Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 3, Problem 11EQ
Summary Introduction
To review:
The chromosomal composition and wing length of white eyes female flies.
Introduction:
White eyes and miniature wings are X-linked recessive traits, which means that the genes for eye color and wing length is present in the X chromosome. The presence of two recessive alleles is required to express these traits. Red eyes and long wings are dominant traits, so, the presence of single dominant allele for each of these traits is enough to express the traits. During meiosis, four gametes are produced and each contains either one X or one Y chromosome.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Female flies with white eyes and miniature wings (both X-linkedrecessive traits) were crossed to male flies with red eyes and longwings. On rare occasions, female offspring were produced withwhite eyes. If we assume these females are due to errors in meiosis, what would be the most likely chromosomal composition ofsuch flies? What would be their wing length?
Butterflies have an X-Y sex-determination system that is different from that of flies or humans. Female butterflies may be either XY or X0, while butterflies with two or more X chromosomes are males. This photograph shows a tiger swallowtail gynandromorph, which is half male (left side) and half female (right side). Given that the first division of the zygote divides the embryo into the future right and left halves of the butterfly, propose a hypothesis that explains how nondisjunction during the first mitosis might have produced this unusual-looking butterfly.
Question is also in the picture.
: In Drosophila, yellow body is due to an X-linked gene that is recessive to the gene forgray body.(a) A homozygous gray female is crossed with a yellow male. The F1 are intercrossed toproduce F2. Give the genotypes and phenotypes, along with the expected proportions, of theF1 and F2 progeny.(b) A yellow female is crossed with a gray male. The F1 are intercrossed to produce the F2.Give the genotypes and phenotypes, along with the expected proportions, of the F1 and F2progeny.(c) A yellow female is crossed with a gray male. The F1 females are backcrossed with graymales. Give the genotypes and phenotypes, along with the expected proportions, of the F2progeny.(d) If the F2 flies in part b mate randomly, what are the expected phenotypic proportions offlies in the F3??
Chapter 3 Solutions
Genetics: Analysis and Principles
Ch. 3.1 - 1. Which of the following is not found in a...Ch. 3.1 - When preparing a karyotype, which of the following...Ch. 3.1 - How many sets of chromosomes are found in a human...Ch. 3.2 - Binary fission a. is a form of asexual...Ch. 3.2 - Prob. 2COMQCh. 3.2 - What critical event occurs during the S phase of...Ch. 3.3 - 1. What is the function of the kinetochore during...Ch. 3.3 - Prob. 2COMQCh. 3.4 - Prob. 1COMQCh. 3.4 - Which phase of meiosis is depicted in the drawing...
Ch. 3.5 - In animals, a key difference between...Ch. 3.5 - Which of the following statements regarding plants...Ch. 3.6 - Which of the following is not one of the tenets of...Ch. 3.6 - A pea plant has the genotype TtRr. The independent...Ch. 3.6 - In mammals, sex is determined by a. the SRY gene...Ch. 3.6 - An abnormal fruit fly has two sets of autosomes...Ch. 3 - The process of binary fission begins with a single...Ch. 3 - 2. What is a homolog? With regard to genes and...Ch. 3 - What is a sister chromatid? Are sister chromatids...Ch. 3 - With regard to sister chromatids, which phase of...Ch. 3 - A species is diploid and has three chromosomes per...Ch. 3 - How does the attachment of kinetochore...Ch. 3 - 7. For the following events, specify whether they...Ch. 3 - Prob. 8CONQCh. 3 - A cell is diploid and contains three chromosomes...Ch. 3 - Prob. 10CONQCh. 3 - A eukaryotic cell is diploid and contains 10...Ch. 3 - Prob. 12CONQCh. 3 - 13. A cell has four pairs of chromosomes. Assuming...Ch. 3 - 14. With regard to question C13, how would the...Ch. 3 - Eukaryotic cells must sort their chromosomes...Ch. 3 - Why is it necessary for the chromosomes to...Ch. 3 - Nine-banded armadillos almost always give birth to...Ch. 3 - 18. A diploid species has four chromosomes per set...Ch. 3 - 19. Explain why the products of meiosis may not be...Ch. 3 - The period between meiosis I and meiosis II is...Ch. 3 - 21. List several ways in which telophase appears...Ch. 3 - Corn has 10 chromosomes per set, and the...Ch. 3 - The arctic fox has 50 chromosomes (25 per set),...Ch. 3 - 24. Let’s suppose that a gene affecting...Ch. 3 - 25. Describe the cellular differences between male...Ch. 3 - 26. At puberty, the testes contain a finite number...Ch. 3 - Describe the timing of meiosis I and II during...Ch. 3 - 28. Three genes (A, B, and C) are found on three...Ch. 3 - A woman with an abnormally long chromosome 13 (and...Ch. 3 - Assuming that such a fly would be viable, what...Ch. 3 - 31. What would be the sex of a human with each of...Ch. 3 - When studying living cells in a laboratory,...Ch. 3 - 2. In Morgan’s experiments, which result do you...Ch. 3 - 3. In his original studies of Figure 3.18, Morgan...Ch. 3 - How would you set up crosses to determine if a...Ch. 3 - 5. Occasionally during meiosis, a mistake can...Ch. 3 - Lets suppose that you have made a karyotype of a...Ch. 3 - Prob. 7EQCh. 3 - 8. White-eyed flies have a lower survival rate...Ch. 3 - A rare form of dwarfism that also included hearing...Ch. 3 - 10. Discuss why crosses (i.e., the experiments of...Ch. 3 - Prob. 11EQCh. 3 - 12. Experimentally, how do you think researchers...Ch. 3 - 1. In Figure 3.18, Morgan obtained a white-eyed...Ch. 3 - 3. Discuss the principles of the chromosome theory...