Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 5, Problem 29Q
To determine
If red light or blue light emit more photon per second.
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Chapter 5 Solutions
Universe: Stars And Galaxies
Ch. 5 - Prob. 1QCh. 5 - Prob. 2QCh. 5 - Prob. 3QCh. 5 - Prob. 4QCh. 5 - Prob. 5QCh. 5 - Prob. 6QCh. 5 - Prob. 7QCh. 5 - Prob. 8QCh. 5 - Prob. 9QCh. 5 - Prob. 10Q
Ch. 5 - Prob. 11QCh. 5 - Prob. 12QCh. 5 - Prob. 13QCh. 5 - Prob. 14QCh. 5 - Prob. 15QCh. 5 - Prob. 16QCh. 5 - Prob. 17QCh. 5 - Prob. 18QCh. 5 - Prob. 19QCh. 5 - Prob. 20QCh. 5 - Prob. 21QCh. 5 - Prob. 22QCh. 5 - Prob. 23QCh. 5 - Prob. 24QCh. 5 - Prob. 25QCh. 5 - Prob. 26QCh. 5 - Prob. 27QCh. 5 - Prob. 28QCh. 5 - Prob. 29QCh. 5 - Prob. 30QCh. 5 - Prob. 31QCh. 5 - Prob. 32QCh. 5 - Prob. 33QCh. 5 - Prob. 34QCh. 5 - Prob. 35QCh. 5 - Prob. 36QCh. 5 - Prob. 37QCh. 5 - Prob. 38QCh. 5 - Prob. 39QCh. 5 - Prob. 40QCh. 5 - Prob. 41QCh. 5 - Prob. 42QCh. 5 - Prob. 43QCh. 5 - Prob. 44QCh. 5 - Prob. 45QCh. 5 - Prob. 46QCh. 5 - Prob. 47QCh. 5 - Prob. 48QCh. 5 - Prob. 49QCh. 5 - Prob. 50QCh. 5 - Prob. 51Q
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- Which produces a shorter wavelength of light: an electron jumping from a hydrogen atom’s 6th energy level to its 2nd energy level, or one jumping from the 3rd to the 2nd energy level? Explain your answer.arrow_forwardThe human eye is most sensitive to light of wavelength 5.50 x 10^-7 m which is the green yellow region of the visible electromagnetic spectrum. (Frequency is 5.45 x 10 ^14 Hz, wavelength is 0.550 microns). Where is this wavelength with respect to the center of the blackbody emission spectrum of the sun's radiation at 0.495 microns, and how did this come about?arrow_forwarda) To which object corresponds this spectrum to? b) What is the source of radiation for each of the two humps? c) Why does the hump on the right hand side peak at higher wavelength than the hump on the left? [Specifically, what does this tell you about the temperature for each object that the light originates from?]arrow_forward
- When astronomers look at the spectrum of the Sun, they noticed that the light from one edge is slightly blue-shifted, while light from the opposite age is slightly red-shifted. What does this tell you about the Sun?arrow_forwardSuppose YOUR body temperature averages 98.6 F. 1. How much radiant energy in Wm^-2 is emitted from YOUR body? 2. What is the total radiant energy in W that is emitted from YOUR body? 3. At what wavelength does YOUR body emit the largest amount of radiant energy?arrow_forwardA blue-hot star is about twice as hot as a red-hot star. But the temperatures of the gases in advertising signs are about the same, whether they emit red or blue light. What is your explanation?arrow_forward
- If you see a red-hot star, you can be certain that its peak intensity is in the infrared region. Why is this?arrow_forwardHow many watts of radiation does a 1-meter-square region of the Sun’s spot emit, at a temperature of 5000 K? How much would the wattage increase if the temperature of the spot were twice as much, 10 000 K?arrow_forwardLook up the wavelengths of the spectral lines of hydrogen, and the nomenclature used to label these lines. Identify the hydrogen lines in the solar spectrum over the range shown below.arrow_forward
- In the graph below, the yellow region shows the AM 1.5 solar spectrum. The area indicated by the blue area represents the AM 1.0 spectrum. The boundaries of the AM 1.0 spectrum; When λ = between 250nm and 1000nm Pλ = 1x109Wm^(-2) m^(-1) When λ = between 1000nm and 2000nm Pλ = 0.25x109W m^(-2) m^(-1) In that case; a-) Find the radiation intensity (I) and photon flux () for AM 1.0. b-) If the radiation intensity in the option a comes to the silicon solar cell with a band gap of 1.12eV, how much will the photo-current be produced?arrow_forwardUse Wien's Law to calculate the peak wavelength of light coming from the Sun. Assume T=5800 K for the surface temperature of the Sun. Wein's displacement law says that the blackbody temperature and peak wavelength multiplied together give a constant of 0.29 cm-K. (K is degrees Kelvin). Convert the wavelength from part A into a frequency. The product of wavelength and frequency for electromagnetic radiation is a constant, the speed of light (c), 3 x 10^10 cm/s.arrow_forwardThe greenhouse effect can be explained easily if you understand the laws of blackbody radiation. A greenhouse gas blocks the transmission of infrared light. Given that the incoming light to Earth is sunlight with a characteristic temperature of 5800 K (which peaks in the visible part of the spectrum) and the outgoing light from Earth has a characteristic temperature of about 300 K (which peaks in the infrared part of the spectrum), explain how greenhouse gases cause Earth to warm up. As part of your answer, discuss that greenhouse gases block both incoming and outgoing infrared light. Explain why these two effects don’t simply cancel each other, leading to no net temperature change.arrow_forward
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