Chapter 11.2, Problem 26WE

To determine

To Find: The area of triangle $RST$ .

Answer to Problem 26WE

  $A=18sq.unit$

Explanation of Solution

Given: If the area of the parallelogram $PQRS$ is $36$ and $T$ is the point on $PQ$ .

Let

  $\begin{array}{l}base=a\\ height=h\end{array}$

  

Now

Area of parallelogram

  $\begin{array}{l}A=bh\\ 36=bh\end{array}$

Area of triangle $RST$

  $\begin{array}{l}A=\frac{1}{2}bh\\ bh=36\\ A=\frac{1}{2}(36)\\ A=18sq.unit\end{array}$

Hence, $A=18sq.unit$