Precalculus with Limits: A Graphing Approach
Precalculus with Limits: A Graphing Approach
7th Edition
ISBN: 9781305071711
Author: Ron Larson
Publisher: Brooks/Cole
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Question
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Chapter 3.5, Problem 42E

a.

To determine

To calculate : the linear model for the value V of the laptop

a.

Expert Solution
Check Mark

Answer to Problem 42E

The linear model for the value V of the laptop is 275t+1200

Explanation of Solution

Given information : The question is

A new laptop computer that sold for $1200 in 2014 has a book value $650 after 2 years

Calculation :

Given two pints

  (t1,V1)(0,1200)(t2,V2)(2,650)

Solve for the slope m

  m=v2v1t2t1=650120020=275VV1=m(tt1)V1200=275(t0)V=275t+1200

b.

To determine

To calculate : the exponential model for the value V of the sedan

b.

Expert Solution
Check Mark

Answer to Problem 42E

The exponential model for the value V of the laptop is 1200e0.3066t

Explanation of Solution

Given information : The question is

A new laptop computer that sold for $1200 in 2014 has a book value $650 after 2 years

Calculation :

Using the exponential model

  y=aebtt=0,V=12001200=aeb(0)a=1200t=2y=650650=aeb(2)6501200=e2bln6501200=lne2bln6501200=2blneb=ln65012002b0.3066V=1200e0.3066t

c.

To determine

To use : the graphing utility to graph the two models

c.

Expert Solution
Check Mark

Explanation of Solution

Given information : The question is

A new laptop computer that sold for $1200 in 2014 has a book value $650 after 2 years

Graph : Sketch the graph using graphing utility.

Step 1: Press WINDOW button to access the Window editor.

Step 2: Press Y= button.

Step 3: Enter the data

Step 4: Press GRAPH button to graph the function.

The graph is obtained as:

  Precalculus with Limits: A Graphing Approach, Chapter 3.5, Problem 42E

Interpretation:

From the above graph it is observed that the red line shows the function V=275t+1200 and the blue line shows the function V=1200e0.3066t

d.

To determine

which model is represent a greater depreciation rate in first year

d.

Expert Solution
Check Mark

Answer to Problem 42E

The exponential model is represent a greater depreciation rate in first year

Explanation of Solution

Given information : The question is

A new laptop computer that sold for $1200 in 2014 has a book value $650 after 2 years

From the function it is observed that the exponential model is represent a greater depreciation rate in first year

e.

To determine

In what year the value of the sedan is greater using the linear and exponential model

e.

Expert Solution
Check Mark

Explanation of Solution

Given information : The question is

A new laptop computer that sold for $1200 in 2014 has a book value $650 after 2 years

