Production and Operations Analysis, Seventh Edition
7th Edition
ISBN: 9781478623069
Author: Steven Nahmias, Tava Lennon Olsen
Publisher: Waveland Press, Inc.
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Chapter 12, Problem 63AP
Summary Introduction
Interpretation:
Percentage of cases fall outside the customer’s specifications.
Concept Introduction:
Probability Distribution Function is a likelihood of an event to occur for discrete random variables. Graphically, it shows how likely variables will fall under the probability area.
Exponential distribution is a probabilitydistribution which finds probability of an event to occur between independent constant rate and continous rate.
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7.
An ad agency tracks the complaints, by week received, about the billboards in its city:
Week
No. of Complaints
1
3
2
6
3
4
4
12
5
2
6
9
This exercise contains only parts a, b, and c.
Part 2
a) The type of control chart that is best to monitor this process is
c minus chart ______
.
Part 3
b) Using z =
3,
the control chart limits for this process are (assume that the historical complaints rate is unknown):
UCLc
= ________ complaints per week (round your response to two decimal places).
The upper control limit is: ________
The lower control limit is: _________
The central limit is ___________
Do control charts assist in monitoring quality as conformance or quality as improvement?
Designing an x -Chart Using the Process Standard DeviationThe Sunny Dale Bank monitors the time required to serve customers at the drive-through window because it is an important quality factor in competing with other banks in the city. After analyzing the data gathered in an extensive study of the window operation, bank management determined that the mean time to process a customer at the peak demand period is 5 minutes, with a standard deviation of 1.5 minutes. Management wants to monitor the mean time to process a customer by periodically using a sample size of six customers. Assume that the process variability is in statistical control. Design an x-chart that has a type I error of 5 percent. That is, set the control limits so that there is a 2.5 percent chance a sample result will fall below the LCL and a 2.5 percent chance that a sample result will fall above the UCL. After several weeks of sampling, two successive samples came in at 3.70 and 3.68 minutes, respectively. Is the…
Chapter 12 Solutions
Production and Operations Analysis, Seventh Edition
Ch. 12.1 - Prob. 2PCh. 12.1 - Prob. 3PCh. 12.1 - Prob. 4PCh. 12.1 - Prob. 5PCh. 12.1 - Prob. 6PCh. 12.2 - Prob. 7PCh. 12.2 - Prob. 8PCh. 12.2 - Prob. 9PCh. 12.2 - Prob. 10PCh. 12.2 - Prob. 11P
Ch. 12.2 - Prob. 12PCh. 12.2 - Prob. 13PCh. 12.3 - Prob. 14PCh. 12.3 - Prob. 15PCh. 12.3 - Prob. 16PCh. 12.3 - Prob. 17PCh. 12.4 - Prob. 18PCh. 12.4 - Prob. 19PCh. 12.4 - Prob. 20PCh. 12.4 - Prob. 21PCh. 12.5 - Prob. 22PCh. 12.6 - Prob. 23PCh. 12.6 - Prob. 24PCh. 12.6 - Prob. 25PCh. 12.6 - Prob. 26PCh. 12.6 - Prob. 27PCh. 12.6 - Prob. 28PCh. 12.9 - Prob. 29PCh. 12.9 - Prob. 30PCh. 12.9 - Prob. 31PCh. 12.9 - Prob. 32PCh. 12.9 - Prob. 33PCh. 12.10 - Prob. 34PCh. 12.10 - Prob. 35PCh. 12.10 - Prob. 37PCh. 12.10 - Prob. 38PCh. 12.10 - Prob. 39PCh. 12.10 - Prob. 40PCh. 12.11 - Prob. 41PCh. 12.11 - Prob. 42PCh. 12.11 - Prob. 43PCh. 12.11 - Prob. 44PCh. 12.12 - Prob. 46PCh. 12.12 - Prob. 47PCh. 12.12 - Prob. 48PCh. 12 - Prob. 49APCh. 12 - Prob. 50APCh. 12 - Prob. 51APCh. 12 - Prob. 52APCh. 12 - Prob. 53APCh. 12 - Prob. 54APCh. 12 - Prob. 55APCh. 12 - Prob. 57APCh. 12 - Prob. 58APCh. 12 - Prob. 59APCh. 12 - Prob. 60APCh. 12 - Prob. 61APCh. 12 - Prob. 62APCh. 12 - Prob. 63APCh. 12 - Prob. 64APCh. 12 - Prob. 65APCh. 12 - Prob. 66APCh. 12 - Prob. 67APCh. 12 - Prob. 68APCh. 12 - Prob. 69APCh. 12 - Prob. 70AP
