Chapter 4.4, Problem 7E

To determine

Tofind:the interval of increase and decrease function, interval of concavity, local maxima, local minima and inflection points using graph.

Answer to Problem 7E

From the graph it can be easily verify the increasing and decreasing of the function, maxima and minima and inflection point and concavity of the function.

Explanation of Solution

Given:

  $\text{f}\left(\text{x}\right){\text{=x}}^{\text{2}}\text{-4x+7cosx}$ , $-4\le x\le 4$ .

Concept used:

Increasing or decreasing function can be calculated by equating first derivative of the function to 0.

  $\frac{\text{dy}}{\text{dx}}\text{=0}$ .

If $\frac{{\text{d}}^2\text{y}}{{\text{dx}}^2}\text{>0}\text{.}$ the concave will be open upward and local minima can be found.

If $\frac{{\text{d}}^2\text{y}}{{\text{dx}}^2}\text{<0}\text{.}$ the concave will open downward and local maxima can be found.

If the graph of $\text{y=<mo>f</mo>}\left(\text{x}\right)$ has point of inflection then .

Calculation:

  $\text{f}\left(\text{x}\right){\text{=x}}^{\text{2}}\text{-4x+7cosx}$ .

   .

   .

From the graph:

Concave upward at point which is Minima $x=0$ , $\text{y=-5}$ .

Concave downward at point which is maxima $\text{x=-π}$ , $\text{y=9}$ .

The function increases in the interval of $\left(1.281,-8.146\right),\left(4,9.28\right)$ .

The function decreases in the interval of $\left(-1.281,0\right),\left(1.281,-8.146\right)$ .

Inflection point= $\left(\text{0,-5}\right)\text{,}\left(\text{-π,9}\right)\text{,}\left(\text{π,9}\right)$ .

The graphs of the functions are:

  

Red line indicates the graph of the function $\text{f}\left(\text{x}\right)$ .

Blue line indicates the graph of the first derivative of the function .

Green line indicates the second derivative of the function .

Hence from the graph it can be easily verify the increasing and decreasing of the function, maxima and minima and inflection point and concavity of the function.