Chapter 4, Problem 4.23NP

Interpretation Introduction

Interpretation:

The value of $\Delta H_R^o$ should be calculated at 675 K for the following reaction.

  ${\text{4NH}}_3\text{(g)}+6\text{NO(g)}\to 5{\text{N}}_{\text{2}}(g)+{\text{6H}}_{\text{2}}\text{O(g)}$

The result for $\Delta H_R^o$ should be compared at 298.15 K. Whether the difference is large or small should be explained with reason.

Concept Introduction:

The mathematical expression for the standard enthalpy change value at room temperature is:

  $\Delta H{°}_R={\displaystyle \sum \text{n}}\text{H°(products})-{\displaystyle \sum \text{p}}\text{H°(reactants)}$

Where, n and p represents the coefficients of reactants and products in the balanced chemical equation.