EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
6th Edition
ISBN: 9781305687875
Author: Gilbert
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Question
Chapter 3.3, Problem 19E
Interpretation Introduction
Interpretation:Reason for different melting points for same compound should be determined.
Concept introduction:Melting point is temperature that involves conversion of substance from solid to liquid state. Both liquid and solid phases are present in equilibrium with each other at this temperature.
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Two samples have the exact same melting points. Are they the same compound? How could you tell for sure?
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Chapter 3 Solutions
EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
Ch. 3.2 - Prob. 1ECh. 3.2 - Prob. 2ECh. 3.2 - Prob. 3ECh. 3.2 - Prob. 4ECh. 3.2 - Prob. 5ECh. 3.2 - Prob. 6ECh. 3.2 - Prob. 7ECh. 3.2 - Prob. 8ECh. 3.2 - Prob. 9ECh. 3.2 - Prob. 10E
Ch. 3.2 - Prob. 11ECh. 3.2 - Prob. 12ECh. 3.2 - Prob. 13ECh. 3.2 - Prob. 14ECh. 3.2 - Prob. 15ECh. 3.2 - Prob. 16ECh. 3.2 - Prob. 17ECh. 3.2 - Prob. 18ECh. 3.2 - Prob. 19ECh. 3.2 - Prob. 20ECh. 3.2 - Prob. 21ECh. 3.2 - Prob. 22ECh. 3.2 - Prob. 23ECh. 3.2 - Prob. 24ECh. 3.2 - Prob. 25ECh. 3.2 - Prob. 26ECh. 3.2 - Prob. 27ECh. 3.2 - Prob. 28ECh. 3.2 - Prob. 29ECh. 3.2 - Prob. 30ECh. 3.2 - Prob. 31ECh. 3.2 - Prob. 32ECh. 3.2 - Prob. 34ECh. 3.3 - Prob. 1ECh. 3.3 - Prob. 2ECh. 3.3 - Prob. 3ECh. 3.3 - Prob. 4ECh. 3.3 - Prob. 5ECh. 3.3 - Prob. 6ECh. 3.3 - Prob. 7ECh. 3.3 - Prob. 8ECh. 3.3 - Prob. 10ECh. 3.3 - Prob. 11ECh. 3.3 - Prob. 12ECh. 3.3 - Prob. 13ECh. 3.3 - Prob. 14ECh. 3.3 - Prob. 15ECh. 3.3 - Prob. 16ECh. 3.3 - Prob. 17ECh. 3.3 - Prob. 18ECh. 3.3 - Prob. 19ECh. 3.3 - Prob. 21ECh. 3.3 - Prob. 22ECh. 3.3 - Prob. 23ECh. 3.3 - Prob. 24ECh. 3.3 - Prob. 25ECh. 3.3 - Prob. 26E
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- At room temperature, what physical state (solid, liquid or gas) would you predict for C18H38? Justify your answerarrow_forwardJust what does it imply when people talk about a "homogeneous structure?"arrow_forward1. Melting point can be defined as the temperature at which the solid and liquid forms of a compound are at equilibrium. Group of answer choices True Falsearrow_forward
- Ceramics used as abrasives must be hard and tough and be able to withstand high temperatures that arise from frictional forces. What is the minimum required hardness (measure in Mohs scale) for a material to be used as abrasive? Your answerarrow_forwardIn Parts 1 and 2, you noticed some patterns about what kind of substances conduct electricity when dissolved in water, and also how melting points are related. Let's test this pattern by applying it to other substances. Consider the following substances: Potassium Chloride: KClKClKCl Octadecanol: C18H38OC_{18}H_{38}OC18H38O Dimethyl Sulfoxide: C2H6OSC_2H_6OSC2H6OS Lithium Bromide: LiBrLiBrLiBr Explain the reasoning that supports your answer.? Use the patterns you saw in the previous sections to predict whether the melting points for each substance will be high (above 400°C) or low (below 200°C).?arrow_forwardEnumerate methods to determine a compound's melting point.arrow_forward
- lattice 1arrow_forwarda student ran a TLC plate with three different molecules that have the same carbon structure but each contain a different functional groups. Help the student match the compounds to the correct lane of the TLC platearrow_forward3.Why is slow cooling required to produce pure crystals?arrow_forward
- CIF(g) + F2(g) CIF3 (g) (6)*) AHDarrow_forward4. When performing a melting point on a solid compound using a melting point apparatus, two melting point determinations were made. One sample, which was 1 mm in height in the capillary, possessed a melting point of 200.0-200.5°C. The other sample was 25 mm in height. What would you expect the approximate melting point to be for this sample, assuming identical heating rates of 1°/min? (Hint: heat is applied from the bottom of the sample) (Give an actual numerical approximation!) 5. For the same solid compound as the question above, if the 1 mm sample was heated at 60° per minute on a melting point apparatus, what would you expect for an approximate melting point? (note that at this heating rate, the sample will melt rather quickly, but again give an actual numerical approximation)arrow_forwardGeneral Chemistry 4th Edition McQuarrie • Rock • Gallogly Consider the data in the table. Compound HF University Science Books presented by Macmillan Learning Melting point (°C) AHfus (kJ/mol) Boiling point (°C) AHvap (kJ/mol) -83.11 4.577 19.54 25.18 HCl -114.3 1.991 -84.9 17.53 HBr -86.96 2.406 -67.0 19.27 HI -50.91 2.871 Using the data in the table, calculate ASfus and ASvap for HCl. ASfus = ASvap = -35.38 21.16 Determine the entropy change when 6.10 mol HCl(g) condenses at atmospheric pressure. AS = J/(K. mol) J/(K⚫ mol) J/Karrow_forward
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