a.
The equivalent resistance of the parallel circuit.
a.
Answer to Problem 14PP
The equivalent resistance of the network is
Explanation of Solution
Given:
Three resistors of value 15 Ω each are connected in parallel across a 30-V battery.
Formula used:
The equivalent resistance of a parallel branch of two resistances is given by,
Calculation:
Consider the circuit shown in Figure 1.
Figure 1
Here, the equivalent resistance of the parallel branches can be calculated using (1) as,
Conclusion:
The equivalent resistance of the circuit is
b.
The current in the circuit.
b.
Answer to Problem 14PP
The current through the circuit is
Explanation of Solution
Given:
Three resistors of value 15 Ω each are connected in parallel across a 30-V battery.
Formula used:
For the resistance of the circuit and supply voltage, the current can be calculated using the Ohm’s law as,
Calculation:
The current flowing through the circuit can be calculated by using the relation in (2), by substituting the total resistance obtained in the part a and the supply voltage V=30 V, as
Conclusion:
The current through the circuit is 6 A.
c.
The current flowing in each branch of the circuit.
c.
Answer to Problem 14PP
The current flowing through each of the branch is
Explanation of Solution
Given:
Three resistors of value 15 Ω each are connected in parallel across a 30-V battery.
Formula used:
The voltage in the each branch in a parallel circuit is equal. The current flowing through each of the branch is expressed in terms of the supply voltage and their individual resistance values as,
Calculation:
Here, since all the three branches have the same resistance values, the branch currents are the same. It can be calculated as,
Thus, the three branches has current of 2 A respectively.
Conclusion:
The current in each of the parallel branches is 2 A.
Chapter 23 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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