Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Chapter 31, Problem 20P
Interpretation Introduction
Interpretation:
A mutation in tRNA should be proposed to suppress frameshifting mutation.
Concept Introductio:
A frameshift mutation is a kind of genetic mutation which is caused due to the incorporation or deletion of a
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An extra piece. In one type of mutation leading to a form of
thalassemia, the mutation of a single base (G to A) generates a new 3'
3' splice site (blue in the illustration below) akin to the normal one
(yellow) but farther upstream.
Normal 3' end
of intron
5' CCTATTGGTCTATTITCCACCCITAGGCTGCTG 3'
5' CCTATTAGTCTAIIIICCACCCTTAGGCTGCTG 3'
What is the amino acid sequence of the extra segment of protein
synthesized in a thalassemic patient having a mutation leading to
aberrant splicing? The reading frame after the splice site begins with
TCT.
Question 8
Review translation. Match the term and its description. Each term can only be used once.
This site holds the tRNA that carries the growing polypeptide chain
| Choose )
This site holds the tRNA that carries the next amino acid to be
| Choose J
added to the chain
This site is the exit site, where discharged tRNAS leave the
[ Choose )
ribosome
Initiation, elongation and termination
| Choose J
>
Leaderless. The MRNA for the A repressor begins with 5'-AUG-3',
5'-AUG-3', which encodes the methionine residue that begins the
protein. What is unusual about this beginning? Would it cause the
MRNA to translate efficiently or not?
Chapter 31 Solutions
Biochemistry
Ch. 31 - Prob. 1PCh. 31 - Prob. 2PCh. 31 - Prob. 3PCh. 31 - Prob. 4PCh. 31 - Prob. 5PCh. 31 - Prob. 6PCh. 31 - Prob. 7PCh. 31 - Prob. 8PCh. 31 - Prob. 9PCh. 31 - Prob. 10P
Ch. 31 - Prob. 11PCh. 31 - Prob. 12PCh. 31 - Prob. 13PCh. 31 - Prob. 14PCh. 31 - Prob. 15PCh. 31 - Prob. 16PCh. 31 - Prob. 17PCh. 31 - Prob. 18PCh. 31 - Prob. 19PCh. 31 - Prob. 20PCh. 31 - Prob. 21PCh. 31 - Prob. 22PCh. 31 - Prob. 23PCh. 31 - Prob. 24PCh. 31 - Prob. 25PCh. 31 - Prob. 26PCh. 31 - Prob. 27PCh. 31 - Prob. 28PCh. 31 - Prob. 29PCh. 31 - Prob. 30PCh. 31 - Prob. 31PCh. 31 - Prob. 32PCh. 31 - Prob. 33PCh. 31 - Prob. 34PCh. 31 - Prob. 35PCh. 31 - Prob. 36PCh. 31 - Prob. 37PCh. 31 - Prob. 38PCh. 31 - Prob. 39PCh. 31 - Prob. 40PCh. 31 - Prob. 41PCh. 31 - Prob. 42PCh. 31 - Prob. 43PCh. 31 - Prob. 44PCh. 31 - Prob. 45PCh. 31 - Prob. 46PCh. 31 - Prob. 47PCh. 31 - Prob. 48PCh. 31 - Prob. 49PCh. 31 - Prob. 50PCh. 31 - Prob. 51PCh. 31 - Prob. 52P
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- Be sure to answer all parts. Write a possible mRNA sequence that codes for each peptide. a. His-Cys-Tyr-Val-Ser 5¹- b. Phe-Val-Thr-Tyr-Glu 5'- 5'- c. Trp-Phe-Asn-Gln -3' U -3' с Table 26.2 The Genetic Code-Triplets in Messenger RNA First Base (5' end) -3' U UUU UUC UUA UUG CUU CUC CUA CUG AUL Phe Phe Leu Leu Leu Leu Leu Leu la C UCU UCC UCA UCG CCU CCC CCA CCG Second Base A UAU UAC UAA UAG CAU CAC CAA CAG Ser Ser Ser Ser Pro Pro Pro Pro Tyr 55 Tyr Stop Stop His His Gin Gin G UGU UGC UGA UGG CGU CGC CGA CGG Cys Cys Stop Trp Arg Arg Arg Arg Third Base (3¹ ond) DUAC DU AG с А Аarrow_forwardthe correct reading frame. next thing to do is to write out the mRNA sequence using this sense strand reading frame. The last thing to do is to translate the sequence. The reading frame DNA sequence is: The mRNA sequence is: The polypeptide sequence is:arrow_forwardInitiation. Bacterial protein synthesis is initiated by: a. S-adenosylmethionyl tRNA b. Methionyl TRNA c. N-formylmethionyl tRNA d. N10-formyltetrahydrofolateN"-formyltetrahydrofolate †RNA „N10arrow_forward
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