World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 16, Problem 35A

(a)

Interpretation Introduction

Interpretation:

The concentration of H+ ion in the solution having pOH= 4.88 should be calculated.

Concept Introduction:

The acidity or alkalinity of a solution is expressed by determining pH of the solution. pH of a solution is defined as negative logarithm of the concentration of H+ ion in the solution. pH is expressed as-

  pH=-log[H+]

  pOH of a solution is defined as negative logarithm of the concentration of hydroxyl ion [OH-] in the solution. pOH is expressed as-

  pOH=-log[OH-]

Both pH and pOH are related to each other by this following equation-

  pH+pOH=pKw

(a)

Expert Solution
Check Mark

Answer to Problem 35A

The concentration of H+ ion is 7.59 × 1010M .

Explanation of Solution

Using the following equation to calculate concentration of H+ ion in the solution,

  pH=-log[H+][H+]=10-pH

The pH of the solution is calculated as:

  pH=14-pOH=14-4.88=9.12

Now, the concentration of hydrogen ion is calculated as:

  [H+]=10-pH=10-9.12=7.59×10-10M

The concentration of H+ ion in the solution is 7.59 × 1010M

(b)

Interpretation Introduction

Interpretation:

The concentration of H+ ion in the solution having pOH= 2.65 should be calculated.

Concept Introduction:

The acidity or alkalinity of a solution is expressed by determining pH of the solution. pH of a solution is defined as negative logarithm of the concentration of H+ ion in the solution. pH is expressed as-

  pH=-log[H+]

  pOH of a solution is defined as negative logarithm of the concentration of hydroxyl ion [OH-] in the solution. pOH is expressed as-

  pOH=-log[OH-]

Both pH and pOH are related to each other by this following equation-

  pH+pOH=pKw

(b)

Expert Solution
Check Mark

Answer to Problem 35A

The concentration of H+ ion is 4.47 × 1012M .

Explanation of Solution

Using the following equation to calculate concentration of H+ ion in the solution,

  pH=-log[H+][H+]=10-pH

The pH of the solution is calculated as:

  pH=14-pOH=14-2.65=11.35

Now, the concentration of hydrogen ion is calculated as:

  [H+]=10-pH=10-11.35=4.47×10-12M

The concentration of H+ ion in the solution is 4.47 × 1012M .

(c)

Interpretation Introduction

Interpretation:

The concentration of H+ ion in the solution having pOH= 11.13 should be calculated.

Concept Introduction:

The acidity or alkalinity of a solution is expressed by determining pH of the solution. pH of a solution is defined as negative logarithm of the concentration of H+ ion in the solution. pH is expressed as-

  pH=-log[H+]

  pOH of a solution is defined as negative logarithm of the concentration of hydroxyl ion [OH-] in the solution. pOH is expressed as-

  pOH=-log[OH-]

Both pH and pOH are related to each other by this following equation-

  pH+pOH=pKw

(c)

Expert Solution
Check Mark

Answer to Problem 35A

The concentration of H+ ion is 1.35 × 103M .

Explanation of Solution

Using the following equation to calculate concentration of H+ ion in the solution,

  pH=-log[H+][H+]=10-pH

The pH of the solution is calculated as:

  pH=14-pOH=14-11.13=2.87

Now, the concentration of hydrogen ion is calculated as:

  [H+]=10-pH=10-2.87=1.35×10-3M

The concentration of H+ ion in the solution is 1.35 × 103M .

(d)

Interpretation Introduction

Interpretation:

The concentration of H+ ion in the solution having pOH= 6.29 should be calculated.

Concept Introduction:

The acidity or alkalinity of a solution is expressed by determining pH of the solution. pH of a solution is defined as negative logarithm of the concentration of H+ ion in the solution. pH is expressed as-

  pH=-log[H+]

  pOH of a solution is defined as negative logarithm of the concentration of hydroxyl ion [OH-] in the solution. pOH is expressed as-

  pOH=-log[OH-]

Both pH and pOH are related to each other by this following equation-

  pH+pOH=pKw

(d)

Expert Solution
Check Mark

Answer to Problem 35A

The concentration of H+ ion is 1.95 × 108M .

Explanation of Solution

Using the following equation to calculate concentration of H+ ion in the solution,

  pH=-log[H+][H+]=10-pH

The pH of the solution is calculated as:

  pH=14-pOH=14-6.29=7.71

Now, the concentration of hydrogen ion is calculated as:

  [H+]=10-pH=10-7.71=1.95×10-8M

The concentration of H+ ion in the solution is 1.95 × 108M .

Chapter 16 Solutions

World of Chemistry, 3rd edition

Ch. 16.2 - Prob. 5RQCh. 16.2 - Prob. 6RQCh. 16.2 - Prob. 7RQCh. 16.3 - Prob. 1RQCh. 16.3 - Prob. 2RQCh. 16.3 - Prob. 3RQCh. 16.3 - Prob. 4RQCh. 16.3 - Prob. 5RQCh. 16.3 - Prob. 6RQCh. 16.3 - Prob. 7RQCh. 16 - Prob. 1ACh. 16 - Prob. 2ACh. 16 - Prob. 3ACh. 16 - Prob. 4ACh. 16 - Prob. 5ACh. 16 - Prob. 6ACh. 16 - Prob. 7ACh. 16 - Prob. 8ACh. 16 - Prob. 9ACh. 16 - Prob. 10ACh. 16 - Prob. 11ACh. 16 - Prob. 12ACh. 16 - Prob. 13ACh. 16 - Prob. 14ACh. 16 - Prob. 15ACh. 16 - Prob. 16ACh. 16 - Prob. 17ACh. 16 - Prob. 18ACh. 16 - Prob. 19ACh. 16 - Prob. 20ACh. 16 - Prob. 21ACh. 16 - Prob. 22ACh. 16 - Prob. 23ACh. 16 - Prob. 24ACh. 16 - Prob. 25ACh. 16 - Prob. 26ACh. 16 - Prob. 27ACh. 16 - Prob. 28ACh. 16 - Prob. 29ACh. 16 - Prob. 30ACh. 16 - Prob. 31ACh. 16 - Prob. 32ACh. 16 - Prob. 33ACh. 16 - Prob. 34ACh. 16 - Prob. 35ACh. 16 - Prob. 36ACh. 16 - Prob. 37ACh. 16 - Prob. 38ACh. 16 - Prob. 39ACh. 16 - Prob. 40ACh. 16 - Prob. 41ACh. 16 - Prob. 42ACh. 16 - Prob. 43ACh. 16 - Prob. 44ACh. 16 - Prob. 45ACh. 16 - Prob. 46ACh. 16 - Prob. 47ACh. 16 - Prob. 48ACh. 16 - Prob. 49ACh. 16 - Prob. 50ACh. 16 - Prob. 51ACh. 16 - Prob. 52ACh. 16 - Prob. 53ACh. 16 - Prob. 54ACh. 16 - Prob. 55ACh. 16 - Prob. 56ACh. 16 - Prob. 57ACh. 16 - Prob. 58ACh. 16 - Prob. 59ACh. 16 - Prob. 60ACh. 16 - Prob. 61ACh. 16 - Prob. 62ACh. 16 - Prob. 63ACh. 16 - Prob. 1STPCh. 16 - Prob. 2STPCh. 16 - Prob. 3STPCh. 16 - Prob. 4STPCh. 16 - Prob. 5STPCh. 16 - Prob. 6STPCh. 16 - Prob. 7STPCh. 16 - Prob. 8STPCh. 16 - Prob. 9STPCh. 16 - Prob. 10STPCh. 16 - Prob. 11STP
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