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Assume that a meiotic-nondisjunction event causes trisomy 8 in a newborn. If two of the three copies of chromosome 8 are absolutely identical, at what point during meiosis did the nondisjunction event take place?arrow_forwardIn Drosophila, ebony body colour is produced by a recessive gene a and wild-type (gray) body colour by its dominant allele a+. Vestigial wings are governed by a recessive gene vg, and normal wing size (wild type) by its dominant allele vg+. If wild-type dihybrid flies are crossed and produce 256 progeny, how many of these progeny flies are expected in each phenotypic class?arrow_forwardThough an individual with abberations such as Robertsonian translocation may be phenotypically normal, they can generate gametes through meiosis that have atypical organizations of chromosomes, resulting in recurrent fetal abnormalities or miscarriages. Why, despite these Robertsonian translocations, are affected cells still able to generate typical gametes through meiosis?arrow_forward
- Table 8.1 shows that Turner syndrome occurs when an individual inherits one X chromosome but lacks a second sex chromosome. Can Turner syndrome be due to nondisjunction during oogenesis, spermatogenesis, or both? If a phenotypically normal couple has a color-blind child (due to a recessive X-linked allele) with Turner syndrome, did nondisjunction occur duringoogenesis or spermatogenesis in this child’s parents? Explain your answer.arrow_forwardA male Drosophila melanogaster has the genotype A/a; B/b; C/c; XD/Y (all genes are on separate chromosomes). How many different sperm genotypes can it produce through meiosis of one single pre-gametic (2n) cell? (remember, there is no crossing over in male Drosophila) Explain.arrow_forwardThe recessive allele s causes Drosophila to have small wings, and the s+ allele causes normal wings. This gene is known to be X linked. If a small-winged male is crossed with a homozygous wild-type female, what ratio of normal to small-winged flies can be expected in each sex in the F1? If F1 flies are intercrossed, what F2 progeny ratios are expected? What progeny ratios are predicted if F1 females are backcrossed with their father?arrow_forward
- Let’s suppose that two different X-linked genes exist in mice,designated with the letters N and L. Gene N exists in a dominant,normal allele and in a recessive allele, n, that is lethal. Similarly,gene L exists in a dominant, normal allele and in a recessive allele,l, that is lethal. Heterozygous females are normal, but males thatcarry either recessive allele are born dead. Explain whether or notit would be possible to map the distance between these two genesby making crosses and analyzing the number of living and deadoffspring. You may assume that you have strains of mice in whichfemales are heterozygous for one or both genes.arrow_forwardIN DROSOPHILA, AN X-LINKED RECESSIVE MUTATION, Xm CAUSES MINIATURE WINGS. LIST THE F₂ PHENOTYPIC RATIOS IF: A MINIATURE-WINGED FEMALE IS CROSSED WITH A NORMAL MALE AND A MINIATURE-WINGED MALE IS ● ● CROSSED WITH A NORMAL FEMALE. WHAT WOULD THE PHENOTYPIC RATIO FROM (A) BE IF THE MINIATURE- WINGED GENE WERE AUTOSOMAL? ASSUME IN ALL CASES THAT THE P1 INDIVIDUALS ARE TRUE-BREEDING.arrow_forwardThe following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyWhat information do you know based on the question and your…arrow_forward
- The following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyAnalyze data. Make a drawing. Make a calculation.arrow_forwardThe following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyA. Calculate the map distances separating the three genes.B. Is…arrow_forwardIn Drosophila,, the curled mutation (cu, chromosome 3, position 50.0) results in wings that curl up, while ebony (e, chromosome 3, position 70.7) results in a dark body. True breeding, wild type females are mated with true breeding males with curled wings and ebony bodies. Considering Drosophila notation, which of the following correctly diagrams the P1 cross? X X ++ e + + + O+ X + X + ■ + X + + + 3+ X X X X + + Y Y cu cu cu + cu cu J e e e e e (D e + cu cu (Darrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage LearningHuman Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY