EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
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Chapter 2, Problem 2.4Q
To determine
To explain whether the tensile true stress-true strain curve is higher than the engineering strain-stress curve holds true for compression test.
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Draw a typical stress vs strain tensile test curve for the following materials (two seperate graphs) and label the axis.
A ductile metallic test specimen that is stretched to failure displaying a characteristic yield point and show the following parts on the curve.
1- Yield point
2- Ultimate Tensile Strength
3- Breaking point
4- Elastic Region
5- Plastic Region
6- Necking region
The following data were obtained from the tensile test of Aluminum alloy. The initial diameter of testspecimen was 0.505 inch and gauge length was 2.0 inch. Plot the stress strain diagram and determine(a) Proportional Limit (b) Modulus of Elasticity (c) Yield Stress at 0.2% offset (d) Ultimate Stress and(e) Nominal Rupture Stress.
QUESTION ONE
(a) Distinguish between physical and mechanical properties of materials. Give two examples
of each.
(b) Explain why in a stress versus strain curve, the plastic portion of the graph after necking
tends to drop (ie the force drops) despite that the tension is increasing.
(c) A tensile test uses a copper test specimen that has a gauge length of 80 mm and a di.ameter
of 16 mm. During the test, the specimen yields under a load of 9,600 N. The corresponding
gauge length is 80.24 mm. The maximum load reached is 148,000 N at a gauge length
of 94.2 mm, while fracture happens at a load of 12,800 N and a gauge length of 102 6 mm
Determine the following:
(i) Modulus of elasticity E
(ii) Yield strength Oy
(iii) Fracture strength, ơt
(iv) Tensile strength OTs.
1
Chapter 2 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 2 - Prob. 2.1QCh. 2 - Prob. 2.2QCh. 2 - Prob. 2.3QCh. 2 - Prob. 2.4QCh. 2 - Prob. 2.5QCh. 2 - Prob. 2.6QCh. 2 - Prob. 2.7QCh. 2 - Prob. 2.8QCh. 2 - Prob. 2.9QCh. 2 - Prob. 2.10Q
Ch. 2 - Prob. 2.11QCh. 2 - Prob. 2.12QCh. 2 - Prob. 2.13QCh. 2 - Prob. 2.14QCh. 2 - Prob. 2.15QCh. 2 - Prob. 2.16QCh. 2 - Prob. 2.17QCh. 2 - Prob. 2.18QCh. 2 - Prob. 2.19QCh. 2 - Prob. 2.20QCh. 2 - Prob. 2.21QCh. 2 - Prob. 2.22QCh. 2 - Prob. 2.23QCh. 2 - Prob. 2.24QCh. 2 - Prob. 2.25QCh. 2 - Prob. 2.26QCh. 2 - Prob. 2.27QCh. 2 - Prob. 2.28QCh. 2 - Prob. 2.29QCh. 2 - Prob. 2.30QCh. 2 - Prob. 2.31QCh. 2 - Prob. 2.32QCh. 2 - Prob. 2.33QCh. 2 - Prob. 2.34QCh. 2 - Prob. 2.35QCh. 2 - Prob. 2.36QCh. 2 - Prob. 2.37QCh. 2 - Prob. 2.38QCh. 2 - Prob. 2.39QCh. 2 - Prob. 2.40QCh. 2 - Prob. 2.41QCh. 2 - Prob. 2.42QCh. 2 - Prob. 2.43QCh. 2 - Prob. 2.44QCh. 2 - Prob. 2.45QCh. 2 - Prob. 2.46QCh. 2 - Prob. 2.47QCh. 2 - Prob. 2.48QCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101P
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- Q2/ Aluminum tensile specimen with 12.5mm diameter, a gauge length of 50.8mm and the final diameter was 10.5mm. • Plot the engineering stress-strain curve and the true stress- strain curve. Determine proportion limit, young's modulus, the yield point, the ultimate tensile strength, the failure stress on drawing? • Determine Ductility? • Determine Resilience modulus and toughness modulus? 0.006 0.008 0.012 0.017 Strain mm/mm Apparent Stress N/mm 100 0.004 0.22 0.25 0.27 150 200 290 325 480 450 410 True stress N/mm 100.1 150.3 201 326 400 500 550 620arrow_forwardThe data shown in the table below were obtained from a tensile test of high-strength steel. The test specimen had a diameter of 13mm and a gage length of 50mm. At fracture, the elongation between the gage marks was 3.0mm and the minimum diameter was 10.7mm. Plot the conventional stress-strain curve for the steel and determine the propotional limit, modulus of elasticity (i.e the slope of the initial part of the stress-strain curve), yield stress at 0.1% offset, ultimate stress, percent elongation in 50mm, and percent reduction area. TENSILE-TEST DATA Load(kN) Elongation(mm) 5 0.005 10 0.015 30 0.048 50 0.084 60 0.099 64.5 0.109 67.0 0.119 68.0 0.137 69.0 0.160 70.0 0.229 72.0 0.259 76.0 0.330 84.0 0.584 92.0 0.853 100.0 1.288 112.0 2.814 113.0 Fracturearrow_forwardBriefly discuss the differences between the Engineering Stress versus Engineering Strain and the True Stress versus True Strain Diagrams for the test specimen. Briefly explain why the two plots are different. When is the use of Engineering Stress versus Engineering Strain invalid?arrow_forward
