Precalculus with Limits: A Graphing Approach
Precalculus with Limits: A Graphing Approach
7th Edition
ISBN: 9781305071711
Author: Ron Larson
Publisher: Brooks/Cole
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Concept explainers

Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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Question
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Chapter 3.4, Problem 118E

a.

To determine

To find:

An interval containing the solution of the equation by completing the table.

a.

Expert Solution
Check Mark

Answer to Problem 118E

Our required interval would be (160,165) .

Explanation of Solution

Given:

A logarithmic equation and a table: 5log10(x−2)=11 .

    x 150 155 160 165 170

      5log10(x−2)

Calculation:

To complete the table, we will substitute the values of x in our given expression as shown below:

  5log10(x−2)⇒5log10(150−2)⇒5log10(148)⇒10.8513085≈10.851

  5log10(x−2)⇒5log10(155−2)⇒5log10(153)⇒10.9234571≈10.923

  5log10(x−2)⇒5log10(160−2)⇒5log10(158)⇒10.9932854≈10.993

  5log10(x−2)⇒5log10(165−2)⇒5log10(163)⇒11.060938≈11.061

  5log10(x−2)⇒5log10(170−2)⇒5log10(168)⇒11.1265464≈11.127

The complete table would be:

    x 150 155 160 165 170

      5log10(x−2)

    		10.851 10.923 10.993 11.061 11.127

Since 11 lies between 10.933and11.127, therefore our required interval would be (160,165) .

b.

To determine

To graph:

The given function using a graphing utility and approximate the solution.

b.

Expert Solution
Check Mark

Answer to Problem 118E

The solution of our given equation would be x=160.489 .

Explanation of Solution

Given:

A logarithmic equation: 5log10(x−2)=11 .

Calculation:

Upon graphing our given function, we will get our required graph as shown below:

  Precalculus with Limits: A Graphing Approach, Chapter 3.4, Problem 118E

We can see that both lines intersect at x=160.489 , therefore, x=160.489 is a solution for our given function.

c.

To determine

To solve:

The given equation algebraically.

c.

Expert Solution
Check Mark

Answer to Problem 118E

The solution of our given equation would be x≈160.489 .

Explanation of Solution

Given:

A logarithmic equation: 5log10(x−2)=11 .

Calculation:

We will use logarithmic properties to solve our given equation.

  5log10(x−2)=11 (Given equation)5log10(x−2)5=115 (Dividing both sides by 5)log10(x−2)=115x−2=10115 (Converting log to exponential form)x−2=158.489319246x−2+2=158.489319246+2x=160.489319246x≈160.489 (Rounding to three decimal places)

Therefore, the solution of our given equation would be x≈160.489 .

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Chapter 3.4, Problem 117E
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Chapter 3.4, Problem 119E

