General Chemistry: Principles and Modern Applications (11th Edition)
General Chemistry: Principles and Modern Applications (11th Edition)
11th Edition
ISBN: 9780132931281
Author: Ralph H. Petrucci, F. Geoffrey Herring, Jeffry D. Madura, Carey Bissonnette
Publisher: PEARSON
Question
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Chapter 22, Problem 7E
Interpretation Introduction

(a)

Interpretation:

The probable geometric structure of XeO2 is to be determined using VSEPR theory.

Concept introduction:

  • Valence shell electron pair repulsion theory (VSEPR) predicts the geometry of the molecules depending on the number of bond pair of electrons and number of lone pair of electrons.
  • Electron pair geometry includes both bonded atoms and lone pairs, while molecular geometry only considers the bonded atoms.
  • The geometries corresponding to different steric number is shown −
  • Steric number = number of bond pairs +number of lone pairs
VSEPR GEOMETRIES
Steric number 0 lone pairs 1 lone pair 2 lone pairs 3 lone pairs 4 lone pairs
2 General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  1
Linear
3 Trigonal planar
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  2
Bent
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  3
4 Tetrahedral
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  4
Trigonal pyramidal
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  5
Bent
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  6
5 TrigonalBipyramidal
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  7
Seesaw
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  8
T-shape
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  9
Linear
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  10
6 Octahedral
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  11
Square pyramidal
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  12
Square planar
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  13
T-shape
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  14
Linear
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  15

Interpretation Introduction

(b)

Interpretation:

The probable geometric structure of XeO4 is to be determined using VSEPR theory.

Concept introduction:

  • Valence shell electron pair repulsion theory (VSEPR) predicts the geometry of the molecules depending on the number of bond pair of electrons and number of lone pair of electrons.
  • Electron pair geometry includes both bonded atoms and lone pairs, while molecular geometry only considers the bonded atoms.
  • The geometries corresponding to different steric number is shown −
  • Steric number = number of bond pairs +number of lone pairs
VSEPR GEOMETRIES
Steric number 0 lone pairs 1 lone pair 2 lone pairs 3 lone pairs 4 lone pairs
2 General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  16
Linear
3 Trigonal planar
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  17
Bent
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  18
4 Tetrahedral
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  19
Trigonal pyramidal
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  20
Bent
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  21
5 TrigonalBipyramidal
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  22
Seesaw
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  23
T-shape
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  24
Linear
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  25
6 Octahedral
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  26
Square pyramidal
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  27
Square planar
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  28
T-shape
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  29
Linear
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  30

Interpretation Introduction

(c)

Interpretation:

The probable geometric structure of XeF3+ is to be determined using VSEPR theory.

Concept introduction:

  • Valence shell electron pair repulsion theory (VSEPR) predicts the geometry of the molecules depending on the number of bond pair of electrons and number of lone pair of electrons.
  • Electron pair geometry includes both bonded atoms and lone pairs, while molecular geometry only considers the bonded atoms.
  • The geometries corresponding to different steric number is shown −
  • Steric number = number of bond pairs +number of lone pairs
VSEPR GEOMETRIES
Steric number 0 lone pairs 1 lone pair 2 lone pairs 3 lone pairs 4 lone pairs
2 General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  31
Linear
3 Trigonal planar
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  32
Bent
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  33
4 Tetrahedral
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  34
Trigonal pyramidal
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  35
Bent
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  36
5 Trigonal Bipyramidal
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  37
Seesaw
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  38
T-shape
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  39
Linear
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  40
6 Octahedral
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  41
Square pyramidal
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  42
Square planar
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  43
T-shape
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  44
Linear
General Chemistry: Principles and Modern Applications (11th Edition), Chapter 22, Problem 7E , additional homework tip  45

Blurred answer

Chapter 22 Solutions

General Chemistry: Principles and Modern Applications (11th Edition)

