Chemistry: An Atoms-Focused Approach
Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393912340
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
Question
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Chapter 19, Problem 19.114QA
Interpretation Introduction

To calculate:

 Hrxn0 for  the given reactions of methanogenic bacteria.

Expert Solution & Answer
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Answer to Problem 19.114QA

Solution:

a) Hrxn0=-252.9 kJ

b) Hrxn0=-234.7 kJ

Explanation of Solution

1) Concept:

We are given two balanced reactions of methanogenic bacteria and asked to find the H°rxn for each given reaction. We can find the standard enthalpy formation values for CH4g, CO2g,CH3OH l, H2(g)and H2Ol_ can find out the standard enthalpy formation values for  from the Appendix and find the standard enthalpy for the reaction using the following equation:

H°rxn= nproductsHf, products0- nreactantsHf, reactants0

2) Formula:

H°rxn= nproductsHf, products0- nreactantsHf, reactants0

3) Given:

i) 4H2g+CO2gCH4g+2H2Ol   

ii) 4CH3OHl3CH4g+CO2g+2H2Ol

4) Calculations:

Values of standard enthalpies of formation of H2g, CO2g, CH4g,

H2Og, CH3OH(l) are taken from Appendix 4 are:

Hf0(kJ/mol)
CH3OH l -238.7
H2g 0.0
CO2g -393.5
H2O l -285.8
CH4(g) -74.8

a) H°rxn for reaction: 4H2g+CO2gCH4g+2H2Ol

H°rxn= nproductsHf, products0- nreactantsHf, reactants0

H°rxn=1 mol CH4g×HCH4g0+2 mol H2Ol×HH2Ol0-4 mol H2×HH2g0+1 mol CO2g×HCO2g0

H°rxn=1 mol CH4g×-74.8kJmol+2 mol H2Ol×-285.8kJmol-4 mol H2× 0.0kJmol+1 mol CO2g×-393.5kJmol

H°rxn=-74.8 kJ+(-571.6 kJ)--393.5 kJ=-252.9 kJ

b) H°rxn for reaction: 4CH3OHl3CH4g+CO2g+2H2Ol

H°rxn= nproductsHf, products0- nreactantsHf, reactants0

H°rxn=3 mol CH4g×HCH4g0+1 mol CO2g×HCO2g0+2 mol H2Ol×HH2Ol0-(4 mol CH3OH(l)×HCH3OHl0)

H°rxn=3 mol CH4g×-74.8kJmol+1 mol CO2g×-393.5kJmol+2 mol H2Ol×-285.8kJmol-(4 mol CH3OHl×-238.7kJmol)

H°rxn=-1189.5 kJ--954.8 kJ=-234.7 kJ

Conclusion:

Using standard enthalpy values from Appendix 4, we calculated the enthalpy of reactions of methanogenic bacteria.

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Chapter 19 Solutions

Chemistry: An Atoms-Focused Approach

Ch. 19 - Prob. 19.11VPCh. 19 - Prob. 19.12VPCh. 19 - Prob. 19.13QACh. 19 - Prob. 19.14QACh. 19 - Prob. 19.15QACh. 19 - Prob. 19.16QACh. 19 - Prob. 19.17QACh. 19 - Prob. 19.18QACh. 19 - Prob. 19.19QACh. 19 - Prob. 19.20QACh. 19 - Prob. 19.21QACh. 19 - Prob. 19.22QACh. 19 - Prob. 19.23QACh. 19 - Prob. 19.24QACh. 19 - Prob. 19.25QACh. 19 - Prob. 19.26QACh. 19 - Prob. 19.27QACh. 19 - Prob. 19.28QACh. 19 - Prob. 19.29QACh. 19 - Prob. 19.30QACh. 19 - Prob. 19.31QACh. 19 - Prob. 19.32QACh. 19 - Prob. 19.33QACh. 19 - Prob. 19.34QACh. 19 - Prob. 19.35QACh. 19 - Prob. 19.36QACh. 19 - Prob. 19.37QACh. 19 - Prob. 19.38QACh. 19 - Prob. 19.39QACh. 19 - Prob. 19.40QACh. 19 - Prob. 19.41QACh. 19 - Prob. 19.42QACh. 19 - Prob. 19.43QACh. 19 - Prob. 19.44QACh. 19 - Prob. 19.45QACh. 19 - Prob. 19.46QACh. 19 - Prob. 19.47QACh. 19 - Prob. 19.48QACh. 19 - Prob. 19.49QACh. 19 - Prob. 19.50QACh. 19 - Prob. 19.51QACh. 19 - Prob. 19.52QACh. 19 - Prob. 19.53QACh. 19 - Prob. 19.54QACh. 19 - Prob. 19.55QACh. 19 - Prob. 19.56QACh. 19 - Prob. 19.57QACh. 19 - Prob. 19.58QACh. 19 - Prob. 19.59QACh. 19 - Prob. 19.60QACh. 19 - Prob. 19.61QACh. 19 - Prob. 19.62QACh. 19 - Prob. 19.63QACh. 19 - Prob. 19.64QACh. 19 - Prob. 19.65QACh. 19 - Prob. 19.66QACh. 19 - Prob. 19.67QACh. 19 - Prob. 19.68QACh. 19 - Prob. 19.69QACh. 19 - Prob. 19.70QACh. 19 - Prob. 19.71QACh. 19 - Prob. 19.72QACh. 19 - Prob. 19.73QACh. 19 - Prob. 19.74QACh. 19 - Prob. 19.75QACh. 19 - Prob. 19.76QACh. 19 - Prob. 19.77QACh. 19 - Prob. 19.78QACh. 19 - Prob. 19.79QACh. 19 - Prob. 19.80QACh. 19 - Prob. 19.81QACh. 19 - Prob. 19.82QACh. 19 - Prob. 19.83QACh. 19 - Prob. 19.84QACh. 19 - Prob. 19.85QACh. 19 - Prob. 19.86QACh. 19 - Prob. 19.87QACh. 19 - Prob. 19.88QACh. 19 - Prob. 19.89QACh. 19 - Prob. 19.90QACh. 19 - Prob. 19.91QACh. 19 - Prob. 19.92QACh. 19 - Prob. 19.93QACh. 19 - Prob. 19.94QACh. 19 - Prob. 19.95QACh. 19 - Prob. 19.96QACh. 19 - Prob. 19.97QACh. 19 - Prob. 19.98QACh. 19 - Prob. 19.99QACh. 19 - Prob. 19.100QACh. 19 - Prob. 19.101QACh. 19 - Prob. 19.102QACh. 19 - Prob. 19.103QACh. 19 - Prob. 19.104QACh. 19 - Prob. 19.105QACh. 19 - Prob. 19.106QACh. 19 - Prob. 19.107QACh. 19 - Prob. 19.108QACh. 19 - Prob. 19.109QACh. 19 - Prob. 19.110QACh. 19 - Prob. 19.111QACh. 19 - Prob. 19.112QACh. 19 - Prob. 19.113QACh. 19 - Prob. 19.114QACh. 19 - Prob. 19.115QACh. 19 - Prob. 19.116QACh. 19 - Prob. 19.117QACh. 19 - Prob. 19.118QACh. 19 - Prob. 19.119QACh. 19 - Prob. 19.120QACh. 19 - Prob. 19.121QACh. 19 - Prob. 19.122QACh. 19 - Prob. 19.123QACh. 19 - Prob. 19.124QACh. 19 - Prob. 19.125QACh. 19 - Prob. 19.126QACh. 19 - Prob. 19.127QACh. 19 - Prob. 19.128QACh. 19 - Prob. 19.129QACh. 19 - Prob. 19.130QACh. 19 - Prob. 19.131QACh. 19 - Prob. 19.132QACh. 19 - Prob. 19.133QACh. 19 - Prob. 19.134QACh. 19 - Prob. 19.135QACh. 19 - Prob. 19.136QACh. 19 - Prob. 19.137QACh. 19 - Prob. 19.138QACh. 19 - Prob. 19.139QACh. 19 - Prob. 19.140QACh. 19 - Prob. 19.141QACh. 19 - Prob. 19.142QA
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