Chapter 3 Solutions

Precalculus with Limits: A Graphing Approach

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Prob. 65ECh. 3.5 - Prob. 66ECh. 3.5 - Prob. 67ECh. 3.5 - Prob. 68ECh. 3.5 - Prob. 69ECh. 3.5 - Prob. 70ECh. 3.5 - Prob. 71ECh. 3.5 - Prob. 72ECh. 3.5 - Prob. 73ECh. 3.5 - Prob. 74ECh. 3.5 - Prob. 75ECh. 3.5 - Prob. 76ECh. 3.5 - Prob. 77ECh. 3.5 - Prob. 78ECh. 3.5 - Prob. 79ECh. 3.6 - Prob. 1ECh. 3.6 - Prob. 2ECh. 3.6 - Prob. 3ECh. 3.6 - Prob. 4ECh. 3.6 - Prob. 5ECh. 3.6 - Prob. 6ECh. 3.6 - Prob. 7ECh. 3.6 - Prob. 8ECh. 3.6 - Prob. 9ECh. 3.6 - Prob. 10ECh. 3.6 - Prob. 11ECh. 3.6 - Prob. 12ECh. 3.6 - Prob. 13ECh. 3.6 - Prob. 14ECh. 3.6 - Prob. 15ECh. 3.6 - Prob. 16ECh. 3.6 - Prob. 17ECh. 3.6 - Prob. 18ECh. 3.6 - Prob. 19ECh. 3.6 - Prob. 20ECh. 3.6 - Prob. 21ECh. 3.6 - Prob. 22ECh. 3.6 - Prob. 23ECh. 3.6 - Prob. 24ECh. 3.6 - Prob. 25ECh. 3.6 - Prob. 26ECh. 3.6 - Prob. 27ECh. 3.6 - Prob. 28ECh. 3.6 - Prob. 29ECh. 3.6 - Prob. 30ECh. 3.6 - Prob. 31ECh. 3.6 - Prob. 32ECh. 3.6 - Prob. 33ECh. 3.6 - Prob. 34ECh. 3.6 - Prob. 35ECh. 3.6 - Prob. 36ECh. 3.6 - Prob. 37ECh. 3.6 - Prob. 38ECh. 3.6 - Prob. 39ECh. 3.6 - Prob. 40ECh. 3.6 - Prob. 41ECh. 3.6 - Prob. 42ECh. 3.6 - Prob. 43ECh. 3.6 - Prob. 44ECh. 3.6 - Prob. 45ECh. 3.6 - Prob. 46ECh. 3.6 - Prob. 47ECh. 3.6 - Prob. 48ECh. 3.6 - Prob. 49ECh. 3.6 - Prob. 50ECh. 3 - Prob. 1RECh. 3 - Prob. 2RECh. 3 - Prob. 3RECh. 3 - Prob. 4RECh. 3 - Prob. 5RECh. 3 - Prob. 6RECh. 3 - Prob. 7RECh. 3 - Prob. 8RECh. 3 - Prob. 9RECh. 3 - Prob. 10RECh. 3 - Prob. 11RECh. 3 - Prob. 12RECh. 3 - Prob. 13RECh. 3 - Prob. 14RECh. 3 - Prob. 15RECh. 3 - Prob. 16RECh. 3 - Prob. 17RECh. 3 - Prob. 18RECh. 3 - Prob. 19RECh. 3 - Prob. 20RECh. 3 - Prob. 21RECh. 3 - Prob. 22RECh. 3 - Prob. 23RECh. 3 - Prob. 24RECh. 3 - Prob. 25RECh. 3 - Prob. 26RECh. 3 - Prob. 27RECh. 3 - Prob. 28RECh. 3 - Prob. 29RECh. 3 - Prob. 30RECh. 3 - Prob. 31RECh. 3 - Prob. 32RECh. 3 - Prob. 33RECh. 3 - Prob. 34RECh. 3 - Prob. 35RECh. 3 - Prob. 36RECh. 3 - Prob. 37RECh. 3 - Prob. 38RECh. 3 - Prob. 39RECh. 3 - Prob. 40RECh. 3 - Prob. 41RECh. 3 - Prob. 42RECh. 3 - Prob. 43RECh. 3 - Prob. 44RECh. 3 - Prob. 45RECh. 3 - Prob. 46RECh. 3 - Prob. 47RECh. 3 - Prob. 48RECh. 3 - Prob. 49RECh. 3 - Prob. 50RECh. 3 - Prob. 51RECh. 3 - Prob. 52RECh. 3 - Prob. 53RECh. 3 - Prob. 54RECh. 3 - Prob. 55RECh. 3 - Prob. 56RECh. 3 - Prob. 57RECh. 3 - Prob. 58RECh. 3 - Prob. 59RECh. 3 - Prob. 60RECh. 3 - Prob. 61RECh. 3 - Prob. 62RECh. 3 - Prob. 63RECh. 3 - Prob. 64RECh. 3 - Prob. 65RECh. 3 - Prob. 66RECh. 3 - Prob. 67RECh. 3 - Prob. 68RECh. 3 - Prob. 69RECh. 3 - Prob. 70RECh. 3 - Prob. 71RECh. 3 - Prob. 72RECh. 3 - Prob. 73RECh. 3 - Prob. 74RECh. 3 - Prob. 75RECh. 3 - Prob. 76RECh. 3 - Prob. 77RECh. 3 - Prob. 78RECh. 3 - Prob. 79RECh. 3 - Prob. 80RECh. 3 - Prob. 81RECh. 3 - Prob. 82RECh. 3 - Prob. 83RECh. 3 - Prob. 84RECh. 3 - Prob. 85RECh. 3 - Prob. 86RECh. 3 - Prob. 87RECh. 3 - Prob. 88RECh. 3 - Prob. 89RECh. 3 - Prob. 90RECh. 3 - Prob. 91RECh. 3 - Prob. 92RECh. 3 - Prob. 93RECh. 3 - Prob. 94RECh. 3 - Prob. 95RECh. 3 - Prob. 96RECh. 3 - Prob. 97RECh. 3 - Prob. 98RECh. 3 - Prob. 99RECh. 3 - Prob. 100RECh. 3 - Prob. 101RECh. 3 - Prob. 102RECh. 3 - Prob. 103RECh. 3 - Prob. 104RECh. 3 - Prob. 105RECh. 3 - Prob. 106RECh. 3 - Prob. 107RECh. 3 - Prob. 108RECh. 3 - Prob. 109RECh. 3 - Prob. 110RECh. 3 - Prob. 111RECh. 3 - Prob. 112RECh. 3 - Prob. 113RECh. 3 - Prob. 114RECh. 3 - Prob. 115RECh. 3 - Prob. 116RECh. 3 - Prob. 117RECh. 3 - Prob. 118RECh. 3 - Prob. 119RECh. 3 - Prob. 120RECh. 3 - Prob. 121RECh. 3 - Prob. 122RECh. 3 - Prob. 123RECh. 3 - Prob. 124RECh. 3 - Prob. 125RECh. 3 - Prob. 126RECh. 3 - Prob. 127RECh. 3 - Prob. 128RECh. 3 - Prob. 129RECh. 3 - Prob. 130RECh. 3 - Prob. 131RECh. 3 - Prob. 132RECh. 3 - Prob. 133RECh. 3 - Prob. 134RECh. 3 - Prob. 135RECh. 3 - Prob. 136RECh. 3 - Prob. 137RECh. 3 - Prob. 138RECh. 3 - Prob. 139RECh. 3 - Prob. 140RECh. 3 - Prob. 1CTCh. 3 - Prob. 2CTCh. 3 - Prob. 3CTCh. 3 - Prob. 4CTCh. 3 - Prob. 5CTCh. 3 - Prob. 6CTCh. 3 - Prob. 7CTCh. 3 - Prob. 8CTCh. 3 - Prob. 9CTCh. 3 - Prob. 10CTCh. 3 - Prob. 11CTCh. 3 - Prob. 12CTCh. 3 - Prob. 13CTCh. 3 - Prob. 14CTCh. 3 - Prob. 15CTCh. 3 - Prob. 16CTCh. 3 - Prob. 17CTCh. 3 - Prob. 18CTCh. 3 - Prob. 19CTCh. 3 - Prob. 20CTCh. 3 - Prob. 21CTCh. 3 - Prob. 22CTCh. 3 - Prob. 23CTCh. 3 - Prob. 24CTCh. 3 - Prob. 25CTCh. 3 - Prob. 26CTCh. 3 - Prob. 27CTCh. 3 - Prob. 28CTCh. 3 - Prob. 1CLTCh. 3 - Prob. 2CLTCh. 3 - Prob. 3CLTCh. 3 - Prob. 4CLTCh. 3 - Prob. 5CLTCh. 3 - Prob. 6CLTCh. 3 - Prob. 7CLTCh. 3 - Prob. 8CLTCh. 3 - Prob. 9CLTCh. 3 - Prob. 10CLTCh. 3 - Prob. 11CLTCh. 3 - Prob. 12CLTCh. 3 - Prob. 13CLTCh. 3 - Prob. 14CLTCh. 3 - Prob. 15CLTCh. 3 - Prob. 16CLTCh. 3 - Prob. 17CLTCh. 3 - Prob. 18CLTCh. 3 - Prob. 19CLTCh. 3 - Prob. 20CLTCh. 3 - Prob. 21CLTCh. 3 - Prob. 22CLTCh. 3 - Prob. 23CLTCh. 3 - Prob. 24CLTCh. 3 - Prob. 25CLTCh. 3 - Prob. 26CLTCh. 3 - Prob. 27CLTCh. 3 - Prob. 28CLTCh. 3 - Prob. 29CLTCh. 3 - Prob. 30CLTCh. 3 - Prob. 31CLTCh. 3 - Prob. 32CLTCh. 3 - Prob. 33CLTCh. 3 - Prob. 34CLTCh. 3 - Prob. 35CLTCh. 3 - Prob. 36CLTCh. 3 - Prob. 37CLTCh. 3 - Prob. 38CLTCh. 3 - Prob. 39CLTCh. 3 - Prob. 40CLTCh. 3 - Prob. 41CLTCh. 3 - Prob. 42CLTCh. 3 - Prob. 43CLTCh. 3 - Prob. 44CLTCh. 3 - Prob. 45CLTCh. 3 - Prob. 46CLTCh. 3 - Prob. 47CLT
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