage of recombinant...Ch. 6 - 6. If two genes are more thanapart, how would you...Ch. 6 - 7. In Morgan’s three-factor crosses of Figure 6.3,...Ch. 6 - Two genes are located on the same chromosome and...Ch. 6 - 9. Two genes, designated A and B, are locatedfrom...Ch. 6 - 10. Two genes in tomatoes areapart; normal fruit...Ch. 6 - In the tomato, three genes are linked on the same...Ch. 6 - A trait in garden peas involves the curling of...Ch. 6 - Prob. 13EQCh. 6 - 14. In the garden pea, several different genes...Ch. 6 - A sex-influenced trait is dominant in males and...Ch. 6 - Three recessive traits in garden pea plants are as...Ch. 6 - In mice, a trait called snubnose is recessive to a...Ch. 6 - 18. In Drosophila, an allele causing vestigial...Ch. 6 - 19. Three autosomal genes are linked along the...Ch. 6 - 20. Let’s suppose that two different X-linked...Ch. 6 - Prob. 21EQCh. 6 - In mice, a dominant allele that causes a short...Ch. 6 - 2. In Chapter 3, we discussed the idea that the X...Ch. 6 - Mendel studied seven traits in pea plants, and the...
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- The following pedigree illustrates the inheritance of Nance–Horan syndrome, a rare genetic condition in which affected people have cataracts and abnormally shaped teeth.arrow_forwardHemophilia is an X-linked disease associated with the inability to produce specific proteins in the blood-clotting pathway. Shown above is a family pedigree tree in which family members afflicted with the disease are shown with filled-in squares (male) or circles (females). A couple is trying to determine the likelihood of passing on the disease to their future children (represented by the ? symbol above) because the hemophilia runs in the woman’s family 4.Assuming that the woman in the couple is a carrier, what is the probability that the couple’s first son will have hemophilia?arrow_forwardChands syndrome is an autosomal recessive condition characterized by very curly hair, underdeveloped nails, and abnormally shaped eyelids. In the pedigree below: Which individuals must be carriers (heterozygotes)? ----- arrow_forward
- Ann's family has a history of cystic fibrosis, a recessive genetic disease. In the pedigree, family members who are afflicted with the disease are shown in red. Members who are unafflicted may or may not be carriers. Which of the given family members can be identified definitively as unafflicted carriers of cystic fibrosis?arrow_forwardCystic fibrosis (CF) is an autosomal recessive trait. A three-generation pedigree is shown below for a family that carries the mutant allele for cystic fibrosis. Note that carriers are not colored in to allow you to figure out their genotypes. Normal allele = F CF mutant allele = f What is the genotype of individual #13? A) ff B) FF C) Ff D) it is impossible to tellarrow_forwardIn a well-publicized paternity case, the following facts were determined: the mother, a beautiful, twice-convicted axe murderer, is blood type A. Her child, Lizzie, is type O and the alleged father, a mild-mannered felon convicted of check fraud, is type B. On the last day of the trial, another father – a missionary worker with blood type O is identified. Which of the two could be Lizzie’s father? Use the space below to support your conclusion. I am really confused with the queshtion and need help finding the answer and how to prove can somone explain the answer and show it in a punnet sqaure pleasearrow_forward
- Refer to the pedigree below which shows inheritance for achondroplasia (dwarfism), a dominantly inherited trait (denoted as D), which are the darkened circles and squares. Dwarfism (darkened shapes) are dominantly inherited, while normal height is recessively inherited (hh). Based on the pedigree, what is the correct genotype for individual #II-6? Dominant Autosomal Pedigree 2 II 2 3 II 1 2 3 6 9 10 Dd DD DD or Dd ddarrow_forwardThe following pedigree illustrates the inheritance of ringed hair, a condition in which each hair is differentiated into light and dark zones. What mode or modes of inheritance are possible for the ringed-hair trait in this family?arrow_forwardHelp me create a pedigree of this information: Pedigree analysis: Generation 1: Normal parents (AA x AA) Generation 2: Carrier parents (AA x AS) Generation 3: Affected child (AS x AS) Generation 4: Affected grandchild (SS) This pedigree has two normal parents in the first generation. Second generation carriers carry the sickle cell trait from one parent. The disease is 25% more likely to be inherited in the third generation if both parents have the 'S' allele. If both parents have the 'S' allele, their children will have sickle cell anemia in the fourth generationarrow_forward
- Brachydactyly type D is human autosomal dominant condition in which the thumbs are abnormally short and broad. In most cases, both thumbs are affected, but occasionally just one thumb is involved. The pedigree above shows a family in which brachydactlyly type D is segregating. Filled circles and squares represent females and males who have involvement of both thumbs. Half-filled in symbols represent family members with just one thumb affected? (Picture attached) There is evidence of variable expressivity and incomplete penetrance in this family. Which individual is most likely nonpenetrant for the trait? A) III-11 B) IV-1 C) IV-5 D) III-10 E) II-4arrow_forwardThe genotype of EB27 and EB67 are unknown. Based on pedigree, what are the most likely genotype of each individual?arrow_forwardUsing the pedigree, assume that the disease is caused by an autosomal dominant allele, R. Give the genotype of the following individuals: (a) III-4 (the girl at lower right) (b) II-3 (the girl’s mother) (c) II-4 (the girl’s father)arrow_forward
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