(a)
Interpretation:
To identify the
Concept introduction:
The synthesis of primary amine is done by using phthalimide and primary alkyl halide in presence of hydroxide base. The important point for this reaction is the phthalimide group has only one hydrogen atom which is attached to nitrogen and can be replaced by alkyl group. Therefore, only one alkyl group can be substitued to the nitrogen atom and so only primary amine will form as the product. The general reaction equation is written as,
(b)
Interpretation: To identify the alkyl halide used for the preparation of following amines by Gabriel synthesis.
Concept introduction: The synthesis of primary amine is done by using phthalimide and primary alkyl halide in presence of hydroxide base. The important point for this reaction is the phthalimide group has only one hydrogen atom which is attached to nitrogen and can be replaced by alkyl group. Therefore, only one alkyl group can be substitued to the nitrogen atom and so only primary amine will form as the product. The general reaction equation is written as,
(c)
Interpretation:
To identify the alkyl halide used for the preparation of following amines by Gabriel synthesis.
Concept introduction:
The synthesis of primary amine is done by using phthalimide and primary alkyl halide in presence of hydroxide base. The important point for this reaction is the phthalimide group has only one hydrogen atom which is attached to nitrogen and can be replaced by alkyl group. Therefore, only one alkyl group can be substitued to the nitrogen atom and so only primary amine will form as the product. The general reaction equation is written as,
(d)
Interpretation:
To identify the alkyl halide used for the preparation of following amines by Gabriel synthesis.
Concept introduction: The synthesis of primary amine is done by using phthalimide and primary alkyl halide in presence of hydroxide base. The important point for this reaction is the phthalimide group has only one hydrogen atom which is attached to nitrogen and can be replaced by alkyl group. Therefore, only one alkyl group can be substitued to the nitrogen atom and so only primary amine will form as the product. The general reaction equation is written as,
Want to see the full answer?
Check out a sample textbook solutionChapter 15 Solutions
Organic Chemistry (8th Edition)
- VI. What ammonium salt is formed when each amine is treated with HCI? Draw the structure of the resulting salt. a. -NH2 b. -CH,NHCH3arrow_forwardFollowing are structural formulas for two more widely used sulfonylurea hypoglycemic agents.Show how each might be synthesized by converting an appropriate amine to a carbamic ester and then treating the carbamate with the sodium salt of a substituted benzenesulfonamide.arrow_forward1. Which are the starting materials used to synthesize the given compound through reductive amination? a. propan-1-amine and acetone b. acetone and dimethylamine c. propanal and dimethylmine d. propan-1-amine and acetaldehyde 2. Arrange the following in increasing order of acidity. I. 2,3-Dichlorobutanoic acid II. 2,2-Dichlorobutanoic acid III. 2-Chlorobutanoic acid IV. Butanoic acid a. Ilarrow_forwardWhat amide(s) will form each of the following amines on treatment with LiAlH4?arrow_forwardWhat alkyl halide is needed to prepare each 1° amine by the Gabriel synthesis?arrow_forwardWhat reagents would you use to convert methyl propanoate to the following compounds? a. isopropyl propanoate b. sodium propanoate c. N-ethylpropanamide d. propanoic acidarrow_forwardWhich of these statements is NOT true about the reaction of amines with a cyclic anhydride like phthalic anhydride? a. Dimethylamine will give a cyclic imide product. b. Aniline will give a cyclic imide product. c. Triethylamine will give a cyclic imide product. d. The reaction undergoes a nucleophilic acyl substitution mechanism.arrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts and the amine side product. 1. NaOH, heat N 1 2. Neutralizing work- uparrow_forwardWhich of the following functional groups will react faster and at lower conditions to a nucleophilic attack? (you can think of a nucleophilic attack by an amine). O a. Carboxylic Acid o b. Nitrile о с. Асyl Нalide d. Esterarrow_forwardDraw the structure of the activated benzene ring and the diazonium ion used in the synthesis of each of the following compounds. a. butter yellow b. methyl orangearrow_forwardTriethylamine is utilized as a base in organic synthesis and can form quaternary ammonium salts when alkylated. The structure of triethylamine in shown below:arrow_forward5. Circle the carbon atom that contains the most acidic C-H bond in this molecule e 6. The tertiary amine and aldehyde below will react to form a. An imine b. An enamine c. A nitrile d. None of the above 7. The secondary amine and aldehyde below will react to form HN, a. An imine b. An enamine c. A nitrile d. None of the abovearrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning