(a)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction:
In order to give the IUPAC name to the alcohol following steps are followed:
1. The parent (longest)
2. The ending of the parent chain from alkane (-e) is changed to -ol and the number is used to locate the -OH group of alcohol.
3. Name should be written in alphabetical order and numbering should be done in such a way that hydroxy group gets lowest number.
4. Configuration should be specified is there exist any cis-trans isomerism.
For number of carbons atoms in chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
(b)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction:
In order to give the IUPAC name to the alcohol following steps are followed:
1. The parent (longest) alkane chain is identified.
2. The ending of the parent chain from alkane (-e) is changed to -ol and the number is used to locate the -OH group of alcohol.
3. Name should be written in alphabetical order and numbering should be done in such a way that hydroxy group gets lowest number.
4. Configuration should be specified is there exist any cis-trans isomerism.
For number of carbons atoms in chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
(c)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction:
In order to give the IUPAC name to the alcohol following steps are followed:
1. The parent (longest) alkane chain is identified.
2. The ending of the parent chain from alkane (-e) is changed to -ol and the number is used to locate the -OH group of alcohol.
3. Name should be written in alphabetical order and numbering should be done in such a way that hydroxy group gets lowest number.
4. Configuration should be specified is there exist any cis-trans isomerism.
For number of carbons atoms in chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
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Check out a sample textbook solutionChapter 17 Solutions
Basic Chemistry
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