Chapter 11.2, Problem 14WE

To determine

To Find: The area.

Answer to Problem 14WE

  $A=18\sqrt{3}c{m}^2$

Explanation of Solution

Given: A rhombus with ${120}^{°}$ angle and sides $6cm$ .

Given: sides= $6cm$ .

Angle: ${120}^{°}$

Area of rhombus

  $\begin{array}{l}$ A={(side)}^2\times \sin \theta $A=6\times 6\times \sin {120}^{°}\\ A=36\times \frac{\sqrt{3}}{2}\\ A=18\sqrt{3}c{m}^2\end{array}$

Hence, $A=18\sqrt{3}c{m}^2$