Chapter 11.7, Problem 2CE

To determine

To Find: The ratio of area of triangles $\Delta ABCand\Delta ADC$ .

Answer to Problem 2CE

  $9:16$

Explanation of Solution

Given:

  

Height of triangles is same i.e. $12$

Base of triangles.

  $\begin{array}{l}\Delta ABC=9\\ \Delta ADC=16\end{array}$

Since both the triangles $\Delta ABCand\Delta ADC$ are similar

Thus

We know that if the two triangles have same height then the ratio of the area is equal to the ratio of their base.

i.e.

  $\begin{array}{l}\Delta ABCand\Delta ADC\\ \frac{ar\left(\Delta ABC\right)}{ar\left(\Delta ADC\right)}=\frac{9}{16}\end{array}$

Hence, $9:16$