- Draw a typical stress vs strain tensile test curve for the following material and label the axis. A typical brittle material subjected to a tensile stress that has been applied to the material till the sample breaks. 1- label the axis and draw the curve for a brittle material. 2- indicate the maximum strength of the material. 3- show on the portion of the curve where young's modulus can be calculated.arrow_forwardYour manager asked you to explain the difference between three-point bending test and four-pointbending test by using a standard specimen each one has the following dimensions:1. Force = 30 KN.2. Thickness= 5 cm.3. Width = 10 cm.4. Length = 25 cm.Calculate the stress on each specimen then justify your answerarrow_forwardEngineering strain of a mild steel sample is recorded as 0.100%. The true strain isarrow_forward
- The diagram shows a plot from an uniaxial test of an unknown metal. The uniaxial tensile test specimen had an original cross-sectional radius of 3.0 mm, an initial gauge length of 42 mm. At failure, the cross-sectional radius was 1.2 mm. Determine the yield strength of the unknown metal and the true stress at failure.arrow_forwardIn True stress-true-strain curve in tension of solid metal cylinder 45 mm high and 8 mm in diameter, two pairs of values of stress and strain were given for the specimen metal after it had yielded (1) true stress = 217 MPa, and true strain = 0.35; and (2) true stress = 259 MPa, and true strain = 0.68. Based on these data points, determine the following: a) The average flow stress that the metal experiences if it is subjected to a stress that is equal to its strength coefficient K. b) The work done that the metal experiences if it is subjected to elongation in height of 45% c) If during the deformation the relative speed = 20 mm/s, determine the strain rate at h = 50 mm and h = 70 mm.arrow_forwardQuestion 4 You do a series of tensile tests on plates of a magnesium alloy that have been subjected to prior cold rolling to true plastic strains of 0.1, 0.2 and 0.3. The resulting true stress-true strain curves are shown below (including a zoomed in version expanding on the small strain region). It is reasonable to approximate the the 0.2% offset yield strength of the magnesium as ✓ MPa for 0.1 plastic strain, ✓ MPa for 0.2 and ✓ MPa for 0.3. Assuming the yield strength is proportional to the square root of the prior true plastic strain results in a hardening coefficient of approximately k= ✓ MPa. Hence, we can predict that we need a prior plastic strain of approximately ✓to obtain a hgth of 120 MPa True Stress (MPa) 250 200 100 85 95 50 105 115 125 135 145 300 350 0.12 0.14 150 0.16 0.18 155 165 175 200 250 0.1 True Stress (MPa) Ep = 0.1 Zoomed version of left plotarrow_forward
- Was there a discrepancy between the values of Young's Modulus found in the tensile test and the bending test? If so, why does this occur?arrow_forwardThe following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 143 kN. - Length of the specimen is 29 mm. - The yield strength is 71 kN/mm2. - The percentage of elongation is 48 %. Determine the following Diameter of the specimen, Final length of the specimen, Stress under an elastic load of 18 kN, Young's Modulus if the elongation is 1 mm at 18 kN and Final diameter if the percentage of reduction in area is 29 %. FIND: Young's Modulus of the Specimen (in N/mm2) Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm)arrow_forwardThe following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 143 kN. - Length of the specimen is 29 mm. - The yield strength is 71 kN/mm2. - The percentage of elongation is 48 %. Determine the following Diameter of the specimen, Final length of the specimen, Stress under an elastic load of 18 kN, Young's Modulus if the elongation is 1 mm at 18 kN and Final diameter if the percentage of reduction in area is 29 %. Initial Cross-sectional Area 2.01 mm2. The Diameter of the Specimen 1.59 mm. Final Length of the Specimen 42.92 mm. Stress at the elastic load 8955.22 N/mm2. Find: Young's Modulus of the Specimen (in N/mm2) Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm)arrow_forward
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