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- 1. An ad agency tracks the complaints, by week received, about the billboards in its city: Week No. of Complaints 1 8 2 4 3 11 4 16 5 8 6 9 This exercise contains only parts a, b, and c. a) The type of control chart that is best to monitor this process is c minus chartc−chart . b) Using z = 3, the control chart limits for this process are (assume that the historical complaints rate is unknown): UCLc =?complaints per week (round your response to two decimal places). LCLc =?complaints per week (round your response to two decimal places).arrow_forwardRefer to Table 56.1-Factors for Computing Control Chart Limits.(3.sigma) for this problem. Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: a) What is the value of x? mm (round your response to two decimal places). b) What is the value of R? R=mm (round your response to two decimal places). c) What are the UCL, and LCL; using 3-sigma? Day 1 2 3 4 5 Upper Control Limit (UCL;)mm (round your response to two decimal places) Lower Control Limit (LCL;)mm (round your response to two decimal places). d) What are the UCL and LCL using 3-sigma? Upper Control Limit (UCLR)-mm (round your response to two decimal places). Lower Control Limit (LCL)-mm (round your response to two decimal places) Mean x (mm) 154.9 151.2 155.6 155.5 154.6 Range R (mm) 4.4 4.8 4.3 5.0 4.7 Nextarrow_forwardAt Isogen Pharmaceuticals, the filling process for its asthma inhaler is set to dispense 140 milliliters (ml) of steroid solution per container. The average range for a sample of 3 containers is 4 ml. use the accompanying table to establish control limits for sample means and ranges for the filling process. x-chart and R-chart Size of Sample (n) Factor for UCL and LCL for x-chart (A2) Factor for LCL for R-Chart (D3) Factor for UCL for R-Chart (D4) 2 1.880 0 3.267 3 1.023 0 2.575 4 0.729 0 2.282 5 0.577 0 2.115 6 0.483 0 2.004 7 0.419 0.076 1.924 8 0.373 0.136 1.864 9 0.337 0.184 1.816 10 0.308 0.223 1.777 The UCLR equals to what ml and the LCLR equals to what ml. (Enter your responses rounded to two decimal places.) The UCLx equals to what ml and the LCLx is what ml. (Enter your responses rounded to two decimal places.)arrow_forward
- A manufacturer of precision machine parts produces round shafts for use in the construction of drill presses. The average diameter of a shaft is .56 inch. Inspection samples contain 6 shafts each. The average range of these samples is .006 inch. Determine the upper and lower x control chart limits.arrow_forwardControl charts for X-bar and R are maintained for the tensile strength of fibers used in composite materials. The specifications are 440+40. After 36 samples of size n=7 are analyzed, we find that: 36 36 X¡ = 12,870 Ri = 1,350 i=1 What are the limits of the X-bar chart? UCL=442.86 and LCL=415.14 UCL=531.43 and LCL=498.17 UCL=415.18 and LCL=389.19 UCL=373.21 and LCL=341.79 UCL=335.89 and LCL=307.61arrow_forwardFactors for Computing Control Chart Limits (3 sigma) Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day Mean x (mm) Range R (mm) 1 156.9 4.2 2 153.2 4.6 3 153.6 4.1 4 155.5 5.0 5 156.6 4.5 Part 4 c) What are the (UCLx) and (LCLx) using 3-sigma? (UCLx) = mm (round your response to two decimal places). (LCLx) = mmarrow_forward
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- A distributor buys Tires from manufacturers. In his store, Phillip Johnson, the supplier quality manager for the distribution company, selects a tire at random which was received in the warehouse the prior day. Small imperfections (minor wears in trade, uneven surfaces, etc) are counted. Recent data show an average of six imperfections (nonconformities) in each sample. Using the formulas for a c chart, calculate the control limits and centerline for this situation. If management wants a process capability of five nonconformities per sample, will this supplier be able to meet that requirement?arrow_forwardAuto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: a) What is the value of X? x= mm (round your response to two decimal places). Day 1 2 3 4 5 Mean x (mm) 158.9 155.2 155.6 157.5 156.6 Range R (mm) 4.2 4.4 4.3 4.8 4.3arrow_forwardExplain the purpose of the following control charts: x-bar, Range, p-chartarrow_forward
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