a.
Equivalent resistance of the circuit.
a.
Answer to Problem 51A
Equivalent resistance of circuit is,
Explanation of Solution
Given:
Resistance of first lamp,
Resistance of second lamp,
Potential difference,
Formula used:
For series circuit equivalent resistance is given by,
Where,
Calculation:
Now, substituting the value of
Conclusion:
Therefore, equivalent resistance of circuit is
b.
Current flowing through the circuit.
b.
Answer to Problem 51A
Current flowing through the circuit,
Explanation of Solution
Given:
Resistance of first lamp,
Resistance of second lamp,
Potential difference,
Formula used:
According to ohm’s law,
Where,
Calculation:
From part (a)
Now, substituting the value of V and R and solve.
Conclusion:
Therefore, current flowing through circuit is 1.698 A.
c.
Potential difference across each lamp.
c.
Answer to Problem 51A
Potential difference across first lamp,
Potential difference across second lamp,
Explanation of Solution
Given:
Resistance of first lamp,
Resistance of second lamp,
Potential difference,
Formula used:
According to ohm’s law,
Where,
Calculation:
From part (b)
Potential difference across first lamp.
Potential difference across second lamp.
Conclusion:
Therefore, potential difference across first lamp is 37.36 V and potential difference across second lamp is 7.64 V.
d.
Power used in each lamp.
d.
Answer to Problem 51A
Power used by first lamp,
Power used by second lamp,
Explanation of Solution
Given:
Resistance of first lamp,
Resistance of second lamp,
Potential difference,
Formula used:
Power is given by,
Where,
Calculation:
From part (b)
From part (c)
Power used by first lamp.
Power used by second lamp.
Conclusion:
Therefore, power used by first lamp is 63.43 W and power used by second lamp is 12.97 W.
Chapter 23 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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