Life: The Science of Biology
11th Edition
ISBN: 9781319010164
Author: David E. Sadava, David M. Hillis, H. Craig Heller, Sally D. Hacker
Publisher: W. H. Freeman
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Chapter 14.4, Problem 3R
Summary Introduction
To review:
The discrepancies that would occur if a gene of 1,440 base pairs codes for a polypeptide chain of 192 amino acids.
Introduction:
The code on deoxyribonucleic acid (DNA) in the form of
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a protein with a molar mass of 3800 g/mol is given. determine the number of nucleotides contained in the gene that encoded this protein, knowing that: 20% of it are introns, the mass of a nucleotide is 300 g/mol and the mass of an amino acid is 110 g/mol
A lilP mutant called lilPXS is isolated that produces a truncated polypeptide of only 6 AA in length. Describe a single basepair DNA change that would lead to this truncated version of the protein. Multiple options are possible（100 words maximum）
In the human genome for the beta chain of haemoglobin (the oxygen-carrying protein in the red blood cells), the first 30 nucleotide in the amino acid coding region is represented by the sequence
3'-TACCACGTGGACTGAGGACTCCTCTTCAGA-5'
Chapter 14 Solutions
Life: The Science of Biology
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- The mass of a gene is 32,400 units. The amount of introns is twice the amount of exons. What is the mass of protein that encodes this gene, if the mass of the amino acid is 110 and the nucleotide is 300 units.arrow_forwardGiven the following Wild Type and Mutated DNA sequences: 1.) Identify where the base pair change occurs ( what letter changed?) 2.) For BOTH sequences, write the mRNA strands, define the codon regions and amino acid sequences. 3.) Describe what kind of mutation has occurred (missense, nonsense, or silent), and what effect this may have on the protein. Wild Type DNA Sequence: 3' - AGGCTCGCCTGT - 5' Mutated DNA Sequence: 3' - AGTCTCGCCTGT - 5'arrow_forwardA portion of the sequence from the DNA coding strand of the chick ovalbumin gene is shown. Determine the partial amino acid sequence of the encoded protein. CTCAGAGTTCACCATGGGCTCCATCGGTGCAGCAAGCATGGAA-(1104 bp)-TTCTTTGGCAGATGTGTTTCCCCTTAAAAAGAA Enter the 3-letter abbreviation for each amino acid in sequence, separated with dashes, and no spaces (example: xxx-xxx-XXX-XXX...) The amino acid sequence is .1104bp..…........arrow_forward
- For the following sequence, what is the Tm? 5'-AGCTACGATCAGGTCA-3'arrow_forwardA lilP mutant called lilPXS is isolated that produces a truncated polypeptide of only 6 AA in length. Describe a single basepair DNA change that would lead to this truncated version of the protein. Multiple options are possible (100 words max.)arrow_forwardA gene contains 30% thymine. What is the percentage of pyrimidines present in this segment? Explain.arrow_forward
- A lilP mutant called lilPXS is isolated that produces a truncated polypeptide of only 6 AA in length. Describe a single basepair DNA change that would lead to this truncated version of the protein. Multiple options are possiblearrow_forwardThe protein encoded by the cystic fibrosis gene is 1480amino acids long, yet the gene spans 250 kb. How is thisdifference possible?arrow_forwardIdentify the FOUR sequence.arrow_forward
- Human Chromosome 22 (48 × 106 nucleotide pairs in length) has about 700 protein-coding genes, which average 19,000 nucleotide pairs in length and contain an average of 5.4 exons, each of which averages 266 nucleotide pairs. What fraction of the average protein-coding gene is converted into mRNA? What fraction of the chromosome do these genes occupy?arrow_forwardHow many binary sequences of length n contain at most five 1 digits? The genetic code specifies an amino acid through a sequence of three nucleotides. Each nucleotide can be of one of the four types T, A, C and G, beingrepetitions allowed. How many amino acids can be encoded in this way?And if there are n types. Comparearrow_forward5'......TACTGCCCATGCCCAGAGAGAAAGCGCAGACGCGTCTAAactgt... 3' a). (10 points). In the above sequences, the open reading frame is indicated by alternating non-underlined and underlined triplets. Please use the codon table to deduce the amino acid sequence for the region shown in the wildtype protein. Wildtype AA sequence for the region around mutation #1: Wildtype AA sequence for the region around mutation #2: b). (10 points). Please make predictions what molecular change mutation #1 and mutation #2 cause. c). (5 points). Which mutation is more likely to abrogate the protein function? Why?arrow_forward
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