Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
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Chapter 17.1, Problem 6R
To determine

To Compare: The mass of the new penny with that of the old penny.

Expert Solution & Answer
Check Mark

Answer to Problem 6R

The new penny’s mass is 19% less than the old penny’s mass.

Explanation of Solution

Given info:

The old mass of the penny is, mold=3.1g

The new mass of the penny is, mnew=2.5g

Formula used:

The mass percentage is given as,

  mass%=changeinmassoldmass×100=Δmmold×100

Calculation:

Now substitute the value of masses in the above formula

  mass%=Δmmold×100=moldmnewmold×100=3.1g2.5g3.1g×100=19%

Conclusion:

Hence, the mass of the new penny is 19% less than the old penny’s mass.

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