Chapter 11.5, Problem 20WE

To determine

To Find: How far will the rider travel during the $4\min$ ride if the wheel rotate once every $20\sec$ ?

Answer to Problem 20WE

  $1584ft$

Explanation of Solution

Given: Diameter of Ferris wheel is $42ft$ , use $\pi =\frac{22}{7}$

Given: $diameter=42$

  $\begin{array}{l}r=\frac{d}{2}\\ r=\frac{42}{2}\\ r=21\end{array}$

Circumference of a circle

  $\begin{array}{l}C=2\pi r\\ C=2\left(\frac{22}{7}\right)\left(21\right)\\ C=132\end{array}$

Converting minute into seconds

  $4\min =4(60)=240\sec$

Now

Wheel rotate once every $20\sec$ .

i.e.

  $\begin{array}{l}20\sec =132\\ 1sec=\frac{132}{20}\\ 240\sec =\frac{132}{20}\times 240=1584ft\end{array}$

Hence, rider will travel $1584ft$ .