Chapter 11.3, Problem 3WE

To determine

To Find: The area of the trapezoid and length of the median.

Answer to Problem 3WE

  $A=6sq.unit$

  $M=3.75unit$

Explanation of Solution

Given: $b_1=3\frac{1}{6},b_2=4\frac{1}{3},h=1\frac{3}{5}$

Given: $b_1=3\frac{1}{6},b_2=4\frac{1}{3},h=1\frac{3}{5}$

Area of Trapezoid.

  $\begin{array}{l}A=\frac{1}{2}h(b_1+b_2)\\ A=\frac{1}{2}\left(1\frac{3}{5}\right)\left(3\frac{1}{6}+4\frac{1}{3}\right)\\ A=\frac{4}{5}\left(\frac{15}{2}\right)\\ A=6sq.unit\end{array}$

Now

Median of the trapezoid.

  $\begin{array}{l}M=\frac{1}{2}(b_1+b_2)\\ M=\frac{1}{2}\left(3\frac{1}{6}+4\frac{1}{3}\right)\\ M=\frac{15}{4}\\ M=3.75unit\end{array}$

Hence, area of the trapezoid is $A=6sq.unit$ and median is $M=3.75unit$.