(a)
Interpretation:
Interpret the reasons for the use of following step in the extraction of Argon gas from the liquid air.
The excess hydrogen is added into the mixture and then the mixture is ignited.
Concept introduction:
Fractional distillation is used to extract the Noble gas like Argon. Since the component gases of air have different boiling point therefore they separate at different temperatures but few gases which have almost same boiling point must be separate by different steps. For example argon and oxygen have same boiling point so oxygen must be removed with the help of different substances.
(b)
Interpretation:
Interpret the reasons for the use of following step in the extraction of Argon gas from the liquid air.
The mixture obtained in step 1 is passed over hot copper(III) oxide.
Concept introduction:
Fractional distillation is used to extract the Noble gas like Argon. Since the component gases of air have different boiling point therefore they separate at different temperatures but few gases which have almost same boiling point must be separate by different steps. For example argon and oxygen have same boiling point so oxygen must be removed with the help of different substances.
(c)
Interpretation:
Interpret the reasons for the use of following step in the extraction of Argon gas from the liquid air.
The mixture obtained in step 2 is passed over dehydrated zeolite material.
Concept introduction:
Fractional distillation is used to extract the Noble gas like Argon. Since the component gases of air have different boiling point therefore they separate at different temperatures but few gases which have almost same boiling point must be separate by different steps. For example argon and oxygen have same boiling point so oxygen must be removed with the help of different substances.
Want to see the full answer?
Check out a sample textbook solutionChapter 22 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
- When solutions of BaCl2 and Na2SO4 are mixed, the mixture becomes cloudy. After a few days, a white solid is observed on the bottom of the beaker with a clear liquid above it. (a) Write a balanced equation for the reaction that occurs. (b) Why is the solution cloudy at first? (c) What happens during the few days of waiting?arrow_forwardWrite a chemical equation representing the decomposition of water into two gaseous products. What are the products?arrow_forwardA student was given a 1.6240-g sample of a mixture of sodium nitrate and sodium chloride and was asked to find the percentage of each compound in the mixture. She dissolved the sample and added a solution that contained an excess of silver nitrate. The silver ion precipitated all of the chloride ion in the mixture as silver chloride. It was filtered, dried, and weighed. Its mass was 2.056g. What was the percentage of each compound in the mixture?arrow_forward
- A solution is defined as a homogeneous mixture. Is a small sample of air a solution? Is the atmosphere a solution?arrow_forwardDescribe the use of gravimetric analysis to determine the percentage of chlorine in a water-soluble unknown solid.arrow_forwardRelative solubilities of salts in liquid ammonia can differsignificantly from those in water. Thus, silver bromide issoluble in ammonia, but barium bromide is not (thereverse of the situation in water). Write a balanced equation for the reaction of anammonia solution of barium nitrate with an ammoniasolution of silver bromide. Silver nitrate is soluble inliquid ammonia. What volume of a 0.50 M solution of silver bromidewill react completely with 0.215 L of a 0.076 M solutionof barium nitrate in ammonia? What mass of barium bromide will precipitate fromthe reaction in part (b)?arrow_forward
- A 2.5624-g sample of a pure solid alkali metal chloride is dissolved in water and treated with excess silver nitrate. The resulting precipitate, filtered and dried, weighs 3.03707 g. What was the percent by mass of chloride ion in the original compound? What is the identity of the salt?arrow_forwardA student weighs out a 4.80-g sample of aluminum bromide, transfers it to a 100-mL volumetric flask, adds enough water to dissolve it, and then adds water to the 100-mL mark. What is the molarity of aluminum bromide in the resulting solution?arrow_forward
- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning