Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 5, Problem 34Q
To determine
The law best describes the alteration of the sun’s spectrum through the earth.
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In the graph below, the yellow region shows the AM 1.5 solar spectrum. The area indicated by the blue area represents the AM 1.0 spectrum. The boundaries of the AM 1.0 spectrum;
When λ = between 250nm and 1000nm Pλ = 1x109Wm^(-2) m^(-1)
When λ = between 1000nm and 2000nm Pλ = 0.25x109W m^(-2) m^(-1)
In that case;
a-) Find the radiation intensity (I) and photon flux () for AM 1.0.
b-) If the radiation intensity in the option a comes to the silicon solar cell with a band gap of 1.12eV, how much will the photo-current be produced?
Chapter 5 Solutions
Universe: Stars And Galaxies
Ch. 5 - Prob. 1QCh. 5 - Prob. 2QCh. 5 - Prob. 3QCh. 5 - Prob. 4QCh. 5 - Prob. 5QCh. 5 - Prob. 6QCh. 5 - Prob. 7QCh. 5 - Prob. 8QCh. 5 - Prob. 9QCh. 5 - Prob. 10Q
Ch. 5 - Prob. 11QCh. 5 - Prob. 12QCh. 5 - Prob. 13QCh. 5 - Prob. 14QCh. 5 - Prob. 15QCh. 5 - Prob. 16QCh. 5 - Prob. 17QCh. 5 - Prob. 18QCh. 5 - Prob. 19QCh. 5 - Prob. 20QCh. 5 - Prob. 21QCh. 5 - Prob. 22QCh. 5 - Prob. 23QCh. 5 - Prob. 24QCh. 5 - Prob. 25QCh. 5 - Prob. 26QCh. 5 - Prob. 27QCh. 5 - Prob. 28QCh. 5 - Prob. 29QCh. 5 - Prob. 30QCh. 5 - Prob. 31QCh. 5 - Prob. 32QCh. 5 - Prob. 33QCh. 5 - Prob. 34QCh. 5 - Prob. 35QCh. 5 - Prob. 36QCh. 5 - Prob. 37QCh. 5 - Prob. 38QCh. 5 - Prob. 39QCh. 5 - Prob. 40QCh. 5 - Prob. 41QCh. 5 - Prob. 42QCh. 5 - Prob. 43QCh. 5 - Prob. 44QCh. 5 - Prob. 45QCh. 5 - Prob. 46QCh. 5 - Prob. 47QCh. 5 - Prob. 48QCh. 5 - Prob. 49QCh. 5 - Prob. 50QCh. 5 - Prob. 51Q
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- Calculate the wavelength of a photon having an energy of 5.89 x 10^11 J of energy. E = hc/λ You must show a correct numerical setup and your answer must include the correct mathematical unit.arrow_forwardWhich of the following statements are TRUE about the Sun's spectrum, which is shown in this image? Brightness 2.5 3.5 0 Jay 200 Sun's Spectrum vs. Thermal Radiator of a single temperature T = 5777 K peak spectrum of Sun spectrum of T=5777 K blackbody emission spectrum (continuum) absorption lines 400 600 800 1000 1200 1400 1600 Wavelength (nanometres) 1800 2000 The spectrum shows that the Sun emits light of all colors equally, which is why we see it as white. The spectrum shows the presence of many sunspots. The peaks and valleys in the black line reveal the chemical composition of the Sun. The spectrum shows absorption features (spectral lines). The spectrum represents a perfect blackbody.arrow_forwardQ1: Find the total energy and the greatest wavelength of the energy emitted from the surface of the sun if you know that the amount of illumination emitted from the surface of the sun will increase by 6 *10^6 times when its surface temperature increases by an amount (0 = 5.67x10* w/m°k* ). 1000 karrow_forward
- Human body temperature is about 310 K (3.10 ✕ 102 K). At what wavelength (in nm) do humans radiate the most energy? In which part of the electromagnetic spectrum (gamma-ray, X-ray, UV, visible light, IR, microwave, or radio) do we emit?arrow_forwardexplain how emission and absorption involve semiclassical physics?arrow_forwardThe human eye is most sensitive to light of wavelength 5.50 x 10^-7 m which is the green yellow region of the visible electromagnetic spectrum. (Frequency is 5.45 x 10 ^14 Hz, wavelength is 0.550 microns). Where is this wavelength with respect to the center of the blackbody emission spectrum of the sun's radiation at 0.495 microns, and how did this come about?arrow_forward
- When astronomers look at the spectrum of the Sun, they noticed that the light from one edge is slightly blue-shifted, while light from the opposite age is slightly red-shifted. What does this tell you about the Sun?arrow_forwardYour research team analysis the light of a mysterious object in space. By using a spectrometer,you can observe the following spectrum of the object. The Hα line peak is clearly visible. Answer the questions from given graph (a) Mark the first four spectral lines of hydrogen (Hα, Hβ, Hγ, Hδ) in the spectrum.(b) Determine the radial velocity and the direction of the object’s movement.(c) Calculate the distance to the observed object.(d) What possible type of object is your team observing?arrow_forwardThe greenhouse effect can be explained easily if you understand the laws of blackbody radiation. A greenhouse gas blocks the transmission of infrared light. Given that the incoming light to Earth is sunlight with a characteristic temperature of 5800 K (which peaks in the visible part of the spectrum) and the outgoing light from Earth has a characteristic temperature of about 300 K (which peaks in the infrared part of the spectrum), explain how greenhouse gases cause Earth to warm up. As part of your answer, discuss that greenhouse gases block both incoming and outgoing infrared light. Explain why these two effects don’t simply cancel each other, leading to no net temperature change.arrow_forward
- The edge of the Sun doesn’t have to be absolutely sharp in order to look that way to us. It just has to go from being transparent to being completely opaque in a distance that is smaller than your eye can resolve. Remember from Astronomical Instruments that the ability to resolve detail depends on the size of the telescope’s aperture. The pupil of your eye is very small relative to the size of a telescope and therefore is very limited in the amount of detail you can see. In fact, your eye cannot see details that are smaller than 1/30 of the diameter of the Sun (about 1 arcminute). Nearly all the light from the Sun emerges from a layer that is only about 400 km thick. What fraction is this of the diameter of the Sun? How does this compare with the ability of the human eye to resolve detail? Suppose we could see light emerging directly from a layer that was 300,000 km thick. Would the Sun appear to have a sharp edge?arrow_forwardExplain why the presence of spectral lines of a given element in the solar spectrum tells you that element is present in the Sun, but the absence of the lines would not necessarily mean the element is absent from the Sun.arrow_forward
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