Ch. 22 - Prob. 11ECh. 22 - Prob. 12ECh. 22 - Prob. 13ECh. 22 - Prob. 14ECh. 22 - Make a general prediction about which of the...Ch. 22 - The following properties of astatine have been...Ch. 22 - Prob. 17ECh. 22 - Prob. 18ECh. 22 - Prob. 19ECh. 22 - Prob. 20ECh. 22 - Prob. 21ECh. 22 - Prob. 22ECh. 22 - Prob. 23ECh. 22 - Prob. 24ECh. 22 - Each of the following compounds decomposes to...Ch. 22 - Ozone is a power oxidizing agent. Using ozone as...Ch. 22 - Prob. 27ECh. 22 - Prob. 28ECh. 22 - Prob. 29ECh. 22 - Prob. 30ECh. 22 - Prob. 31ECh. 22 - Prob. 32ECh. 22 - Prob. 33ECh. 22 - In water, O2(aq) is a strong base. If 100.0 mg of...Ch. 22 - The conversion of O2(g) to O2(g) can be...Ch. 22 - Prob. 36ECh. 22 - Prob. 37ECh. 22 - Prob. 38ECh. 22 - Prob. 39ECh. 22 - Prob. 40ECh. 22 - Prob. 41ECh. 22 - Joseph Priestley, e British chemist, was credited...Ch. 22 - Give an appropriate name to each of theb following...Ch. 22 - Prob. 44ECh. 22 - Give a specific example of a chemical equation...Ch. 22 - Prob. 46ECh. 22 - Prob. 47ECh. 22 - Prob. 48ECh. 22 - Prob. 49ECh. 22 - Prob. 50ECh. 22 - Prob. 51ECh. 22 - Prob. 52ECh. 22 - Prob. 53ECh. 22 - Prob. 54ECh. 22 - Prob. 55ECh. 22 - Prob. 56ECh. 22 - Prob. 57ECh. 22 - Prob. 58ECh. 22 - Prob. 59ECh. 22 - One reaction that competes with reaction (22.41),...Ch. 22 - Prob. 61ECh. 22 - Prob. 62ECh. 22 - Draw plausible Lewis structures for a....Ch. 22 - Both nitramide and hyponitrous acid have the...Ch. 22 - Prob. 65ECh. 22 - Prob. 66ECh. 22 - Prob. 67ECh. 22 - Prob. 68ECh. 22 - Prob. 69ECh. 22 - Prob. 70ECh. 22 - Use data from Table 7.2 (page 273) to calculate...Ch. 22 - Prob. 72ECh. 22 - Prob. 73ECh. 22 - Prob. 74ECh. 22 - Prob. 75ECh. 22 - What volume of H2(g) at 25C and 752 mmHg is...Ch. 22 - Prob. 77ECh. 22 - How many grams of CaH2(s) are required to generate...Ch. 22 - Prob. 79ECh. 22 - On the basis of molecular orbital theory, would...Ch. 22 - Prob. 81IAECh. 22 - Prob. 82IAECh. 22 - Prob. 83IAECh. 22 - The photograph was taken after a few drops of a...Ch. 22 - Prob. 85IAECh. 22 - Prob. 86IAECh. 22 - Prob. 87IAECh. 22 - Despite the fact that it has the higher molecular...Ch. 22 - The text mentions that ammonium perchlorate is an...Ch. 22 - Prob. 90IAECh. 22 - Prob. 91IAECh. 22 - Prob. 92IAECh. 22 - Refer to Figure 11-25 to arrange the following...Ch. 22 - Prob. 94IAECh. 22 - Prob. 95IAECh. 22 - Estimate the percent dissociation of CI2(g) into...Ch. 22 - Prob. 97IAECh. 22 - The structure of N(SiH2)2 involves a planar...Ch. 22 - Prob. 99IAECh. 22 - Refer to the Integrative Example on page 1082....Ch. 22 - The bond energies of CIz and 159kJmol1 are 243 and...Ch. 22 - Prob. 102IAECh. 22 - Prob. 103IAECh. 22 - Prob. 104IAECh. 22 - Prob. 105IAECh. 22 - The heavier halogens (CI, Br, and I) form...Ch. 22 - Prob. 107IAECh. 22 - Chemists have successfully synthesized the ionic...Ch. 22 - Prob. 109IAECh. 22 - Various thermochemical cycles are being explored...Ch. 22 - The decomposition of aqueous hydrogen peroxide is...Ch. 22 - Both in this chapter and in Chapter 19, we have...Ch. 22 - Prob. 113FPCh. 22 - The so-called pyroanions, X2O7n+ , form a series...Ch. 22 - A description of bonding in XeF2 based on the...Ch. 22 - Prob. 116FPCh. 22 - Prob. 117SAECh. 22 - Prob. 118SAECh. 22 - Prob. 119SAECh. 22 - Which of the following can oxidize Br to Br2 in...Ch. 22 - Prob. 121SAECh. 22 - Prob. 122SAECh. 22 - Prob. 123SAECh. 22 - Prob. 124SAECh. 22 - Prob. 125SAECh. 22 - Prob. 126SAECh. 22 - Prob. 127SAECh. 22 - Give a practical laboratory method that you might...Ch. 22 - Prob. 129SAECh. 22 - Prob. 130SAECh. 22 - Prob. 131SAECh. 22 - Prob. 132SAECh. 22 - Prob. 133SAECh. 22 - Prob. 134SAECh. 22 - Prob. 135SAE
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