General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
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Question
Chapter 17, Problem 82P
Interpretation Introduction
Interpretation:
The products formed when following ester is hydrolyzed with H2O should be determined:
Concept Introduction:
Alcohols are the organic compounds with general chemical formula of R-OH whereas carboxylic acids are the organic molecules with R-COOH as general chemical formula.
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17. Which functional groups are in the following molecule of aspirin?
HO,
a benzene ring, an ester, a ketone, and an alcohol
b. a benzene ring, two ketones, an ether, and an alcohol
a benzene ring, a carboxylic acid, an ether, and a ketone
d. a benzene ring, a carboxylic acid, and an ester
a.
c.
Why is the water solubility of a carboxylate salt greater than that of its parent carboxylic acid?
A) A carboxylate salt is an ionic compound which is soluble in water.
B) A carboxylate salt is less polar than its parent carboxylic acid.
C) A carboxylate salt has a lower boiling point than its parent carboxylic acid.
D) A carboxylate salt is more readily reduced to an aldehyde than its parent carboxylic acid.
What is the equation for the dissociation of a carboxylic acid in water?
Chapter 17 Solutions
General, Organic, and Biological Chemistry - 4th edition
Ch. 17.1 - Draw out each compound to clearly show what groups...Ch. 17.1 - Prob. 17.2PCh. 17.1 - (a) Label each functional group in lisinopril, a...Ch. 17.2 - Give the IUPAC name for each compound. a. b. c.Ch. 17.2 - Give the structure corresponding to each IUPAC...Ch. 17.2 - Prob. 17.5PCh. 17.2 - Give an acceptable name for each ester. a. CH3(...Ch. 17.2 - Prob. 17.6PCh. 17.2 - Prob. 17.7PCh. 17.2 - Prob. 17.8P
Ch. 17.2 - Prob. 17.9PCh. 17.3 - Which compound in each pair has the higher boiling...Ch. 17.4 - Prob. 17.11PCh. 17.5 - In addition to ethyl butanoate (Section 17.5),...Ch. 17.6 - Prob. 17.3PPCh. 17.6 - Prob. 17.13PCh. 17.6 - Which compound ¡n each pair ¡s more water soluble?...Ch. 17.6 - Prob. 17.5PPCh. 17.6 - Prob. 17.14PCh. 17.6 - Prob. 17.15PCh. 17.7 - Ibuprofen is another pain reliever that is a...Ch. 17.8 - Prob. 17.6PPCh. 17.8 - Prob. 17.17PCh. 17.8 - Prob. 17.18PCh. 17.8 - Prob. 17.7PPCh. 17.8 - Prob. 17.19PCh. 17.9 - Prob. 17.8PPCh. 17.9 - Prob. 17.20PCh. 17.9 - Prob. 17.21PCh. 17.9 - Prob. 17.22PCh. 17.9 - Prob. 17.9PPCh. 17.9 - Prob. 17.23PCh. 17.9 - Prob. 17.24PCh. 17.10 - Prob. 17.10PPCh. 17.10 - Prob. 17.25PCh. 17.11 - Prob. 17.26PCh. 17 - Prob. 27PCh. 17 - Prob. 28PCh. 17 - Prob. 29PCh. 17 - Prob. 30PCh. 17 - Prob. 31PCh. 17 - Prob. 32PCh. 17 - Prob. 33PCh. 17 - Prob. 34PCh. 17 - Prob. 35PCh. 17 - Give an acceptable name for each ester. a. CH3CO2(...Ch. 17 - Prob. 37PCh. 17 - Prob. 38PCh. 17 - Prob. 39PCh. 17 - Prob. 40PCh. 17 - Prob. 41PCh. 17 - Prob. 42PCh. 17 - Prob. 43PCh. 17 - Draw the structure corresponding to each name. a....Ch. 17 - Draw the structure corresponding to each name. a....Ch. 17 - Draw the structure corresponding to each name. a....Ch. 17 - Prob. 47PCh. 17 - Prob. 48PCh. 17 - Prob. 49PCh. 17 - Prob. 50PCh. 17 - Prob. 51PCh. 17 - Prob. 52PCh. 17 - Prob. 53PCh. 17 - Prob. 54PCh. 17 - What ester is formed when butanoic acid...Ch. 17 - Prob. 56PCh. 17 - Prob. 57PCh. 17 - Prob. 58PCh. 17 - Prob. 59PCh. 17 - Prob. 60PCh. 17 - Prob. 61PCh. 17 - Prob. 62PCh. 17 - Prob. 63PCh. 17 - Prob. 64PCh. 17 - Prob. 65PCh. 17 - Prob. 66PCh. 17 - What products are formed when each ester is...Ch. 17 - Prob. 68PCh. 17 - Prob. 69PCh. 17 - Prob. 70PCh. 17 - Prob. 71PCh. 17 - Prob. 72PCh. 17 - Prob. 73PCh. 17 - Prob. 74PCh. 17 - Draw the products formed in each reaction. a. b....Ch. 17 - Draw the products formed in each reaction. a. b....Ch. 17 - Answer the following questions about A, depicted...Ch. 17 - Answer the following questions about B, depicted...Ch. 17 - Prob. 79PCh. 17 - Prob. 80PCh. 17 - Prob. 81PCh. 17 - Prob. 82PCh. 17 - Prob. 83PCh. 17 - Prob. 84PCh. 17 - Prob. 85PCh. 17 - Prob. 86PCh. 17 - Prob. 87PCh. 17 - Prob. 88PCh. 17 - Prob. 89CPCh. 17 - Lactams can be hydrolyzed with base, just like...
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