From the graph the linear model is 0<t<2 and the exponential model is t2

Chapter 3 Solutions

Precalculus with Limits: A Graphing Approach

Ch. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.1 - Prob. 13ECh. 3.1 - Prob. 14ECh. 3.1 - Prob. 15ECh. 3.1 - Prob. 16ECh. 3.1 - Prob. 17ECh. 3.1 - Prob. 18ECh. 3.1 - Prob. 19ECh. 3.1 - Prob. 20ECh. 3.1 - Prob. 21ECh. 3.1 - Prob. 22ECh. 3.1 - Prob. 23ECh. 3.1 - Prob. 24ECh. 3.1 - Prob. 25ECh. 3.1 - Prob. 26ECh. 3.1 - Prob. 27ECh. 3.1 - Prob. 28ECh. 3.1 - Prob. 29ECh. 3.1 - Prob. 30ECh. 3.1 - Prob. 31ECh. 3.1 - Prob. 32ECh. 3.1 - Prob. 33ECh. 3.1 - Prob. 34ECh. 3.1 - Prob. 35ECh. 3.1 - Prob. 36ECh. 3.1 - Prob. 37ECh. 3.1 - Prob. 38ECh. 3.1 - Prob. 39ECh. 3.1 - Prob. 40ECh. 3.1 - Prob. 41ECh. 3.1 - Prob. 42ECh. 3.1 - Prob. 43ECh. 3.1 - Prob. 44ECh. 3.1 - Prob. 45ECh. 3.1 - Prob. 46ECh. 3.1 - Prob. 47ECh. 3.1 - Prob. 48ECh. 3.1 - Prob. 49ECh. 3.1 - Prob. 50ECh. 3.1 - Prob. 51ECh. 3.1 - Prob. 52ECh. 3.1 - Prob. 53ECh. 3.1 - Prob. 54ECh. 3.1 - Prob. 55ECh. 3.1 - Prob. 56ECh. 3.1 - Prob. 57ECh. 3.1 - Prob. 58ECh. 3.1 - Prob. 59ECh. 3.1 - Prob. 60ECh. 3.1 - Prob. 61ECh. 3.1 - Prob. 62ECh. 3.1 - Prob. 63ECh. 3.1 - 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Prob. 40ECh. 3.6 - Prob. 41ECh. 3.6 - Prob. 42ECh. 3.6 - Prob. 43ECh. 3.6 - Prob. 44ECh. 3.6 - Prob. 45ECh. 3.6 - Prob. 46ECh. 3.6 - Prob. 47ECh. 3.6 - Prob. 48ECh. 3.6 - Prob. 49ECh. 3.6 - Prob. 50ECh. 3 - Prob. 1RECh. 3 - Prob. 2RECh. 3 - Prob. 3RECh. 3 - Prob. 4RECh. 3 - Prob. 5RECh. 3 - Prob. 6RECh. 3 - Prob. 7RECh. 3 - Prob. 8RECh. 3 - Prob. 9RECh. 3 - Prob. 10RECh. 3 - Prob. 11RECh. 3 - Prob. 12RECh. 3 - Prob. 13RECh. 3 - Prob. 14RECh. 3 - Prob. 15RECh. 3 - Prob. 16RECh. 3 - Prob. 17RECh. 3 - Prob. 18RECh. 3 - Prob. 19RECh. 3 - Prob. 20RECh. 3 - Prob. 21RECh. 3 - Prob. 22RECh. 3 - Prob. 23RECh. 3 - Prob. 24RECh. 3 - Prob. 25RECh. 3 - Prob. 26RECh. 3 - Prob. 27RECh. 3 - Prob. 28RECh. 3 - Prob. 29RECh. 3 - Prob. 30RECh. 3 - Prob. 31RECh. 3 - Prob. 32RECh. 3 - Prob. 33RECh. 3 - Prob. 34RECh. 3 - Prob. 35RECh. 3 - Prob. 36RECh. 3 - Prob. 37RECh. 3 - Prob. 38RECh. 3 - Prob. 39RECh. 3 - Prob. 40RECh. 3 - Prob. 41RECh. 3 - Prob. 42RECh. 3 - Prob. 43RECh. 3 - Prob. 44RECh. 3 - Prob. 45RECh. 3 - Prob. 46RECh. 3 - Prob. 47RECh. 3 - Prob. 48RECh. 3 - Prob. 49RECh. 3 - Prob. 50RECh. 3 - Prob. 51RECh. 3 - Prob. 52RECh. 3 - Prob. 53RECh. 3 - Prob. 54RECh. 3 - Prob. 55RECh. 3 - Prob. 56RECh. 3 - Prob. 57RECh. 3 - Prob. 58RECh. 3 - Prob. 59RECh. 3 - Prob. 60RECh. 3 - Prob. 61RECh. 3 - Prob. 62RECh. 3 - Prob. 63RECh. 3 - Prob. 64RECh. 3 - Prob. 65RECh. 3 - Prob. 66RECh. 3 - Prob. 67RECh. 3 - Prob. 68RECh. 3 - Prob. 69RECh. 3 - Prob. 70RECh. 3 - Prob. 71RECh. 3 - Prob. 