Concept explainers
To Find:The intervals of the increase and decrease and intervals concavity of the function.
Answer to Problem 11E
Explanation of Solution
Given:Sketch the graph by hand using asymptotes and the intercepts but not derivatives. Then use your sketch to producing graphs that display the major features of the curve. Use the graph to estimate the maximum and minimum values.
Given:
The factors of the numerator are
Thus the intercepts are
The Zeroes of the denominator are giving intercepts
There is no
The graph of the function is
Now,
The for the signs of the interval
Then
Local maximum=
Local minimum =
Now,
The function is increasing and decreasing on the interval
And local maximum is
Hence
Local maximum=
Local minimum =
Chapter 4 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning