World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 16, Problem 19A
Interpretation Introduction

Interpretation:Amphoterism of anions mustbe provided.

Concept introduction:A very simple definition of acid is that any substance which furnishes H+ ions when added to H2O can be put into a class of acid. On the counterpart if any substance accepts H+ ions when added to H2O , can be classified as base.

Conjugate acid- base pair contain 2 components, one that accept H+ and other which donates shown as follows: HA(aq)+H2O(l)H3O+(aq)+A(aq)

Where,

  • HA and A is acid-conjugate base pair.
  • H2O and H3O+ is base- conjugate pair.

Expert Solution & Answer
Check Mark

Answer to Problem 19A

Anions such as HCO3 and H2PO4 which consist of hydrogen are amphoteric.

Explanation of Solution

Amphoteric are those which can donate as well as accept H+ ions as per medium whether acidic or basic. Example of such compound are H2O , HCO3 and H2PO4 .

In reaction HCO3(aq)+H+(aq)H2CO3(aq) , HCO3 accepts H+ therefore act as base.

Whereasreaction HCO3(aq)+H2OH3O+(aq)+CO32(aq) , HCO3 donates H+ therefore act as base.

Conclusion

Anions such as HCO3 and H2PO4 which consist of hydrogen are amphoteric.

Chapter 16 Solutions

World of Chemistry, 3rd edition

Ch. 16.2 - Prob. 5RQCh. 16.2 - Prob. 6RQCh. 16.2 - Prob. 7RQCh. 16.3 - Prob. 1RQCh. 16.3 - Prob. 2RQCh. 16.3 - Prob. 3RQCh. 16.3 - Prob. 4RQCh. 16.3 - Prob. 5RQCh. 16.3 - Prob. 6RQCh. 16.3 - Prob. 7RQCh. 16 - Prob. 1ACh. 16 - Prob. 2ACh. 16 - Prob. 3ACh. 16 - Prob. 4ACh. 16 - Prob. 5ACh. 16 - Prob. 6ACh. 16 - Prob. 7ACh. 16 - Prob. 8ACh. 16 - Prob. 9ACh. 16 - Prob. 10ACh. 16 - Prob. 11ACh. 16 - Prob. 12ACh. 16 - Prob. 13ACh. 16 - Prob. 14ACh. 16 - Prob. 15ACh. 16 - Prob. 16ACh. 16 - Prob. 17ACh. 16 - Prob. 18ACh. 16 - Prob. 19ACh. 16 - Prob. 20ACh. 16 - Prob. 21ACh. 16 - Prob. 22ACh. 16 - Prob. 23ACh. 16 - Prob. 24ACh. 16 - Prob. 25ACh. 16 - Prob. 26ACh. 16 - Prob. 27ACh. 16 - Prob. 28ACh. 16 - Prob. 29ACh. 16 - Prob. 30ACh. 16 - Prob. 31ACh. 16 - Prob. 32ACh. 16 - Prob. 33ACh. 16 - Prob. 34ACh. 16 - Prob. 35ACh. 16 - Prob. 36ACh. 16 - Prob. 37ACh. 16 - Prob. 38ACh. 16 - Prob. 39ACh. 16 - Prob. 40ACh. 16 - Prob. 41ACh. 16 - Prob. 42ACh. 16 - Prob. 43ACh. 16 - Prob. 44ACh. 16 - Prob. 45ACh. 16 - Prob. 46ACh. 16 - Prob. 47ACh. 16 - Prob. 48ACh. 16 - Prob. 49ACh. 16 - Prob. 50ACh. 16 - Prob. 51ACh. 16 - Prob. 52ACh. 16 - Prob. 53ACh. 16 - Prob. 54ACh. 16 - Prob. 55ACh. 16 - Prob. 56ACh. 16 - Prob. 57ACh. 16 - Prob. 58ACh. 16 - Prob. 59ACh. 16 - Prob. 60ACh. 16 - Prob. 61ACh. 16 - Prob. 62ACh. 16 - Prob. 63ACh. 16 - Prob. 1STPCh. 16 - Prob. 2STPCh. 16 - Prob. 3STPCh. 16 - Prob. 4STPCh. 16 - Prob. 5STPCh. 16 - Prob. 6STPCh. 16 - Prob. 7STPCh. 16 - Prob. 8STPCh. 16 - Prob. 9STPCh. 16 - Prob. 10STPCh. 16 - Prob. 11STP
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