72RECh. 3 - Prob. 73RECh. 3 - Prob. 74RECh. 3 - Prob. 75RECh. 3 - Prob. 76RECh. 3 - Prob. 77RECh. 3 - Prob. 78RECh. 3 - Prob. 79RECh. 3 - Prob. 80RECh. 3 - Prob. 81RECh. 3 - Prob. 82RECh. 3 - Prob. 83RECh. 3 - Prob. 84RECh. 3 - Prob. 85RECh. 3 - Prob. 86RECh. 3 - Prob. 87RECh. 3 - Prob. 88RECh. 3 - Prob. 89RECh. 3 - Prob. 90RECh. 3 - Prob. 91RECh. 3 - Prob. 92RECh. 3 - Prob. 93RECh. 3 - Prob. 94RECh. 3 - Prob. 95RECh. 3 - Prob. 96RECh. 3 - Prob. 97RECh. 3 - Prob. 98RECh. 3 - Prob. 99RECh. 3 - Prob. 100RECh. 3 - Prob. 101RECh. 3 - Prob. 102RECh. 3 - Prob. 103RECh. 3 - Prob. 104RECh. 3 - Prob. 105RECh. 3 - Prob. 106RECh. 3 - Prob. 107RECh. 3 - Prob. 108RECh. 3 - Prob. 109RECh. 3 - Prob. 110RECh. 3 - Prob. 111RECh. 3 - Prob. 112RECh. 3 - Prob. 113RECh. 3 - Prob. 114RECh. 3 - Prob. 115RECh. 3 - Prob. 116RECh. 3 - Prob. 117RECh. 3 - Prob. 118RECh. 3 - Prob. 119RECh. 3 - Prob. 120RECh. 3 - Prob. 121RECh. 3 - Prob. 122RECh. 3 - Prob. 123RECh. 3 - Prob. 124RECh. 3 - Prob. 125RECh. 3 - Prob. 126RECh. 3 - Prob. 127RECh. 3 - Prob. 128RECh. 3 - Prob. 129RECh. 3 - Prob. 130RECh. 3 - Prob. 131RECh. 3 - Prob. 132RECh. 3 - Prob. 133RECh. 3 - Prob. 134RECh. 3 - Prob. 135RECh. 3 - Prob. 136RECh. 3 - Prob. 137RECh. 3 - Prob. 138RECh. 3 - Prob. 139RECh. 3 - Prob. 140RECh. 3 - Prob. 1CTCh. 3 - Prob. 2CTCh. 3 - Prob. 3CTCh. 3 - Prob. 4CTCh. 3 - Prob. 5CTCh. 3 - Prob. 6CTCh. 3 - Prob. 7CTCh. 3 - Prob. 8CTCh. 3 - Prob. 9CTCh. 3 - Prob. 10CTCh. 3 - Prob. 11CTCh. 3 - Prob. 12CTCh. 3 - Prob. 13CTCh. 3 - Prob. 14CTCh. 3 - Prob. 15CTCh. 3 - Prob. 16CTCh. 3 - Prob. 17CTCh. 3 - Prob. 18CTCh. 3 - Prob. 19CTCh. 3 - Prob. 20CTCh. 3 - Prob. 21CTCh. 3 - Prob. 22CTCh. 3 - Prob. 23CTCh. 3 - Prob. 24CTCh. 3 - Prob. 25CTCh. 3 - Prob. 26CTCh. 3 - Prob. 27CTCh. 3 - Prob. 28CTCh. 3 - Prob. 1CLTCh. 3 - Prob. 2CLTCh. 3 - Prob. 3CLTCh. 3 - Prob. 4CLTCh. 3 - Prob. 5CLTCh. 3 - Prob. 6CLTCh. 3 - Prob. 7CLTCh. 3 - Prob. 8CLTCh. 3 - Prob. 9CLTCh. 3 - Prob. 10CLTCh. 3 - Prob. 11CLTCh. 3 - Prob. 12CLTCh. 3 - Prob. 13CLTCh. 3 - Prob. 14CLTCh. 3 - Prob. 15CLTCh. 3 - Prob. 16CLTCh. 3 - Prob. 17CLTCh. 3 - Prob. 18CLTCh. 3 - Prob. 19CLTCh. 3 - Prob. 20CLTCh. 3 - Prob. 21CLTCh. 3 - Prob. 22CLTCh. 3 - Prob. 23CLTCh. 3 - Prob. 24CLTCh. 3 - Prob. 25CLTCh. 3 - Prob. 26CLTCh. 3 - Prob. 27CLTCh. 3 - Prob. 28CLTCh. 3 - Prob. 29CLTCh. 3 - Prob. 30CLTCh. 3 - Prob. 31CLTCh. 3 - Prob. 32CLTCh. 3 - Prob. 33CLTCh. 3 - Prob. 34CLTCh. 3 - Prob. 35CLTCh. 3 - Prob. 36CLTCh. 3 - Prob. 37CLTCh. 3 - Prob. 38CLTCh. 3 - Prob. 39CLTCh. 3 - Prob. 40CLTCh. 3 - Prob. 41CLTCh. 3 - Prob. 42CLTCh. 3 - Prob. 43CLTCh. 3 - Prob. 44CLTCh. 3 - Prob. 45CLTCh. 3 - Prob. 46CLTCh. 3 - Prob. 47CLT
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